Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 10, Problem 52A

(a)

Interpretation Introduction

Interpretation: To determine the number of hydrogen atoms in a given compound.

Concept Introduction: The molecular formula is the representation of the chemical proportion of a molecule by using the total number and symbol of the atoms present in the molecule.

(a)

Expert Solution
Check Mark

Answer to Problem 52A

The number of hydrogen atoms will be 3.

Explanation of Solution

The given compound is AlOH3

The total number of hydrogen atoms in AlOH3= 3

(b)

Interpretation Introduction

Interpretation: To determine the number of hydrogen atoms in a given compound.

Concept Introduction: The molecular formula is the representation of the chemical proportion of a molecule by using the total number and symbol of the atoms present in the molecule.

(b)

Expert Solution
Check Mark

Answer to Problem 52A

The number of hydrogen atoms will be 2.

Explanation of Solution

The given compound is H2C2O4

The total number of a hydrogen atoms in H2C2O4 =2

(c)

Interpretation Introduction

Interpretation: To determine the number of hydrogen atoms in a given compound.

Concept Introduction: The molecular formula is the representation of the chemical proportion of a molecule by using the total number and symbol of the atoms present in the molecule.

(c)

Expert Solution
Check Mark

Answer to Problem 52A

The number of hydrogen atom will be 9.

Explanation of Solution

The given compound is NH42HPO4

The total number of hydrogen atom in NH42HPO4 can be determined as:

Total number of hydrogens = 9 (4×2+1)

(d)

Interpretation Introduction

Interpretation: To determine the number of hydrogen atoms in a given compound.

Concept Introduction: The molecular formula is the representation of the chemical proportion of a molecule by using the total number and symbol of the atoms present in the molecule.

(d)

Expert Solution
Check Mark

Answer to Problem 52A

The number of hydrogen atoms will be 10.

Explanation of Solution

The given compound is C4H10O

The total number of a hydrogen atom in C4H10O = 10

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Chapter 10, Problem 51A
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Chapter 10, Problem 53A

Chapter 10 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 10.1 - Prob. 1SPCh. 10.1 - Prob. 2SPCh. 10.1 - Prob. 3SPCh. 10.1 - Prob. 4SPCh. 10.1 - Prob. 5SPCh. 10.1 - Prob. 6SPCh. 10.1 - Prob. 7SPCh. 10.1 - Prob. 8SPCh. 10.1 - Prob. 9LCCh. 10.1 - Prob. 10LC
Ch. 10.1 - Prob. 11LCCh. 10.1 - Prob. 12LCCh. 10.1 - Prob. 13LCCh. 10.1 - Prob. 14LCCh. 10.1 - Prob. 15LCCh. 10.2 - Prob. 16SPCh. 10.2 - Prob. 17SPCh. 10.2 - Prob. 18SPCh. 10.2 - Prob. 19SPCh. 10.2 - Prob. 20SPCh. 10.2 - Prob. 21SPCh. 10.2 - Prob. 22SPCh. 10.2 - Prob. 23SPCh. 10.2 - Prob. 24LCCh. 10.2 - Prob. 25LCCh. 10.2 - Prob. 26LCCh. 10.2 - Prob. 27LCCh. 10.2 - Prob. 28LCCh. 10.2 - Prob. 29LCCh. 10.2 - Prob. 30LCCh. 10.2 - Prob. 31LCCh. 10.2 - Prob. 32LCCh. 10.3 - Prob. 33SPCh. 10.3 - Prob. 34SPCh. 10.3 - Prob. 35SPCh. 10.3 - Prob. 36SPCh. 10.3 - Prob. 37SPCh. 10.3 - Prob. 38SPCh. 10.3 - Prob. 39SPCh. 10.3 - Prob. 40SPCh. 10.3 - Prob. 41SPCh. 10.3 - Prob. 42SPCh. 10.3 - Prob. 43LCCh. 10.3 - Prob. 44LCCh. 10.3 - Prob. 45LCCh. 10.3 - Prob. 46LCCh. 10.3 - Prob. 47LCCh. 10.3 - Prob. 48LCCh. 10.3 - Prob. 49LCCh. 10 - Prob. 50ACh. 10 - Prob. 51ACh. 10 - Prob. 52ACh. 10 - Prob. 53ACh. 10 - Prob. 54ACh. 10 - Prob. 55ACh. 10 - Prob. 56ACh. 10 - Prob. 57ACh. 10 - Prob. 58ACh. 10 - Prob. 59ACh. 10 - Prob. 60ACh. 10 - Prob. 61ACh. 10 - Prob. 62ACh. 10 - Prob. 63ACh. 10 - Prob. 64ACh. 10 - Prob. 65ACh. 10 - Prob. 66ACh. 10 - Prob. 67ACh. 10 - Prob. 68ACh. 10 - Prob. 69ACh. 10 - Prob. 70ACh. 10 - Prob. 71ACh. 10 - Prob. 72ACh. 10 - Prob. 73ACh. 10 - Prob. 74ACh. 10 - Prob. 75ACh. 10 - Prob. 76ACh. 10 - Prob. 77ACh. 10 - Prob. 78ACh. 10 - Prob. 79ACh. 10 - Prob. 80ACh. 10 - Prob. 81ACh. 10 - Prob. 82ACh. 10 - Prob. 83ACh. 10 - Prob. 84ACh. 10 - Prob. 85ACh. 10 - Prob. 86ACh. 10 - Prob. 87ACh. 10 - Prob. 88ACh. 10 - Prob. 89ACh. 10 - Prob. 90ACh. 10 - Prob. 91ACh. 10 - Prob. 92ACh. 10 - Prob. 93ACh. 10 - Prob. 94ACh. 10 - Prob. 95ACh. 10 - Prob. 96ACh. 10 - Prob. 97ACh. 10 - Prob. 98ACh. 10 - Prob. 99ACh. 10 - Prob. 100ACh. 10 - Prob. 101ACh. 10 - Prob. 102ACh. 10 - Prob. 103ACh. 10 - Prob. 104ACh. 10 - Prob. 105ACh. 10 - Prob. 106ACh. 10 - Prob. 108ACh. 10 - Prob. 109ACh. 10 - Prob. 110ACh. 10 - Prob. 111ACh. 10 - Prob. 112ACh. 10 - Prob. 113ACh. 10 - Prob. 114ACh. 10 - Prob. 115ACh. 10 - Prob. 116ACh. 10 - Prob. 117ACh. 10 - Prob. 118ACh. 10 - Prob. 119ACh. 10 - Prob. 120ACh. 10 - Prob. 121ACh. 10 - Prob. 122ACh. 10 - Prob. 123ACh. 10 - Prob. 124ACh. 10 - Prob. 125ACh. 10 - Prob. 126ACh. 10 - Prob. 127ACh. 10 - Prob. 128ACh. 10 - Prob. 1STPCh. 10 - Prob. 2STPCh. 10 - Prob. 3STPCh. 10 - Prob. 4STPCh. 10 - Prob. 5STPCh. 10 - Prob. 6STPCh. 10 - Prob. 7STPCh. 10 - Prob. 8STPCh. 10 - Prob. 9STPCh. 10 - Prob. 10STPCh. 10 - Prob. 11STPCh. 10 - Prob. 12STPCh. 10 - Prob. 13STPCh. 10 - Prob. 14STP
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