The Practice of Statistics for AP - 4th Edition
The Practice of Statistics for AP - 4th Edition
4th Edition
ISBN: 9781429245593
Author: Starnes, Daren S., Yates, Daniel S., Moore, David S.
Publisher: Macmillan Higher Education
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Chapter 11.2, Problem 48E

(a)

To determine

To clarify: the explanation is meaningless. Then create a right two-way table that displays the experiment outcomes.

(a)

Expert Solution
Check Mark

Answer to Problem 48E

Independent requirement has been not met.

Explanation of Solution

Given:

  The Practice of Statistics for AP - 4th Edition, Chapter 11.2, Problem 48E , additional homework tip  1

In this table, 32 participants from the treatment are not given full details. Group and 23 of the observed experimental group. So, the use of Chi-square makes no sense. The above-mentioned table exam.

The below is the product of the two-way table from the previous experiment:

    Treatment ControlTotal
    After 1 month19120
    After 2 months628
    After 2 months don't get rid of72027
    Total322355

(b)

To determine

Explaining: the explanation why it is not acceptable to use the right two-way table with a chi-square test in that situation.

(b)

Expert Solution
Check Mark

Answer to Problem 48E

Not proven to satisfy the random criterion.

Explanation of Solution

Given:

  The Practice of Statistics for AP - 4th Edition, Chapter 11.2, Problem 48E , additional homework tip  2

Formula used:

  Expectedcount=RawTotal×ColumnTotalTableTotal

Calculation:

Expected count for any cell when H0 is true is

For the expected count

  Expectedcount=RawTotal×ColumnTotalTableTotal

    TreatmentControlTotal
    After 1 month20×3255=11.6420×2355=8.3620
    After 2 months8×3255=4.658×2355=3.358
    After 2 months don't get rid of27×3255=15.7127×2355=11.2927
    Total322355

Since at least 5 are not all expectations. So, in this situation, a chi-square test should not be carried out.

Chapter 11 Solutions

The Practice of Statistics for AP - 4th Edition

Ch. 11.1 - Prob. 3ECh. 11.1 - Prob. 4ECh. 11.1 - Prob. 5ECh. 11.1 - Prob. 6ECh. 11.1 - Prob. 7ECh. 11.1 - Prob. 8ECh. 11.1 - Prob. 9ECh. 11.1 - Prob. 10ECh. 11.1 - Prob. 11ECh. 11.1 - Prob. 12ECh. 11.1 - Prob. 13ECh. 11.1 - Prob. 14ECh. 11.1 - Prob. 15ECh. 11.1 - Prob. 16ECh. 11.1 - Prob. 17ECh. 11.1 - Prob. 18ECh. 11.1 - Prob. 19ECh. 11.1 - Prob. 20ECh. 11.1 - Prob. 21ECh. 11.1 - Prob. 22ECh. 11.1 - Prob. 23ECh. 11.1 - Prob. 24ECh. 11.1 - Prob. 25ECh. 11.1 - Prob. 26ECh. 11.2 - Prob. 1.1CYUCh. 11.2 - Prob. 1.2CYUCh. 11.2 - Prob. 1.3CYUCh. 11.2 - Prob. 2.1CYUCh. 11.2 - Prob. 2.2CYUCh. 11.2 - Prob. 2.3CYUCh. 11.2 - Prob. 3.1CYUCh. 11.2 - Prob. 3.2CYUCh. 11.2 - Prob. 3.3CYUCh. 11.2 - Prob. 4.1CYUCh. 11.2 - Prob. 4.2CYUCh. 11.2 - Prob. 6.1CYUCh. 11.2 - Prob. 27ECh. 11.2 - Prob. 28ECh. 11.2 - Prob. 29ECh. 11.2 - Prob. 30ECh. 11.2 - Prob. 31ECh. 11.2 - Prob. 32ECh. 11.2 - Prob. 33ECh. 11.2 - Prob. 34ECh. 11.2 - Prob. 35ECh. 11.2 - Prob. 36ECh. 11.2 - Prob. 37ECh. 11.2 - Prob. 38ECh. 11.2 - Prob. 39ECh. 11.2 - Prob. 40ECh. 11.2 - Prob. 41ECh. 11.2 - Prob. 42ECh. 11.2 - Prob. 43ECh. 11.2 - Prob. 44ECh. 11.2 - Prob. 45ECh. 11.2 - Prob. 46ECh. 11.2 - Prob. 47ECh. 11.2 - Prob. 48ECh. 11.2 - Prob. 49ECh. 11.2 - Prob. 50ECh. 11.2 - Prob. 51ECh. 11.2 - Prob. 52ECh. 11.2 - Prob. 53ECh. 11.2 - Prob. 54ECh. 11.2 - Prob. 55ECh. 11.2 - Prob. 56ECh. 11.2 - Prob. 57ECh. 11.2 - Prob. 58ECh. 11.2 - Prob. 59ECh. 11.2 - Prob. 60ECh. 11.2 - Prob. 61ECh. 11.2 - Prob. 62ECh. 11.2 - Prob. 63ECh. 11.2 - Prob. 64ECh. 11 - Prob. 1CRECh. 11 - Prob. 2CRECh. 11 - Prob. 3CRECh. 11 - Prob. 4CRECh. 11 - Prob. 5CRECh. 11 - Prob. 6CRECh. 11 - Prob. 1PTCh. 11 - Prob. 2PTCh. 11 - Prob. 3PTCh. 11 - Prob. 4PTCh. 11 - Prob. 5PTCh. 11 - Prob. 6PTCh. 11 - Prob. 7PTCh. 11 - Prob. 8PTCh. 11 - Prob. 9PTCh. 11 - Prob. 10PTCh. 11 - Prob. 11PTCh. 11 - Prob. 12PTCh. 11 - Prob. 13PT
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