Select all that is true about transcription in eukaryotes. 1.Introns get spliced out of pre-mRNA 2.Transcription occurs simultaneously and in the same place as translation 3.General transcription factors assist in transcription 4.Poly A tail and a 5' 7-methyl guanosine cap are added for transcript stability 5.The sigma factor positions the RNA polymerase holoenzyme at t

Select all that is true about transcription in eukaryotes. 1.Introns get spliced out of pre-mRNA 2.Transcription occurs simultaneously and in the same place as translation 3.General transcription factors assist in transcription 4.Poly A tail and a 5' 7-methyl guanosine cap are added for transcript stability 5.The sigma factor positions the RNA polymerase holoenzyme at t

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Description: Select all that is true about transcription in eukaryotes.1.Introns get spliced out of pre-mRNA2.Transcription occurs simultaneously and in the same place as translation3.General transcription factors assist in transcription4.Poly A tail and a 5' 7-m

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter16: Gene Expression

Section: Chapter Questions

Problem 20RQ: A scientist mutates elF-2 to eliminate its GTP hydrolysis capability. How would this mutated form of...

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A scientist mutates elF-2 to eliminate its GTP hydrolysis capability. How would this mutated form of elF-2 alter translation? Initiation factors would not be able to bind to mRNA The large ribosomal subunit would not be able to interact with itiRNA transcripts tRNAi-Met would not scan mRNA transcripts for the start codon elF-2 would not be able to interact with the small ribosomal subunit.
Choose all that apply regarding gene transcription in eukaryotes: Multiple transcription factors are necessary to form the pre-initiation complex (PIC) of RNA Pol II. The 5' cap of mRNA requires the free triphosphate on the nucleotide at the 5' end. Introns must be removed from the initial RNA transcipt. Histone acetylation is a method controlling gene expression. Acetylation creates more positive charges on histones, leading to tighter binding of the proteins to DNA. Exons are removed from mRNA by the spliceosome. RNA polymerase II must completely finish an mRNA transcript before processing can begin. RNA polymerase I catalyzes the synthesis of the majority of ribosomal RNA. The hormone 173-estradiol binds to a G-protein coupled receptor to control gene transcription.
6. Indicate whether each of the following events occurs when tryptophan is high or when tryptophan is low by placing a check in each of the appropriate blanks. Share your reasoning. Tryptophan Tryp high Event Ribosome does not stall at Trp codons Region 2 of the leader pairs with region 3 Ribosome covers part of region 2 of leader Transcription is terminated before structural genes are transcribed
2. Consider the pre-mRNA molecule shown below. Re-order the events listed, in the sequence they would occur during pre-mRNA processing in eukaryotes. Pre-MRNA Exon 1 Intron Exon 2 Pre-MRNA processing MRNA Exon1 Exon 2 AAAAA 3 Export to cytoplasm Translation Recognition and binding the 3' AAUAAA sequence by specific proteins Attachment of snRNP U1 to the 5' splice site Formation of a bond between the guanine in the 5' splice site and the adenine of the branch point Binding of the snRNP U4, U5 and U6 complex to the spliceosome Addition of the 5' cap Release of the intron as a lariat structure and splicing of exon 1 and 2 Addition of the poly(A) tail Binding of snRNP U2 to the branch point Cleavage at the poly (A) site
A bacterial species has a hypothetical sigma promoter that has the following sequence: TTGGCA - 18 bases - TATAAT What change in the level of transcription would there be if the sequence was mutated to: TTCGCA -18 bases -TATAAT 1.The mutation would move the promoter away from consensus and reduce the level of transcription 2.No change the consensus TATAAT sequence in the same. 3.The mutation would bind the promoter to the consensus and produce normal levels of transcription 4.The mutation would inhibit the promoter thereby inhibiting transcription
1. What is a consensus sequence? What are the components of RNA polymerase and what are their functions? 2. Describe the steps involved with transcription initiation.? Describe the steps involved with transcription elongation. 3. Describe the steps involved with transcription termination. A consensus sequence is a sequence of DNA,RNA, or protein that has aligned sequence.
1. Shown below is the diagram of a eukaryotic gene that encodes a protein. The promoter and transcription start sites are indicated on the map. The numbers shown correlate with nucleotide base position along the DNA sequence. Transcriptional Transcription start site occurs at base position 1 terminator 5100 Promoter 5' Exon 1 Intron 1 Exon 2 Intron 2 Exon 3 3' 100 Positions 1100 2000 3000 4000 200-202 Start codon positions 4801-4803 Stop codon а. Where in the above sequence where RNA polymerase will bind? b. How long (in bases) will the primary mRNA transcript of this gene be? How long (in başes) is the processed mRNA transcript? С.
Consider this list (below) of steps involved in transcription. These steps are out of order. TRANSCRIPTION: 1. mRNA travels through a nuclear pore and enters the cytoplasm 2. the mRNA polymerase attaches at the start of a specific gene 3. RNA polymerase reads the gene surface4. a transcription factor bonds to a promoter site5. DNA molecule is unwound 6. a complimentary mRNA is produced What is the correct order of this transcription?
(1) Give 3 differences between DNA and RNA (2) Give 2 similarities and 2 differences between transcription and replication (3) A DNA strand is 5' TAC ACG GTC TAA3' Write the RNA strand that could be made from the DNA strand. Indicate the 5' and 3' ends For each of the following, say whether they are DNA or protein Enhancer Transcription Factor Promoter RNA polymerase
A bacterial species has a hypothetical sigma promoter that has the following sequence: TTGGCA - 18 bases - TATAAT What change in the level of transcription would there be if the sequence was mutated to: TTCGCA -18 bases -TATAAT Group of answer choices 1.The mutation would inhibit the promoter thereby inhibiting transcription 2.No change the consensus TATAAT sequence in the same. 3.The mutation would move the promoter away from consensus and reduce the level of transcription 4.The mutation would bind the promoter to the consensus and produce normal levels of transcription
Synthesize a Protein 5. Below is a region of a gene. Transcribe the gene into a pre-mRNA strand. DNA MRNA G C C G T A 6. What is the name of the enzyme which catalyzes this reaction? 7. What three things must then happen to the pre-MRNA you just synthesized before it is allowed to exit the nucleus? 8. Now that you have mature mRNA and it has exited the nucleus and entered the cytosol, it is time to transcribe the mRNA. You may use the abbreviations for the amino acids found in Figure 15.8 of your textbook DNA C A G C A C C T. G A G C C A MRNA Peptide chain
14. The TATA box: O acts to position RNA polymerase II for transcription initiation. O serves as a promoter sequence for genes transcribed by RNA polymerase III. O is present in all eukaryotic genes. is located approximately 100 base pairs upstream of the start site for mRNAs.