Chapter 11, Problem 18CT

(a)

To determine

To Find: The circumference of the circle.

Answer to Problem 18CT

  $20\pi units$

Explanation of Solution

Given: $marcABC=288,QA=10$

  

Given: $marcABC=288,QA=10$

  $\begin{array}{l}radius(QA)=10\\ C=2\pi r\\ C=2\pi (10)\\ C=20\pi units\end{array}$

(b)

To determine

To Find: The length of arc $AC$.

Answer to Problem 18CT

  ${72}^{°}$

Explanation of Solution

Given: $marcABC=288,QA=10$

  

Given: $marcABC=288,QA=10$

  $\begin{array}{l}m(arcAC)=360-288\\ m(arcAC)={72}^{°}\end{array}$

(c)

To determine

To Find: The area of sector $AQC$.

Answer to Problem 18CT

  $20\pi sq.units$

Explanation of Solution

Given: $marcABC=288,QA=10$

  

Given: $marcABC=288,QA=10$

  $\begin{array}{l}A=\frac{x}{360}\cdot \pi r^2\\ $ A=\frac{72}{360}\cdot \pi {(10)}^2$A=20\pi sq.units\end{array}$