Elementary Statistics: Picturing the World (7th Edition)

7th Edition

ISBN: 9780134683416

Author: Ron Larson, Betsy Farber

Publisher: PEARSON

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Chapter 8.3, Problem 10E

Testing the Difference Between Two Means In Exercises 9–20, (a) identify the claim and state H₀ and H_a, (b) find the critical value(s) and identify the rejection region(s), (c) calculate d ¯ and s_d, (d) find the standardized test statistic t, (e) decide whether to reject or fail to reject the null hypothesis, and (f) interpret the decision in the context of the original claim. Assume the samples are random and dependent, and the populations are normally distributed.

10. SAT Scores An instructor for a SAT preparation course claims that the course will improve the test scores of students. The table shows the critical reading scores for 10 students the first two times they took the SAT. Before taking the SAT for the second time, the students took the instructor’s course to try to improve their critical reading SAT scores. At α = 0.01, is there enough evidence to support the instructor’s claim?

Chapter 8.3, Problem 10E, Testing the Difference Between Two Means In Exercises 920, (a) identify the claim and state H0 and

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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Chapter 8.3, Problem 9E

Chapter 8.3, Problem 11E

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P-values In Exercises 17–20, do the following: a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P- value. (See Figure 8-3 on page 364.) c. Using a significance level of α = 0.05, should we reject H0 or should we fail to reject H0? The test statistic of z = 1.00 is obtained when testing the claim that p > 0.3.

Applying the Concepts and SkillsIn Exercises, perform a Kruskal–Wallis test by using either the critical-value approach or the P-value approach.TV-Commercial Placement. In the article “Violence and Sex Impair Memory for Television Ads” (Journal of Applied Psychology, Vol. 87, No. 3, pp. 557–564), B. Bushman and A. Bonacci studied whether the type of television program in which commercials are placed affects a viewer’s ability to remember the product. Participants watched a violent, sexually explicit, or neutral TV program that contained nine advertisements. The next day, participants were asked to recall the advertised brands. The number of brands the participants were able to recall are presented in the following table. Violent Sexually explict Neutral 0 0 4 0 2 1.000 2 2 2 1 2 3 1 0 2 0 1 7 At the 5% significance level, do the data provide sufficient evidence to conclude that a difference exists in the median number of advertised brands a viewer is able to recall…

Test the claim that the mean GPA of Orange Coast students is larger than the mean GPA of Coastline students at the 0.01 significance level. The null and alternative hypothesis would be: Ho:μο = μc Ho:μο με H1:po pc Hy:μο < με Reject the null hypothesis O Fail to reject the null hypothesis (to 2 decimals) (to 2 decimals)

Chapter 8 Solutions

Elementary Statistics: Picturing the World (7th Edition)

Ch. 8.1 - Classify each pair of samples as independent or...Ch. 8.1 - A survey indicates that the mean annual wages for...Ch. 8.1 - A travel agency claims that the average daily cost...Ch. 8.1 - What is the difference between two samples that...Ch. 8.1 - Explain how to perform a two-sample z-test for the...Ch. 8.1 - Describe another way you can perform a hypothesis...Ch. 8.1 - What conditions are necessary in order to use the...Ch. 8.1 - Prob. 5E Ch. 8.1 - Prob. 6E Ch. 8.1 - Independent and Dependent Samples In Exercises 58,...

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Solution Summary: The claim is that the course will improve the test scores of students. The alternative hypothesis indicates the claim.

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Chapter 8 Solutions