Chapter U5, Problem 7RE

Interpretation Introduction

Interpretation:

Aluminum metal or liquid water which take more or less energy to raise the temperature needs to be identified.

Concept introduction:

The amount heat transferred due to change in temperature of a substance can be calculated as follows:

$\text{q = mCΔT}$

Here,

q = energy

m = mass

C = specific heat

$\text{ΔT}$ = change in temperature

Answer to Problem 7RE

Liquid water requires more temperature than aluminum metal.

Explanation of Solution

Given that the mass and temperature change of aluminum metal and liquid water is same. The amount of thermal energy is depending upon the specific heat. Since specific heat of water is greater than the specific heat of aluminum metal.

The specific heat of water is $4.18{\text{ J/g }}^{\text{o}}\text{C}$

The specific heat of aluminium is $0.902{\text{ J/g }}^{\text{o}}\text{C}$

Thus, the thermal energy of water is greater than the thermal energy of aluminum metal.