Living by Chemistry
Living by Chemistry
2nd Edition
ISBN: 9781464142314
Author: Angelica M. Stacy
Publisher: W. H. Freeman
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter U5.99, Problem 6E

a.

Interpretation Introduction

Interpretation: The amount of energy required to melt 56 g of ice needs to be calculated.

Concept introduction: The energy absorbed or released during a phase change under constant temperature is said to be latent heat. The heat energy required, Q for a specific phase change for an object of mass, m is given by the formula:

  Q = Lm - (1)

Where L represents latent heat.

a.

Expert Solution
Check Mark

Answer to Problem 6E

The amount of energy required to melt 56 g of ice is 18.704 kJ .

Explanation of Solution

The amount of energy required to melt 56 g of ice into water at constant temperature is calculated using equation (1) as:

  Q = Lfm

Where represents energy of fusion, Lf represents latent heat of fusion and m is mass of the ice.

The value of Lf is 334 kJ/kg and the value of m is 56 g .

Converting mass from g to kg as:

  56 g×103 kg1 g = 0.056 kg

Substituting the values as:

  Q = 334 kJ/kg×0.056 kgQ = 18.704 kJ

Hence, the amount of energy required to melt 56 g of ice is 18.704 kJ .

b.

Interpretation Introduction

Interpretation: The amount of energy required to melt 56 mol of ice needs to be calculated.

Concept introduction: The energy absorbed or released during a phase change under constant temperature is said to be latent heat. The heat energy required, Q for a specific phase change for an object of mass, m is given by the formula:

  Q = Lm - (1)

Where L represents latent heat.

b.

Expert Solution
Check Mark

Answer to Problem 6E

The amount of energy required to melt 56 mol of ice is 336.7 kJ .

Explanation of Solution

The amount of energy required to melt 56 mol of ice into water at constant temperature is calculated using equation (1) as:

  Q = Lfm

Where represents energy of fusion, Lf represents latent heat of fusion and m is mass of the ice.

The value of Lf is 334 kJ/kg and the value of m for 56 mol of ice is determined as follows:

  number of moles = given mass Molar mass

Since, molar mass of ice is 18 g/mol so:

  56 moles = mass 18 g/molmass = 56 moles×18 g/molmass = 1008 gmass = 1008 g×103 kg1 g = 1.008 kg

Substituting the values as:

  Q = 334 kJ/kg×1.008 kgQ = 336.7 kJ

Hence, the amount of energy required to melt 56 mol of ice is 336.7 kJ .

