
Concept explainers
(a)
Interpretation:
The orbital energy level diagram and the number of unpaired electrons in [Co(NH3)6]3+ complex have to be given.
(a)

Explanation of Solution
The oxidation number of cobalt in [Co(NH3)6]3+ complex is +3 and the electronic configuration of Co3+ is [Ar]3d6 and it is an octahedral complex. In an octahedral complex there are six ligands attached to the central
The orbital energy level diagram for d6 configuration is,
Since, ammonia acts as a strong ligand in [Co(NH3)6]3+ complex all the d electrons are paired up in the lower energy levels and there is no unpaired electron.
(b)
Interpretation:
The orbital energy level diagram and the number of unpaired electrons in [Ni(Cl)4]2- complex have to be given.
(b)

Explanation of Solution
The oxidation number of nickel in [Ni(Cl)4]2- complex is +2 and the electronic configuration of Ni2+ is [Ar]3d8 and it is a tetrahedral complex. In a tetrahedral complex, there are four ligands attached to the central metal. The d-orbitals split into two different energy levels. The two three consist of dxy, dxz, dyz and the bottom two consist of dx2-y2 & dz2 the reason for this is due to the poor orbital overlap between the metal and the ligand orbitals
The orbital energy level diagram for d8 configuration is,
Since, chloride ion is a weak ligand the electrons are filled according to the Hund’s rule in the d-orbitals and the number of unpaired electron in nickel complex is two.
(c)
Interpretation:
The orbital energy level diagram and the number of unpaired electrons in [Fe(OH2)6]3+ complex have to be given.
(c)

Explanation of Solution
The oxidation number of iron in [Fe(OH2)6]3+ complex is +3 and the electronic configuration of Fe3+ is [Ar]3d5 and it is an octahedral complex. In an octahedral complex, there are six ligands attached to the central transition metal. The d-orbital splits into two different levels. The bottom three energy levels are dxy, dxz, dyz named as (t2g) and the two upper levels are dx2-y2 & dz2 named as eg set.
The orbital energy level diagram for d5 configuration is,
Since, water is a weak ligand the electrons are filled according to the Hund’s rule in the d-orbitals and the number of unpaired electron in iron complex is five.
(d)
Interpretation:
The orbital energy level diagram and the number of unpaired electrons in [Fe(CN)6]3- complex have to be given.
(d)

Explanation of Solution
The oxidation number of iron in [Fe(CN)6]3- complex is +3 and the electronic configuration of Fe3+ is [Ar]3d5 and it is an octahedral complex. In an octahedral complex there are six ligands attached to the central transition metal. The d-orbital splits into two different levels. The bottom three energy levels are dxy, dxz, dyz named as (t2g) and the two upper levels are dx2-y2 & dz2 named as eg set.
The orbital energy level diagram for d5 configuration is,
Since, cyanide acts as a strong ligand in [Fe(CN)6]3- complex all the d electrons are paired up in the lower energy levels and there is one unpaired electron.
Want to see more full solutions like this?
Chapter 9 Solutions
Chemical Principles: The Quest for Insight
- Don't used hand raitingarrow_forwardQuizzes - Gen Organic & Biological Che... ☆ myd21.lcc.edu + O G screenshot on mac - Google Search savings hulu youtube google disney+ HBO zlib Homework Hel...s | bartleby cell bio book Yuzu Reader: Chemistry G periodic table - Google Search b Home | bartleby 0:33:26 remaining CHEM 120 Chapter 5_Quiz 3 Page 1: 1 > 2 > 3 > 6 ¦ 5 > 4 > 7 ¦ 1 1 10 8 ¦ 9 a ¦ -- Quiz Information silicon-27 A doctor gives a patient 0.01 mC i of beta radiation. How many beta particles would the patient receive in I minute? (1 Ci = 3.7 x 10 10 d/s) Question 5 (1 point) Saved Listen 2.22 x 107 222 x 108 3.7 x 108 2.22 x 108 none of the above Question 6 (1 point) Listen The recommended dosage of 1-131 for a test is 4.2 μCi per kg of body mass. How many millicuries should be given to a 55 kg patient? (1 mCi = 1000 μСi)? 230 mCiarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- Don't used hand raiting and don't used Ai solutionarrow_forwardQ3: Arrange each group of compounds from fastest SN2 reaction rate to slowest SN2 reaction rate. CI Cl H3C-Cl CI a) A B C D Br Br b) A B C Br H3C-Br Darrow_forwardQ4: Rank the relative nucleophilicity of halide ions in water solution and DMF solution, respectively. F CI Br | Q5: Determine which of the substrates will and will not react with NaSCH3 in an SN2 reaction to have a reasonable yield of product. NH2 Br Br Br .OH Brarrow_forward
- Classify each molecule as optically active or inactive. Determine the configuration at each H соон Chirality center OH 애 He OH H3C Ноос H H COOH A K B.arrow_forwardQ1: Rank the relative nucleophilicity of the following species in ethanol. CH3O¯, CH3OH, CH3COO, CH3COOH, CH3S Q2: Group these solvents into either protic solvents or aprotic solvents. Acetonitrile (CH3CN), H₂O, Acetic acid (CH3COOH), Acetone (CH3COCH3), CH3CH2OH, DMSO (CH3SOCH3), DMF (HCON(CH3)2), CH3OHarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- 10. The main product of the following reaction is [1.1:4',1"-terphenyl]-2'-yl(1h-pyrazol-4- yl)methanone Ph N-H Pharrow_forwardDraw the Fischer projection for a D-aldo-pentose. (aldehyde pentose). How many total stereoisomers are there? Name the sugar you drew. Draw the Fischer projection for a L-keto-hexose. (ketone pentose). How many total stereoisomers are there? Draw the enantiomer.arrow_forwardDraw a structure using wedges and dashes for the following compound: H- Et OH HO- H H- Me OHarrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
- Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning





