Chapter 11.2, Problem 3.3CYU

To determine

To draw: The conclusion and justify it.

Explanation of Solution

Given:

The table is:

Use Facebook	Main Campus	Common wealth
Several times a month or less	55	76
At least once a week	215	157
At least once a day	640	394
Total Facebook users	910	627

The P -value using calculator is 0.000059.

Calculation:

The null and alternative hypotheses are:

  $\begin{array}{l}{H}_0:\left(\begin{array}{l}\text{There is no difference in the distribution of Facebook use between }\\ \text{students at Penn state’s campus and its commonwealth campuses}.\end{array}\right)\\ H_a:\left(\begin{array}{l}\text{There is a difference in the distribution of Facebook use between }\\ \text{students at Penn state’s campus and its commonwealth campuses}.\end{array}\right)\end{array}$

The P -value is less than the significance level, the null hypothesis can be rejected.

At 5% significance level, there is enough evidence to state that there is a difference in the distribution of users in both the schools.