PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
7th Edition
ISBN: 9781119610526
Author: Mannering
Publisher: WILEY
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Chapter 8, Problem 34P
To determine
The probability of the household making three or more peak hour trips,
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QI) For the project data shown in table below. Find the probability of completing
the project in 34 weeks.
Activity
3-6 3-7
7-9 8-10 9-10
1-3
2
5
4-5 5-7 6-7 7-8
2
4
7
1-2
1-4
2-6
3-5
2
2
10
4
4
8
2
6.
8.
2
7
10
M
11
11
10
4
6
8
10
8
13
10
6.
14
4
oloo
I
100
3
25
300
1
Current Year
IV
50
75
25
200
Future Year
T[I]
T[I]
250
4
400
2
150
III
= 300
= 1000
T [III]
= 800
T [IV]
= 300
Distribute the trips for inter zonal movement based on Uniform Growth Factor
Method and Detroit Method. Compare the iteration number & give your conclusion.
the number of newspaper copies distributed is given by C = 50t^2 - 237t + 17900, where t is in years. find the minimum number of copies distributed from 1995 to 2002.
Chapter 8 Solutions
PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
Ch. 8 - Prob. 1PCh. 8 - Prob. 2PCh. 8 - Prob. 3PCh. 8 - Prob. 4PCh. 8 - Prob. 5PCh. 8 - Prob. 6PCh. 8 - Prob. 7PCh. 8 - Prob. 8PCh. 8 - Prob. 9PCh. 8 - Prob. 10P
Ch. 8 - Prob. 11PCh. 8 - Prob. 12PCh. 8 - Prob. 13PCh. 8 - Prob. 14PCh. 8 - Prob. 15PCh. 8 - Prob. 16PCh. 8 - Prob. 17PCh. 8 - Prob. 18PCh. 8 - Prob. 19PCh. 8 - Prob. 20PCh. 8 - Prob. 21PCh. 8 - Prob. 22PCh. 8 - Prob. 23PCh. 8 - Prob. 24PCh. 8 - Prob. 25PCh. 8 - Prob. 26PCh. 8 - Prob. 27PCh. 8 - Prob. 28PCh. 8 - Prob. 29PCh. 8 - Prob. 30PCh. 8 - Prob. 31PCh. 8 - Prob. 32PCh. 8 - Prob. 33PCh. 8 - Prob. 34PCh. 8 - Prob. 35PCh. 8 - Prob. 36PCh. 8 - Prob. 37PCh. 8 - Prob. 38PCh. 8 - Prob. 39P
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- 10. Assume that the duration of some activities is not known with certainty. The estimates of these activities are shown below. Activity A C D G H Optimistic Q 8 3 10 13 8 Most Likely 10 5 12 15 10 POM a. What is the project's expected completion time and its variance? b. What is the probability that the project will be completed in 61 days or more? c. What is the probability that the project will be completed in no more than 54 days? c. If the company wants a 94% probability of completing the project on time, state the latest time each activity should have started and completed. Pessimistic 5+ 12 7 14 17 12arrow_forwardQ2: For the project, its data shown below find: ● Time in weeks that gives a probability of %97.5 Probability of finishing the project 4 weeks more than TE Probability of finishing the project 3 weeks less than TE Act. 1-2 2-3 2-5 2-4 3-4 3-7 5-6 6-7 4-7 0 8 4 7 7 4 7 10 10 4 M 10 5 9 6 8 14 14 5 P 24 12 21 11 8 15 24 24 12arrow_forwardMultinomial Logit Model - Sample Problem Let the number of trips from zone i to zone j is 5000, and two modes are available which has the characteristics given in below. Compute the trips made by the three modes and the fare required to travel by each mode. coefficient car bus train ti twalk tij Fij 0.03 0.04 0.06 0.1 20 18 30 6 12 5 10 3 2 Pij 0.1 Cij = a₁tij + a₂tij + asti; +astnij + a5 Fij + a60j + darrow_forward
