Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 10, Problem 5P
Human late prophase karyotypes have about
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An STR on chromosome 5 is very closely linked to a gene involved in a dominant metabolism disorder (one one copy of the mutation causes the disease). There are four different alleles of the STR (Q, B, S, and L), each with different numbers of GATCTCG repeats. The S allele
has 2 repeats, the B allele has 7 repeats, the Q allele has 10 repeats, and the L allele has 5 repeats.
Part 1
Lane 1 of the gel shown below indicates the locations of PCR products corresponding to all four STR alleles when run together in one lane. DNA was loaded into the wells at the top of the gel.
Move the letter of each allele to its correct position at the left of Lane 1 to indicate where each allele runs on the gel.
0000
Gabriel
Andre
Lane 1
O Maria
Andre Maria Juliana
B L
Part 2
Andre and Maria are the parents in this family; all others shown on the gel are children. Daughter Juliana is born with the metabolism disorder, but daughter Camila does not have the disorder. Assuming no recombination between the STR…
To detect the CAG repeat expansion with a particular gene where 30 repeats in Normal changes to 250 repeats in a certain disease, how can we diagnose the condition.
How To identify Y chromosome microdeletion ( which involves the deletion of AZF locus) using conventional karyotyping? If not then why.
How will you diagnose a chromosomal translocation event?
The fruit fly Drosophila melanogaster has about 2 x 10^8 base pairs of DNA per haploid genome, of which about 75% in nonrepeated DNA. The DNA
is distributed among four pairs of homologous chromosomes, which have a total of about 5,000 visible bands when in polytene forms in the salivary
gland. The number of genes initially estimated from mutational studies was also about 5,000 but recent DNA sequencing studies suggest that the
gene number may be somewhat higher.
a. Why was it tempting to speculate that each band corresponds to a single gene? What does this suggest about the number of different proteins
Drosophila can make? Does that seem like a reasonable number to you?
b. Assuming all the nonrepeated DNA is uniformly distributed in the chromosomes, how much nonrepeated DNA (in base pairs) is there in average
band?
Chapter 10 Solutions
Genetic Analysis: An Integrated Approach (3rd Edition)
Ch. 10 - 10.1 Give descriptions for the following...Ch. 10 - 10.2 The human genome contains contains base...Ch. 10 - In eukaryotic DNA, Where are you most likely to...Ch. 10 - 10.4 Describe the importance of light and dark G...Ch. 10 - Human late prophase karyotypes have about 2000...Ch. 10 - Prob. 6PCh. 10 - From the following list, identify the types...Ch. 10 - 10.8 If the haploid number for a plant species is...Ch. 10 - Mating between a male donkey (2n=64) and a female...Ch. 10 - A researcher interested in studying a human gene...
Ch. 10 - 10.11 In what way does position effect variegation...Ch. 10 - 10.12 A pair of homologous chromosomes in...Ch. 10 - 10.13 An animal heterozygous for a reciprocal...Ch. 10 - Dr. Ara B. Dopsis has an idea he thinks will be a...Ch. 10 - A normal chromosome and its homolog carrying a...Ch. 10 - The accompanying chromosome diagram represents a...Ch. 10 - 10.17 Histone protein isolated from pea plants...Ch. 10 - 10.18 A survey of organisms living deep in the...Ch. 10 - In humans that XX/XO mosaics, the phenotype is...Ch. 10 - 10.20 A plant breeder would like to develop the...Ch. 10 - In Drosophilia, seven partial deletion (1to7)...Ch. 10 - Two experimental varieties of strawberry are...Ch. 10 - 10.23 In the tomato, Solanum esculentum, tall ()...Ch. 10 - A boy with Down syndrome (trisomy 21) has 46...Ch. 10 - Experimental evidence demonstrates that the...Ch. 10 - Prob. 26PCh. 10 - Genomic DNA from the nematode worm...Ch. 10 - 10.28 A small population of deer living on an...Ch. 10 - A eukaryote with a diploid number of 2n=6 carries...Ch. 10 - Prob. 30PCh. 10 - For the following crosses, determine as accurately...Ch. 10 - A healthy couple with a history of three previous...
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- Rice has a chromosome number of 2n = 24. If different euploids and anaeuploids are available in rice, identifythe chromosomal mutation, chromosome configuration, chromosome number, and/or type of gametes in each of the mutations below. Complete the table. Example: for 10B, the answer is "10 II + 2 I"arrow_forwardARVC5 is a disorder characterized by the replacement of healthy heart tissue with fatty fibrous tissue. Recent research has discovered the mutated gene that causes the disorder is on chromosome 3. People who have the mutation have a GCG triplet instead of the normal ACA triplet. The following is a section of a gene on chromosome 3: GGT GCG ACA ATT 1. Complete the following table. AA DNA sense strand DNA antisense strand GGT GCG ACA ATT mRNA tRNA 2. Indicate the change in the amino acid sequence resulting from the mutation in the gene described above., B I 123 ||| 14 E GO LG US X₂ x²arrow_forwardThe dominant condition elliptocytosis causes red blood cells to become misshapen into oval-shaped cells. One of the genes responsible for the abnormal shape encodes the band 4.1 protein that together with ankyrin and other scaffold proteins creates and maintains the spherical concave shape of a normal red blood cell. The gene for band 4.1 protein, EPB41, is found on the p arm of chromosome 1. This is very close to the gene encoding the red blood cell Rhesus (Rh) blood type, either phenotype + (dominant) or - (recessive), with a recombination frequency of 2%. This means that 98% of the time alleles for these two genes are linked and are transmitted together. Diane and Jack are siblings, and both have elliptocytosis and Rh+ blood type. Due to the elliptocytosis, both had emergency splenectomies after having severe anemia. Their younger brother, Devonté, has not yet shown signs of elliptocytosis, but has Rh- blood. André, their dad, also has elliptocytosis and Rh+ blood; while their…arrow_forward
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