7. Instead of one big square it is much easier to make two small Punnett squares, one for each gene. In the space at the bottom of page, draw the two squares (from 4d and 5b on previous page). Indicate the phenotypic ratios for each square and then multiply to get the combined probabilities. For example, the probability of having both diseases requires multiplying the probability of each event. a. Is the inheritance of an "A" or "a" allele dependent on (or affected by) the inheritance of a "B" or b" allele? Why or why not? (hint: Which of Mendel's Laws is involved?) h What is the chance that their child will be phenotypically normal (for both genes)?

7. Instead of one big square it is much easier to make two small Punnett squares, one for each gene. In the space at the bottom of page, draw the two squares (from 4d and 5b on previous page). Indicate the phenotypic ratios for each square and then multiply to get the combined probabilities. For example, the probability of having both diseases requires multiplying the probability of each event. a. Is the inheritance of an "A" or "a" allele dependent on (or affected by) the inheritance of a "B" or b" allele? Why or why not? (hint: Which of Mendel's Laws is involved?) h What is the chance that their child will be phenotypically normal (for both genes)?

Name: 7. Instead of one big square it is much easier to make two small Punn
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: 7. Instead of one big square it is much easier to make two small Punnett squares, one for eachgene. In the space at the bottom of page, draw the two squares (from 4d and 5b onprevious page). Indicate the phenotypic ratios for each square and then mu

Biology: The Unity and Diversity of Life (MindTap Course List)

14th Edition

ISBN:9781305073951

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter13: Observing Patterns In Inherited Traits

Section: Chapter Questions

Problem 11GP: A single allele gives rise to the Hbs form of hemoglobin. Individuals who are homozygous for the...

See similar textbooks

Similar questions

97. This family is (picture above) affected with blindness. Individual (IV.1) is clinically unaffected. What is the chance that he is homozygous for the normal allele? A-½ B-% C- almost 0 D-1/3 E- almost 100% ANS: IV TO O 560-556
While sitting at home during Movement Control Order (MCO) because of pandemic covid19, observe two different traits of a couple in your family (eg. your mom & dad or your sister & her husband or your brother & his wife, etc). Draw a genetic cross that involves cross of the parents with the chosen 2 pairs of their contracting traits. Imagine that the cross obeys the Mendelian Laws, show the cross and gametes production for each generation (P, F1 and F2). By Using a Punnet square as symbolic representation of the results for the cross, determine the phenotypes, genotypes, phenotypic ratio and genotypic ratio of F2 generation in the family.
1. Hemophilia is due to a sex-linked gene. It is recessive and found on the X chromosome. A woman who is a carrier for hemophilia marries a normal man. What will be the possible phenotypes of their children? Use a punnet square. 2. A phenotypically normal man, who has a hemophiliac brother, marries a normal woman, who is not a carrier. What is the probability that any of their children will be hemophiliac? Use a punnet square. 3. Color-blindness is an X-linked, recessive trait. If a normal-sighted woman, whose father was color-blind, marries a colorblind man, what is the probability that they will have a son who is color-blind? Use a punnet square. 4. A man and woman, both of normal vision, have: 1) a color-blind son (#1) who has a daughter of normal vision 2) a daughter (#1) of normal vision who has one color-blind son and one normal vision son 3) another daughter (#2) of normal vision who has five sons, all with normal vision What are the probable genotypes of the…
5.) A man and a woman living in a tropical area where malaria is prevalent and health care is not accessible have seven children during their lifetime. The genotypes of their children are: ss, Ss, SS, ss, Ss, Ss, and SS. What must the genotypes of both parents be? Your answer should include a Punnett square to illustrate your work, and list all the genotypes and phenotypes.
An individual has the following genotype. Gene loci (A) and (B) are 15 m.u. apart. What are the correct frequencies of some of the gametes that car be made by this individual? Bl a O A. Ab = 7.5%; AB = 42.5% B. ab = 25%; aB = 50% O C. AB = 7.5%; aB = 42.5% O D. aB = 15%; Ab = F0% E. aB = 70%; Ab = 15% Reset Selection OMark for Review What's This?
Background information for problem #5 In humans there is a gene that controls formation of hemoglobin (the protein in red blood cells {RBC's} that is responsible for carrying oxygen to the tissues of the body). The normal allele of this gene codes for normal hemoglobin. However, there is another allele for this gene that contains a mutation in the DNA and the resulting hemoglobin protein is defective. An RBC with this defective hemoglobin will, under stress, crystallize within the cell and cause a characteristic sickle shape. While the letters S and s are often used to represent these alleles, in reality neither is dominant to the other (codominant). Someone who is SS makes all normal hemoglobin, someone who is ss makes all abnormal hemoglobin (someone who has sickle-cell anemia), and someone who is Ss essentially has two sets of instructions (and so makes some of each kind of hemoglobin; often referred to as sickle-cell trait). Because the RBC's of a person who is ss contain all…
1. What is the probability of producing a child with Patau syndrome and show your solution. 2. What is the probability of producing a child with Edward syndrome and show your solution.
2. Given: GGWw X ggww Yellow, Round Green Wrinkled Problem: Determine the F2 Genotype and Phenotype
y 301 Amelogenesis imperfecta is X-linked dominant. Affected XY individuals have extremely thin enamel on the teeth while XX carriers have grooved teeth from uneven deposition of enamel. If an unaffected XY individual were to produce children with a XX carrier partner, a. what would be the expected chance of a XY child being affected with the disease? b. what would be the expected chance of a XY child being affected with the disease?
5. A woman with type AB blood marries a man with type homozygous type B blood. What are the phenotype and genotype ratios of the offspring? 6. Hemophilia is a sex linked recessive trait. If a carrier woman marries a normal man. The couple gives birth to a boy. What are the chances that this child will have hemophilia? Make sure use XX or XY here) 7. The height of a certain plant is a result of polygenic inheritance involving two pairs of genes. Draw a Punnett square to show the result of a cross between a tall (AABB) plant and a short (aabbi. What is the phenotype ratio? 8. What is a mutation? 9. What is sickle cell anemia? 10. What is hemophilia? 11. What is a pedigree? 12. Draw a pedigree to represent the following. Shaded symbols should represent individuals with hemophilia: A man with hemophilia marries a normal woman. They have 3 children, two normal boys and a girl who is a carrier. The girl marries a normal man and they have two boys and two girls. One of the girls is a carrier…
1. If the allelic composition of a gene is Aa, the genotype is said to be (homozygous, heterozygous). What is the probability of having "a" allele in gametes? 2. For a genotype of AaBb, what are the possible allele compositions in gametes? 3. What are the possible genotypes and phenotypes ("A" phenotype or "a" phenotype) in the offspring of a monohybrid cross Aa x Aa? 4. If the organism display a dominant phenotype for a trait ("A" phenotype), how does one determine if the genotype is homozygous or heterozygous? Please use the Punnett square to explain. 5. How many possible genotypes are there in the offspring of a dihybrid cross AaBb x AaBb? What are the possible phenotypes for such a cross? What is the phenotypic ratio for AB : Ab : aB : ab? D Focus 72°F DEA F4 PrtScr Insert Hor F5 F6 F7 F8 F9 F10 F11 F12 24 & 3. 8 E R T Y U
1 . 3 Below are the results of some blood tests and you need to compare the child's blood type to the parent's blood type and confirm paternity. If there is no way that parents with the indicated blood types could give rise to a child with the child's blood type write 'No'. If it is possible write 'Yes' and include the parent's genotypes. Child Mom and Dad Possible? If Yes Ogenotypes AB and B O. A and B AB and A АВ A and O A and B 2.