- Problem 2 - Use of multi-nomial logit model for estimation of modal split Use a logit model to determine the probabilities of a group of 5000 work commuters choosing between three modes of travel during the morning peak hour, including Privite car, Bus and Light rail If 1450 commuters travel by bus, 950 commuters taking light rail, determine the travel time of driving private cars (T). The utility functions for the three modes are estimated using the following equations: Uc = 2.4 – 0.4C – 0.05 T Ug = 1.4 – 0.4C – 0.05T ULR= 0.4 – 0.4C– 0.05T where C = cost (£) T= travel time (minutes) For all workers: • The cost of driving is £6.00 with a travel time of T minutes • The bus fare is £2.50 with a travel time of 50 minutes The rail fare is £2.80 with a travel time of 35 minutes. where P = probability that mode m is chosen m' = index over all modes included in chosen setarrow_forwardIn a survey in the base year, the trip attraction, number of employees and shopping area in the zones are found as follows: Zone 1 2 3 4 5 6 7 8 9 10 Trip attraction (Trips/day) 34,000 33,000 37,000 9,000 19,000 20,000 50,000 22,000 21,000 5,000 Number of employees (persons) 2000 1500 3000 500 1000 1000 3200 1800 1600 200 Shopping area (m²) 250,000 350,000 150,000 80,000 160,000 180,000 350,000 60,000 100,000 50,000 Prepare a excel worksheet to calculate the generation model by regression analysis.arrow_forwardSuppose that the projected road vehicle traffic flow in a corridor is 5000 vehicle-trips per hour in one direction. The average perceived user cost functions of the two major highways (Route 1 and Route 2 in the corridor are as follows (in dollars): Route 1: Ci =1 +8(qı/5000) Route 2: C2 = 1+10(q2/2500) Where: qi and q2 are the traffic flows on Route 1 and Route 2 respectively. Calculate the volume of traffic during the peak hour on each route, if users were free to choose their own routes.arrow_forward
- Q1. The following is the number of trips and the number of households by the number of persons per household and the level of household income in a given zone. Persons/hh 1 2 3 4 5 or above Low No. of hh 93 72 59 120 13 Persons/household 1 2 3 4 5 or more Trip No. 222 341 417 1010 107 Income Medium Low 120 100 90 150 30 No. of hh 149 138 125 109 37 Trip No. 616 853 1025 1186 457 The forecasted number of households in the study area for a target year is shown below. High Income Medium 280 220 190 180 60 No. of hh 96 27 33 40 33 Trip No. 360 205 381 471 423 High 130 40 50 70 60arrow_forward4. The number of trips generated by each household h (Yh) in Zone A is given by the following household-level regression model: Yh=2.5+1.5 X₁ + 1.2 X2+ 1.0 X3....where, X₁ =Number of Adults (per household). X2 =Number of Cars in the household. X3 =Income in Thousands ($). a. What is the minimum number of trips made by a household based on the equation? b. For a zone labeled “A”, Table 1 provides total number of households classified by household size and number of cars. It is given that the average household income in this Zone is $55K. Compute the number of trips produced from this zone. Table 1: Household Composition for Zone A Number of cars Person per household per household 1 2 3 0 100 200 150 1 300 500 210 2 150 100 60arrow_forwardThe activity-on-arrow network of activities for a construction project is shown in the figure. The duration (expressed in days) of the activities are mentioned besides the arrows. V The critical duration for this construction project isarrow_forward
- Q3): Income from an operation has been decreasing uniformly for 5 years. If income in year 1 was $300,000 and it decreased by $30,000 per year through year 4, the annual worth of the income at 10% per year is closest to:arrow_forwardA Car hire has two cars which it hires out day by day. The number of demands for a car in each day is distributed as poisson distribution with mean 1.5. The number of days in a leap year on which neither of the two cars are on demand isarrow_forwardIf 7 % is considered the minimum attractive rate of return which alternative should be selected year. A B 0. -$14500 -$23000 1. 5900. 9200 2 5900 9200 3 5900 9200arrow_forward
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