Chapter 11, Problem 111A

a)

Interpretation Introduction

Interpretation : The electronic configuration of Fluorine needs to be determined.

Concept introduction : Electrons are filled in orbitals according to Hund’s rule, Pauli’s exclusive principle and Aufbau’s principle.

Answer to Problem 111A

[He] 2s² 2p⁵

Explanation of Solution

Fluorine has 9 electrons. Thus, the electronic configuration will be:

$1s^{2}2s^{2}2s^5$

Or,

[He] 2s² 2p⁵

b)

Interpretation Introduction

Interpretation:

Electronic configuration of aluminium needs to be written.

Concept introduction : Electrons are filled in orbitals according to Hund’s rule, Pauli’s exclusive principle and Aufbau’s principle.

Answer to Problem 111A

[Ne] 3s² 3p¹

Explanation of Solution

Number of electron in Al is 13.

The electronic configuration can be written as follows:

$1s^2{\text{2s}}^2{\text{ 2p}}^{6}3s^{2}3p^1$

Or,

[Ne] 3s² 3p¹

c)

Interpretation Introduction

Interpretation : Electronic configuration of titanium needs to be determined.

Concept introduction : Electrons are filled in orbitals according to Hund’s rule, Pauli’s exclusive principle and Aufbau’s principle.

Answer to Problem 111A

[Ar] 3d² 4s²

Explanation of Solution

Fluorine has 22 electrons. The electronic configuration can be written as follows:

$1s^2{\text{2s}}^2{\text{ 2p}}^{6}3s^{2}3p^{6}3d^{2}4s^2$

Or,

[Ar] 3d² 4s²

d)

Interpretation Introduction

Interpretation:

Electronic configuration of radon needs to be determined.

Concept introduction : Electrons are filled in orbitals according to Hund’s rule, Pauli’s exclusive principle and Aufbau’s principle.

Answer to Problem 111A

[Xe] 4f¹⁴ 5d¹⁰ 6s²6p⁶

Explanation of Solution

Number of electron in Radon is 86.

The electronic configuration is represented as follows:

[Xe] 4f¹⁴ 5d¹⁰ 6s²6p⁶

Here, electronic configuration of Xe is:

$1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}4p^{6}4d^{10}$