(a)
Interpretation: To determine the number of protons, neutrons, and electrons.
Concept Introduction:
(a)
Answer to Problem 116A
- number of protons = 40
- number of electrons = 40
- number of neutrons = 50
Explanation of Solution
The atomic number of zirconium = 40 = number of proton or electrons (known)
Hence, the number of protons = 40
number of electrons = 40
number of neutrons = 50
(b)
Interpretation: To determine the number of protons, neutrons, and electrons.
Concept Introduction: Atomic number of particular atoms is equal to the number of protons or electrons present in an atom.
(b)
Answer to Problem 116A
- number of protons = 46
- number of electrons = 46
- number of neutrons = 62
Explanation of Solution
The atomic number of palladium = 46 = number of proton or electrons (known)
Atomic mass of palladium = 108 (given)
Hence, number of protons = 46
number of electrons = 46
number of neutrons = 62
(c)
Interpretation: To determine the number of protons, neutrons, and electrons.
Concept Introduction: Atomic number of particular atoms is equal to the number of protons or electrons present in an atom.
(c)
Answer to Problem 116A
- number of protons = 35
- number of electrons = 35
- number of neutrons = 46
Explanation of Solution
Atomic number of bromine = 35 = number of proton or electron (known)
Atomic mass of bromine = 81 (given)
Hence, the number of protons = 35
number of electrons = 35
number of neutrons = 46
(d)
Interpretation: To determine the number of protons, neutrons, and electrons.
Concept Introduction: Atomic number of particular atoms is equal to the number of protons or electrons present in an atom.
(d)
Answer to Problem 116A
- number of protons = 51
- number of electrons = 51
- number of neutrons = 72
Explanation of Solution
The atomic number of antimony = 51 = number of proton or electrons (known)
Atomic mass of antimony = 123 (given)
Hence, the number of protons = 51
number of electrons = 51
number of neutrons = 72
Chapter 10 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
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