Concept explainers
Interpretation:
The way by which triangular bipyramidal and square pyramidal molecular geometries differ from each other has to be given.
Concept introduction:
Electron geometry is the shape of a molecule predicted by considering both bond electron pairs and lone pair of electrons.
Molecular geometry is the shape of a molecule predicted by considering only bond pair of electrons
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Chapter 7 Solutions
Chemistry: The Molecular Science
- If you have three electron regions around a central atom, how can you have a triangular planar molecule? An angular molecule? What bond angles are predicted in each case?arrow_forwardDraw the Lewis structure of SeF₆ and then determine its electron domain and molecular geometries.arrow_forwardIn the trigonal bipyramidal arrangement, why does a lone pair occupy an equatorial position rather than an axial position?arrow_forward
- Draw the Lewis structure of hydrogen cyanide, (HCN) and then choose the appropriate pair of molecular geometries of the two central atoms. Your answer choice is independent of the orientation of your drawn structure.arrow_forwardThe molecules SiF4, SF4, and XeF4 have molecular formulas of the type AF4, but the molecules have different molecular geometries. Predict the shape of each molecule, and explain why the shapes differ.arrow_forwardThe following geometries are possible for a molecule with three atoms bonded to a central atom. II II Assuming the bonded atoms are halogens, determine the central atom for each of these molecular geometries choosing from one of the following atoms. Be, Al, Br, or As,arrow_forward
- Write the two resonances formula for benzene, C6H6, (note the carbon atoms are all bonded to each other forming a ring.). What is the geometry about any one of the carbon atoms? What hybridization would be used in valence bond theory to describe the bonding? The ∆Hf for C6H6(g) is actually -83 kJ/mol. What is the equation for the standard molar enthalpy of formation form benzene? Use the standard enthalpy of formation equation and ∆Hf for C(g) 715 kJ/mol and H2(g) is 0 kJ/mol. Calculate the estimate enthalpy of formation of benzene. Then calculate the resonance energy of benzene. The resonance energy is defined as ∆Hf (estimated) – ∆Hf (actual).arrow_forwardDraw the Lewis structure of SF₃⁻ and then determine the hybridization of the central atom.arrow_forwardPlease envision this table like it was one long table. (I had to make it two because it hung out of the quiz boundaries and was inaccessible.) It is recommended that you draw the Lewis Structure of the molecules and then complete this table. electronic Molecular Molecule Geometry Geometry CH3F tetrahedral tetrahedral NH3 tetrahedral trigonal pyramidal C2F4 trigonal planar trigonal planar CO2 linear linear main dipole Molecule intermolecular moment force CH3F [ Select ] yes NH3 hydrogen bonding yes C2F4 [ Select ) no CO2 ( Select | no > >arrow_forward
- Arrange the following compounds in order of increasing bond angle. Explain H2S, CCl4, NF3arrow_forwardThe concept of valence-shell electron-pair repulsion (VSEPR) is presented in introductory organic chemistry as a way to predict molecular geometries. The idea be- hind VSEPR is that areas of electron density repel each other so that the geometry of bonds and/or lone pairs of electrons around any one atom places these areas as far apart as possible. For four areas of electron density, a tetrahedral geometry is predicted. For three areas of electron density, a trigonal planar geometry is predicted. Two areas of electron density lead to a linear geometry. VSEPR is simply a predictive tool, but in some cases, it gives an incorrect prediction. In these instances, additional insights into bonding are necessary, such as resonance. Interestingly, several important situations are critical to biochemistry where VSEPR breaks down. Two examples are shown here. :O: CH3 H,N H3N CH3 H :0: :0: Histidine The circled nitrogen atoms are predicted by VSEPR to be tetrahedral in geometry because each…arrow_forwardWhich of the following molecules do not exist under the molecular orbital theory? These are substances with no bond order. O Al, 2+ O P2 Be2 S2 O Cl,2- O F21- O C22+ O N2arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning