Chapter 9, Problem 9C.2AST

Interpretation Introduction

Interpretation:

The hydrate isomers present in which $\text{0}\text{.00010}\text{mol}$ of ${\text{CrCl}}_{\text{3}}{\text{.6H}}_{\text{2}}\text{O}$ reacts to form $\text{0}\text{.00010}\text{mol}$ in silver chloride has to be given.

Concept Introduction:

Hydrate Isomers:

Hydrate isomers differ by the exchange of a ${\text{H}}_{\text{2}}\text{O}$ molecule with another ligand in the coordination sphere.  It can be distinguished by the stoichiometry of reactions in which the ion is exchanged with water.

Example:

2 mole of $\text{AgCl}$ can be precipitated from 1 mole $\left[{\text{CrCl(OH}}_{\text{2}}{\text{)}}_{\text{5}}\right]{\text{Cl}}_{\text{2}}{\text{.H}}_{\text{2}}\text{O}\text{.}$

$\left[{\text{CrCl(OH}}_{\text{2}}{\text{)}}_{\text{5}}\right]{\text{Cl}}_{\text{2}}{\text{.H}}_{\text{2}}{\text{O+2Ag}}^{\text{+}}\stackrel{}{\to }\left[{\text{CrCl(OH}}_{\text{2}}{\text{)}}_{\text{5}}\right]{\text{H}}_{\text{2}}\text{O+2AgCl}$