Chapter 10, Problem 117A

(a)

Interpretation Introduction

Interpretation: The complete electron configuration for the fluorine atom needs to be determined.

Concept Introduction: An electron configuration of an atom shows the arrangement of a total number of electrons in the atomic orbitals of an atom. Here, the total number of electrons is equal to the atomic number of an atom.

Explanation of Solution

The atomic number of fluorine is 9. It belongs to the 17^th group thus, the number of valence electrons in fluorine is 7. The complete electron configuration for the fluorine atom will be:

  $1s^{2}2s^{2}2p^5$

(b)

Interpretation Introduction

Interpretation: The complete electron configuration for the lithium atom needs to be determined.

Concept Introduction: An electron configuration of an atom shows the arrangement of the total number of electrons in the atomic orbitals of an atom. Here, the total number of electrons is equal to the atomic number of an atom.

Explanation of Solution

The atomic number of lithium is 3. It belongs to the 1^st group thus, the number of valence electrons in lithium is 1. The complete electron configuration for the lithium atom will be:

  $1s^{2}2s^1$

(c)

Interpretation Introduction

Interpretation: The complete electron configuration for the rubidium atom needs to be determined.

Concept Introduction: An electron configuration of an atom shows the arrangement of the total number of electrons in the atomic orbitals of an atom. Here, the total number of electrons is equal to the atomic number of an atom.

Explanation of Solution

The atomic number of rubidium is 37. It belongs to the 1^st group thus, the number of valence electrons in rubidium is 1. The complete electron configuration for the rubidium atom will be:

  $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{10}4s^{2}4p^{6}5s^1$