Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 7.10, Problem 35AAP
(a)
To determine
The plot for the creep strain verses time.
(b)
To determine
The steady-state creep rate for the test condition.
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The following creep data were taken on an aluminum alloy at 480 C (900 F) and a constant stress of 2.75 MPa (400 psi). Plot the data as strain versus time,
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Chapter 7 Solutions
Foundations of Materials Science and Engineering
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- The following creep curve is derived from an aluminum alloy tested at 380℃ with a constant stress of 2.50 MPa. Identify in the illustration the 3 stages of creep. Determine the steady-state creep rate and the rupture lifetime.arrow_forwardSteady-state creep rate data are given in the following table for a nickel alloy at 538 °C (811 K): o(MPa) 10-7 22.0 10 36.1 Compute the stress at which the steady-state creep is 104h' (also at 538 °C).arrow_forwardA specimen of 975 mm long of an S-S90 alloy is exposed to a tensile stress of 300 MPa at 730 degrees Celcious. The steady state creep rate is 0.01 h^-1 at 300 MPa and 730 degrees Celcious. Determine the elongation in mm the specimen would undergo after 4 hoursarrow_forward
- X Incorrect. Steady-state creep rate data are given here for some alloy taken at 200°C (473 K): (h) a (MPa) 2.5x 10 2.3 x 102 71 If it is known that the activation energy for creep is 160000 /mol, compute the steady state creep rate at a temperature of 220°C (493 K) and a stress level of 48 MPa. the tolerance is +/-9% the tolerance is +/-9%arrow_forward6. The following engineering stress-strain data were obtained for 0.2% C plain carbon steel. (a) Plot the engineering stress-strain curve (b) Determine the ultimate tensile strength for the alloy (c) Determine the percent elongation at fracture (d) Plot the true stress-strain curve Engineering strain, in./in. Engineering stress, ksi 30 0.001 55 0.002 60 0.005 68 0.01 72 0.02 74 0.04 75 0.06 76 0.08 75 0.1 73 0.12 69 0.14 65 0.16 56 0.18 51 0.19(fracture)arrow_forward10 - Prob 7. Steady - state creep data taken for stainless steel at a stress level of 70 MPa (10,000 psi) are given as follows: (8 marks) If it is known that the value of the stress exponent n for this alloy is 7.0, compute the steady - state creep rate at 1250 K and a stress level of 50 Mpa. é, (s-1) T (K) 1.0 X 10-5 2.5 X 10-3 977 1089arrow_forward
- Steady-state creep data taken for an iron at a stress level of 140 MPa are given here: &, (h:¹) T(K) 6.4×104 1080 8.8 x 102 1180 If it is known that the value of the stress exponent n for this alloy is 8.5, compute the steady-state creep rate at 1290 K and a stress level of 82 MPa. i h1arrow_forwardConsider a cylindrical specimen of a steel alloy with 8.5 mm diameter and 80 mm long that is pulled in tension. Estimate the following mechanical properties using Fig. 1: a. Modulus of Elasticity and Resilience in MPa and psi b. Ultimate Tensile Strength in MPa and psi c. Fracture Strength in MPa and psi d. Ductility or % elongation at fracture in MPa and psi 2000 10³ psi MPa 300 2000 200 1000 100 0 0.000 0.005 0.010 0.015 Strain 0.020 0.040 0.060 Strain Fig. 1 Engineering Stress-Strain Curve Stress (MPa) 1000 0 0.000 Stress 0.080 300 200 100 0 Stress (10³ psi)arrow_forwardFind the total toughness energy for a metal that experiences both elastic and plastic deformations. The modulus of elasticity is 107.2 GPa, and elastic deformation terminates at a strain of 0.009. For plastic deformation, assume that the relationship between stress and strain is described by T = 1.66xKn, in which the values for K and n are 1453 MPa and 0.175, respectively. Furthermore, plastic deformation occurs between strain values of 0.009 and 0.67, at which point fracture occursarrow_forward
- Calculate the activation energy (in J/mol) for creep for an alloy having the steady state creep behavior shown in the figure. Use the data taken at stress level of 300MPA and temperature of 650C and 730C. Assume that the stress component n in independent of the temperature. 1000 800 600 650°C 400 730°C 200 815°C 100 925°C 80 60 40 20 10-6 10-5 104 10-3 10-2 10-1 10 102 103 Steady-state creep rate (h-) Stress (MPa)arrow_forwardSorry I forgot to add the table. I think the answers will change this time The following creep data were taken on an aluminum alloy at 480 C (900 F) and a constant stress of 2.75 MPa (400 psi). Plot the data as strain versus time, a) then determine the steady-state or minimum creep rate. Note: The initial and instantaneous strain is not included. b) Identify at what time can a secondary creep region occur and at what time would it end to start the tertiary region in a creep curve: (see attachment).arrow_forwardSteady-state creep data taken for an iron at a stress level of 136 MPa are given here: If it is known that the value of the stress exponent n for this alloy is 8.3, compute the steady-state creep rate at 1300 K and a stress level of 83 MPa. i Es (h-¹) T(K) 6.7 x 104 1100 8.5 x 10-2 1200 h-1arrow_forward
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