Chapter U4.22, Problem 6E

(a)

Interpretation Introduction

Interpretation:

The concentration of an acid and the pH of the solution should be predicted.

Concept Introduction:

The full form of pH is the potential of pH. In other words, it explains the strength of the hydrogen ion in a solution. It is given by the formula,

  $\text{pH}=-\log \left[{\text{H}}^{+}\right]$

Answer to Problem 6E

The concentration of an acid and pH of the solution is 1.7 M and -0.23 respectively.

Explanation of Solution

Given information:

• 0.95 M NaOH
• 46 mL NaOH
• 25 mL of acid

The concentration of an acid is calculated as follows:

  $\begin{array}{c}{\text{C}}_{\text{1}}{\text{V}}_{\text{1}}\left(\text{NaOH}\right)={\text{C}}_{\text{2}}{\text{V}}_{\text{2}}\left(\text{acid}\right)\end{array}$

  $\begin{array}{c}\text{0}\text{.95}\text{M}\left(\text{46}\text{mL}\right)={\text{C}}_{\text{2}}\left(25\text{mL}\right)\end{array}$

        $\begin{array}{c}{\text{C}}_{\text{2}}=\frac{\text{0}\text{.95}\text{M}\left(\text{46}\text{mL}\right)}{25\text{mL}}\end{array}$

        $\begin{array}{c}{\text{C}}_{\text{2}}=1.7\text{M}\end{array}$

The pH of the solution is calculated as follows:

  $\begin{array}{c}\text{pH}=-\log \left[{\text{H}}^{+}\right]\end{array}$

    $\begin{array}{c}=-\log \left[1.7\right]\end{array}$

    $\begin{array}{c}=-0.23\end{array}$

Therefore, the concentration of an acid and pH of the solution is 1.7 M and -0.23 respectively.

(b)

Interpretation Introduction

Interpretation:

The concentration of an acid and the pH of the solution should be predicted.

Concept Introduction:

The full form of pH is the potential of pH. In other words, it explains the strength of the hydrogen ion in a solution. It is given by the formula,

  $\text{pH}=-\log \left[{\text{H}}^{+}\right]$

Answer to Problem 6E

The concentration of an acid and pH of the solution is 1.6 M and -0.20 respectively.

Explanation of Solution

Given information:

• 0.95 M NaOH
• 17 mL NaOH
• 10 mL of acid

The concentration of an acid is calculated as follows:

  $\begin{array}{c}{\text{C}}_{\text{1}}{\text{V}}_{\text{1}}\left(\text{NaOH}\right)={\text{C}}_{\text{2}}{\text{V}}_{\text{2}}\left(\text{acid}\right)\end{array}$

   $\begin{array}{c}\text{0}\text{.95}\text{M}\left(17\text{mL}\right)={\text{C}}_{\text{2}}\left(10\text{mL}\right)\end{array}$

        $\begin{array}{c}{\text{C}}_{\text{2}}=\frac{\text{0}\text{.95}\text{M}\left(17\text{mL}\right)}{10\text{mL}}\end{array}$

        $\begin{array}{c}{\text{C}}_{\text{2}}=1.6\text{M}\end{array}$

The pH of the solution is calculated as follows:

   $\begin{array}{c}\text{pH}=-\log \left[{\text{H}}^{+}\right]\end{array}$

    $\begin{array}{c}=-\log \left[1.6\right]\end{array}$

    $\begin{array}{c}=-0.20\end{array}$

Therefore, the concentration of an acid and pH of the solution is 1.6 M and -0.20 respectively.

(c)

Interpretation Introduction

Interpretation:

The concentration of an acid and the pH of the solution should be predicted.

Concept Introduction:

The full form of pH is the potential of pH. In other words, it explains the strength of the hydrogen ion in a solution. It is given by the formula,

  $\text{pH}=-\log \left[{\text{H}}^{+}\right]$

Answer to Problem 6E

The concentration of an acid and pH of the solution is 0.46 M and 0.34 respectively.

Explanation of Solution

Given information:

• 0.95 M NaOH
• 12 mL NaOH
• 25 mL of acid

The concentration of an acid is calculated as follows:

  $\begin{array}{c}{\text{C}}_{\text{1}}{\text{V}}_{\text{1}}\left(\text{NaOH}\right)={\text{C}}_{\text{2}}{\text{V}}_{\text{2}}\left(\text{acid}\right)\end{array}$

  $\begin{array}{c}\text{0}\text{.95}\text{M}\left(12\text{mL}\right)={\text{C}}_{\text{2}}\left(25\text{mL}\right)\end{array}$

        $\begin{array}{c}{\text{C}}_{\text{2}}=\frac{\text{0}\text{.95}\text{M}\left(12\text{mL}\right)}{25\text{mL}}\end{array}$

        $\begin{array}{c}{\text{C}}_{\text{2}}=0.46\text{M}\end{array}$

The pH of the solution is calculated as follows:

  $\begin{array}{c}\text{pH}=-\log \left[{\text{H}}^{+}\right]\end{array}$

    $\begin{array}{c}=-\log \left[0.46\right]\end{array}$

    $\begin{array}{c}=0.34\end{array}$

Therefore, the concentration of an acid and pH of the solution is 0.46 M and 0.34 respectively.