Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 11, Problem 69A
Interpretation Introduction

Interpretation:

The mass of CO2 produces from 100.0 g of ethanol for the given reaction needs to be determined.

Concept introduction:

The mole concept provides the relation between moles, mass and molar mass. The mathematical expression of mole concept can write as:

Mole =MassMolar mass

1 mole of any substance contains 6.022 × 1023 number of particles or atoms or molecules.

Expert Solution & Answer
Check Mark

Answer to Problem 69A

Mass =  95.6 g CO

Explanation of Solution

Given information:

C2H5OH(l) +  O2(g)  CO2(g)  +  H2O(g)

Mass of ethanol = 100.0 g

The given reaction:

C2H5OH(l) +  O2(g)  CO2(g)  +  H2O(g)

Mass of ethanol = 100.0 g

Molar mass of ethanol = 46.0 g/mol

Molar mass of CO2 = 44.0 g/mol

The mole ratio relates the moles of reactant with other reactant and product molecules in the balance chemical equation.

C2H5OH(l) +  O2(g)  CO2(g)  +  H2O(g)

1 mole of CO2 = 1 mole of ethanol

Calculate mass of CO2 with the help of mole ratio:

100.0 g C2H5OH ×1 mole C2H5OH46.0 g C2H5OH×1 mole CO 1 mole C2H5OH  ×44.0 g CO  1 mole CO  = 95.6 g CO

Conclusion

Mole ratio is used to calculate the mass of product.

Chapter 11 Solutions

Chemistry: Matter and Change

Ch. 11.2 - Prob. 11PPCh. 11.2 - Prob. 12PPCh. 11.2 - Prob. 13PPCh. 11.2 - Prob. 14PPCh. 11.2 - Prob. 15PPCh. 11.2 - Prob. 16PPCh. 11.2 - Prob. 17SSCCh. 11.2 - Prob. 18SSCCh. 11.2 - Prob. 19SSCCh. 11.2 - Prob. 20SSCCh. 11.2 - Prob. 21SSCCh. 11.2 - Prob. 22SSCCh. 11.3 - Prob. 23PPCh. 11.3 - Prob. 24PPCh. 11.3 - Prob. 25SSCCh. 11.3 - Prob. 26SSCCh. 11.3 - Prob. 27SSCCh. 11.4 - Prob. 28PPCh. 11.4 - Prob. 29PPCh. 11.4 - Prob. 30PPCh. 11.4 - Prob. 31SSCCh. 11.4 - Prob. 32SSCCh. 11.4 - Prob. 33SSCCh. 11.4 - Prob. 34SSCCh. 11.4 - Prob. 35SSCCh. 11 - Prob. 36ACh. 11 - Prob. 37ACh. 11 - Prob. 38ACh. 11 - Prob. 39ACh. 11 - Prob. 40ACh. 11 - Prob. 41ACh. 11 - Prob. 42ACh. 11 - Prob. 43ACh. 11 - Interpret the following equation in terms of...Ch. 11 - Smelting When tin(IV) oxide is heated with carbon...Ch. 11 - When solid copper is added to nitric acid, copper...Ch. 11 - When hydrochloric acid solution reacts with lead...Ch. 11 - When aluminum is mixed with iron(lll) oxide, iron...Ch. 11 - Solid silicon dioxide, often called silica, reacts...Ch. 11 - Prob. 50ACh. 11 - Prob. 51ACh. 11 - Prob. 52ACh. 11 - Antacids Magnesium hydroxide is an ingredient in...Ch. 11 - Prob. 54ACh. 11 - Prob. 55ACh. 11 - Prob. 56ACh. 11 - Prob. 57ACh. 11 - Prob. 58ACh. 11 - Prob. 59ACh. 11 - Ethanol (C2H5OH) , also known as grain alcohol,...Ch. 11 - Welding If 5.50 mol of calcium carbide (CaC2)...Ch. 11 - Prob. 62ACh. 11 - Prob. 63ACh. 11 - Prob. 64ACh. 11 - Prob. 65ACh. 11 - Prob. 66ACh. 11 - Prob. 67ACh. 11 - Prob. 68ACh. 11 - Prob. 69ACh. 11 - Prob. 70ACh. 11 - Prob. 71ACh. 11 - Prob. 72ACh. 11 - Prob. 73ACh. 11 - Prob. 74ACh. 11 - Prob. 75ACh. 11 - Prob. 76ACh. 11 - Prob. 77ACh. 11 - Prob. 78ACh. 11 - Prob. 79ACh. 11 - Prob. 80ACh. 11 - Prob. 81ACh. 11 - Prob. 82ACh. 11 - Prob. 83ACh. 11 - Prob. 84ACh. 11 - Prob. 85ACh. 11 - Prob. 86ACh. 11 - Prob. 87ACh. 11 - Prob. 88ACh. 11 - Prob. 89ACh. 11 - Prob. 90ACh. 11 - Lead(ll) oxide is obtained by roasting galena,...Ch. 11 - Prob. 92ACh. 11 - Prob. 93ACh. 11 - Prob. 94ACh. 11 - Prob. 95ACh. 11 - Prob. 96ACh. 11 - Prob. 97ACh. 11 - Ammonium sulfide reacts With copper(ll) nitrate in...Ch. 11 - Fertilizer The compound calcium cyanamide (CaNCN)...Ch. 11 - When copper(ll) oxide is heated in the presence Of...Ch. 11 - Air Pollution Nitrogen monoxide, which is present...Ch. 11 - Electrolysis Determine the theoretical and percent...Ch. 11 - Iron reacts with oxygen as Shown....Ch. 11 - Analyze and Conclude In an experiment, you obtain...Ch. 11 - Observe and Infer Determine whether each reaction...Ch. 11 - Design an Experiment Design an experiment that can...Ch. 11 - Apply When a campfire begins to die down and...Ch. 11 - Apply Students conducted a lab to investigate...Ch. 11 - When 9.59 g of a certain vanadium oxide is heated...Ch. 11 - Prob. 110ACh. 11 - Prob. 111ACh. 11 - Prob. 112ACh. 11 - Prob. 113ACh. 11 - Prob. 114ACh. 11 - Prob. 115ACh. 11 - Prob. 116ACh. 11 - Prob. 117ACh. 11 - Prob. 118ACh. 11 - Prob. 119ACh. 11 - Prob. 120ACh. 11 - Prob. 1STPCh. 11 - Prob. 2STPCh. 11 - Prob. 3STPCh. 11 - Prob. 4STPCh. 11 - Prob. 5STPCh. 11 - Prob. 6STPCh. 11 - Prob. 7STPCh. 11 - Prob. 8STPCh. 11 - Prob. 9STPCh. 11 - Prob. 10STPCh. 11 - Prob. 11STPCh. 11 - Prob. 12STPCh. 11 - Prob. 13STPCh. 11 - Prob. 14STPCh. 11 - Prob. 15STPCh. 11 - Prob. 16STPCh. 11 - Prob. 17STP
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
Bonding (Ionic, Covalent & Metallic) - GCSE Chemistry; Author: Science Shorts;https://www.youtube.com/watch?v=p9MA6Od-zBA;License: Standard YouTube License, CC-BY
Stoichiometry - Chemistry for Massive Creatures: Crash Course Chemistry #6; Author: Crash Course;https://www.youtube.com/watch?v=UL1jmJaUkaQ;License: Standard YouTube License, CC-BY