Chapter 10, Problem 48R

To determine

The wavelength of sound in air.

Answer to Problem 48R

The required wavelength is $\boxed{\lambda =0.77\text{ m}}$ .

Explanation of Solution

Given:

The frequency of sound wave, $f=\text{44}0\text{ Hz}$ and the speed of sound in air is $v=\text{34}0\text{ m}/\text{s}$ .

Formula used:

The expression for wavelength of a note is,

$\lambda =v/f$   ..... (1)

Here, $\lambda$ is the wavelength of the note, v is the velocity of sound and $f$ is the frequency.

Equation (1) is the relation between frequency and wavelength.

Calculation:

Substitute $\text{34}0\text{ m}/\text{s}$ for v and $\text{44}0\text{ Hz}$ in equation (1)

$\lambda =\frac{340}{440}=0.77\text{ m}$

Conclusion:

Hence, the required wavelength is $0.\text{77 m}$ .