Chapter U5 Solutions

Living by Chemistry

Ch. U5.95 - Prob. 3ECh. U5.95 - Prob. 4ECh. U5.95 - Prob. 5ECh. U5.96 - Prob. 1TAICh. U5.96 - Prob. 1ECh. U5.96 - Prob. 2ECh. U5.96 - Prob. 3ECh. U5.96 - Prob. 4ECh. U5.96 - Prob. 5ECh. U5.96 - Prob. 6ECh. U5.96 - Prob. 7ECh. U5.96 - Prob. 8ECh. U5.96 - Prob. 9ECh. U5.96 - Prob. 10ECh. U5.96 - Prob. 11ECh. U5.97 - Prob. 1TAICh. U5.97 - Prob. 1ECh. U5.97 - Prob. 2ECh. U5.97 - Prob. 3ECh. U5.97 - Prob. 4ECh. U5.97 - Prob. 5ECh. U5.97 - Prob. 6ECh. U5.97 - Prob. 7ECh. U5.98 - Prob. 1TAICh. U5.98 - Prob. 1ECh. U5.98 - Prob. 2ECh. U5.98 - Prob. 3ECh. U5.98 - Prob. 4ECh. U5.98 - Prob. 5ECh. U5.98 - Prob. 6ECh. U5.98 - Prob. 7ECh. U5.98 - Prob. 8ECh. U5.98 - Prob. 9ECh. U5.98 - Prob. 10ECh. U5.99 - Prob. 1TAICh. U5.99 - Prob. 1ECh. U5.99 - Prob. 2ECh. U5.99 - Prob. 3ECh. U5.99 - Prob. 4ECh. U5.99 - Prob. 5ECh. U5.99 - Prob. 6ECh. U5.99 - Prob. 7ECh. U5.99 - Prob. 8ECh. U5.99 - Prob. 9ECh. U5.100 - Prob. 1TAICh. U5.100 - Prob. 1ECh. U5.100 - Prob. 2ECh. U5.100 - Prob. 3ECh. U5.100 - Prob. 4ECh. U5.100 - Prob. 5ECh. U5.101 - Prob. 1TAICh. U5.101 - Prob. 1ECh. U5.101 - Prob. 2ECh. U5.101 - Prob. 3ECh. U5.101 - Prob. 4ECh. U5.101 - Prob. 6ECh. U5.102 - Prob. 1TAICh. U5.102 - Prob. 1ECh. U5.102 - Prob. 2ECh. U5.102 - Prob. 3ECh. U5.102 - Prob. 4ECh. U5.102 - Prob. 5ECh. U5.102 - Prob. 6ECh. U5.102 - Prob. 8ECh. U5.103 - Prob. 1TAICh. U5.103 - Prob. 1ECh. U5.103 - Prob. 2ECh. U5.103 - Prob. 3ECh. U5.103 - Prob. 4ECh. U5.103 - Prob. 5ECh. U5.103 - Prob. 6ECh. U5.104 - Prob. 1TAICh. U5.104 - Prob. 1ECh. U5.104 - Prob. 2ECh. U5.104 - Prob. 3ECh. U5.104 - Prob. 4ECh. U5.104 - Prob. 5ECh. U5.104 - Prob. 6ECh. U5.104 - Prob. 7ECh. U5.104 - Prob. 8ECh. U5.104 - Prob. 9ECh. U5.105 - Prob. 1TAICh. U5.105 - Prob. 1ECh. U5.105 - Prob. 2ECh. U5.105 - Prob. 3ECh. U5.105 - Prob. 4ECh. U5.105 - Prob. 5ECh. U5.106 - Prob. 1TAICh. U5.106 - Prob. 1ECh. U5.106 - Prob. 2ECh. U5.106 - Prob. 3ECh. U5.106 - Prob. 4ECh. U5.106 - Prob. 5ECh. U5.106 - Prob. 6ECh. U5.106 - Prob. 7ECh. U5.106 - Prob. 8ECh. U5.106 - Prob. 9ECh. U5.106 - Prob. 11ECh. U5.107 - Prob. 1TAICh. U5.107 - Prob. 1ECh. U5.107 - Prob. 2ECh. U5.107 - Prob. 3ECh. U5.107 - Prob. 4ECh. U5.108 - Prob. 1TAICh. U5.108 - Prob. 1ECh. U5.108 - Prob. 2ECh. U5.108 - Prob. 3ECh. U5.108 - Prob. 4ECh. U5.108 - Prob. 5ECh. U5.109 - Prob. 1TAICh. U5.109 - Prob. 1ECh. U5.109 - Prob. 2ECh. U5.109 - Prob. 3ECh. U5.109 - Prob. 4ECh. U5.109 - Prob. 5ECh. U5.109 - Prob. 6ECh. U5.109 - Prob. 7ECh. U5.109 - Prob. 8ECh. U5.110 - Prob. 1TAICh. U5.110 - Prob. 1ECh. U5.110 - Prob. 2ECh. U5.110 - Prob. 3ECh. U5.110 - Prob. 4ECh. U5.110 - Prob. 5ECh. U5.110 - Prob. 6ECh. U5.110 - Prob. 7ECh. U5.111 - Prob. 1TAICh. U5.111 - Prob. 1ECh. U5.111 - Prob. 2ECh. U5.111 - Prob. 3ECh. U5.111 - Prob. 4ECh. U5.111 - Prob. 5ECh. U5.111 - Prob. 6ECh. U5.111 - Prob. 7ECh. U5.111 - Prob. 8ECh. U5.111 - Prob. 9ECh. U5.112 - Prob. 1TAICh. U5.112 - Prob. 1ECh. U5.112 - Prob. 2ECh. U5.112 - Prob. 3ECh. U5.112 - Prob. 4ECh. U5.112 - Prob. 5ECh. U5.112 - Prob. 6ECh. U5.112 - Prob. 7ECh. U5.113 - Prob. 1TAICh. U5.113 - Prob. 1ECh. U5.113 - Prob. 2ECh. U5.113 - Prob. 3ECh. U5.113 - Prob. 4ECh. U5.113 - Prob. 5ECh. U5.113 - Prob. 6ECh. U5.113 - Prob. 7ECh. U5.113 - Prob. 8ECh. U5.114 - Prob. 1TAICh. U5.114 - Prob. 1ECh. U5.114 - Prob. 2ECh. U5.114 - Prob. 3ECh. U5.114 - Prob. 4ECh. U5.114 - Prob. 5ECh. U5.114 - Prob. 6ECh. U5.115 - Prob. 1TAICh. U5.115 - Prob. 1ECh. U5.115 - Prob. 2ECh. U5.115 - Prob. 3ECh. U5.115 - Prob. 4ECh. U5.115 - Prob. 5ECh. U5.115 - Prob. 6ECh. U5.115 - Prob. 7ECh. U5.116 - Prob. 1TAICh. U5.116 - Prob. 1ECh. U5.116 - Prob. 2ECh. U5.116 - Prob. 3ECh. U5.116 - Prob. 4ECh. U5.116 - Prob. 5ECh. U5.116 - Prob. 6ECh. U5.116 - Prob. 7ECh. U5.116 - Prob. 8ECh. U5 - Prob. C18.1RECh. U5 - Prob. C18.2RECh. U5 - Prob. C18.3RECh. U5 - Prob. C18.4RECh. U5 - Prob. C18.5RECh. U5 - Prob. C18.6RECh. U5 - Prob. C18.7RECh. U5 - Prob. C18.8RECh. U5 - Prob. C19.1RECh. U5 - Prob. C19.2RECh. U5 - Prob. C19.3RECh. U5 - Prob. C19.4RECh. U5 - Prob. C20.1RECh. U5 - Prob. C20.2RECh. U5 - Prob. C20.3RECh. U5 - Prob. C20.4RECh. U5 - Prob. C20.6RECh. U5 - Prob. C21.1RECh. U5 - Prob. C21.2RECh. U5 - Prob. C21.3RECh. U5 - Prob. C21.4RECh. U5 - Prob. C21.5RECh. U5 - Prob. 1RECh. U5 - Prob. 2RECh. U5 - Prob. 3RECh. U5 - Prob. 4RECh. U5 - Prob. 5RECh. U5 - Prob. 6RECh. U5 - Prob. 7RECh. U5 - Prob. 8RECh. U5 - Prob. 9RECh. U5 - Prob. 10RECh. U5 - Prob. 11RECh. U5 - Prob. 12RECh. U5 - Prob. 13RECh. U5 - Prob. 14RECh. U5 - Prob. 15RECh. U5 - Prob. 16RECh. U5 - Prob. 17RECh. U5 - Prob. 1STPCh. U5 - Prob. 2STPCh. U5 - Prob. 3STPCh. U5 - Prob. 4STPCh. U5 - Prob. 5STPCh. U5 - Prob. 6STPCh. U5 - Prob. 7STPCh. U5 - Prob. 8STPCh. U5 - Prob. 9STPCh. U5 - Prob. 10STPCh. U5 - Prob. 11STPCh. U5 - Prob. 12STPCh. U5 - Prob. 13STPCh. U5 - Prob. 14STPCh. U5 - Prob. 15STPCh. U5 - Prob. 16STPCh. U5 - Prob. 17STPCh. U5 - Prob. 18STPCh. U5 - Prob. 19STPCh. U5 - Prob. 20STPCh. U5 - Prob. 21STPCh. U5 - Prob. 22STP

Additional Science Textbook Solutions

Find more solutions based on key concepts
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
Types of Matter: Elements, Compounds and Mixtures; Author: Professor Dave Explains;https://www.youtube.com/watch?v=dggHWvFJ8Xs;License: Standard YouTube License, CC-BY