Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Question
Chapter 7.10, Problem 47SEP
(a)
To determine
The choice of selecting metal for making the component. From the metal
(b)
To determine
The metal which you choose when considering both safety and weight.
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A new processing method is proposed for producing Alumina ceramic heads for total hip replacement.
The new method has been shown to reduce the surface critical flaw size from 4 µm to 2.5 µm.
If the alumina has a plane strain fracture toughness of 5.4 MPa.m0.5 and currently is found to fail at a stress of 200
MPa what will the difference in failure stress be with the reduction in flaw size?
(This question has only one correct answer)
Select one:
а.
253 MPа
O b. A decrease in failure stress of 42 MPa
С.
An increase in failure stress of 53 MPa
O d. 158 MPa
small crack, 4mm deep, is found on the
edge of a large, thick plate structure.
The plate is continuously subjected to
a uniform cyclic tensile stress (in the
direction perpendicular to the crack
plane) which varies from 0 MPa to
100 MPa and back to 0 MPa every 40
seconds. If the next inspection is to
take place in 30 days, would it be safe
to delay the replacement or repair of
the plate until that time? The stress
intensity factor, KI, for this type of
crack is related to the nominal stress,
G, and the crack length, a, via the
relationship is K, = 1.12a Va %3D
For the plate material, the yield stress
is 800 MPa, the fracture toughness
is 50 MN/m2 and threshold stress
intensity factor range is 6 MN/m3/2,
The fatigue-crack growth rate per cycle
for the material, da/dN, can be defined
by: 3/2 da / dN = 2.8 x 10-12 (AK,) ^PY
(m/cycle) Where AK1 has unit MN/m
e 8:34 /
Which of the following statements are true?
(This question has more than one correct answer)
a. You should always apply safety factors when setting a materials specification
b. You should always design in small radii of curvature at profile changes
c. Crack propagation in ductile materials occurs when the stresses at the crack tip are greater or equal to the yield strength of
the material
d. The stress concentration factors for ductile materials are greater than expected
e. The stress concentration factors for brittle materials are less than expected
f. Crack propagation in brittle materials occurs when the stresses at the crack tip are greater or equal to the failure strength of
the material
Chapter 7 Solutions
Foundations of Materials Science and Engineering
Ch. 7.10 - What are the characteristics of the surface of a...Ch. 7.10 - Prob. 2KCPCh. 7.10 - Prob. 3KCPCh. 7.10 - Prob. 4KCPCh. 7.10 - Prob. 5KCPCh. 7.10 - Prob. 6KCPCh. 7.10 - Prob. 7KCPCh. 7.10 - Prob. 8KCPCh. 7.10 - Prob. 9KCPCh. 7.10 - How does the carbon content of a plain-carbon...
Ch. 7.10 - Describe a metal fatigue failure.Ch. 7.10 - What two distinct types of surface areas are...Ch. 7.10 - Prob. 13KCPCh. 7.10 - Prob. 14KCPCh. 7.10 - Prob. 15KCPCh. 7.10 - Describe the four basic structural changes that...Ch. 7.10 - Describe the four major factors that affect the...Ch. 7.10 - Prob. 18KCPCh. 7.10 - Prob. 19KCPCh. 7.10 - Prob. 20KCPCh. 7.10 - Prob. 21KCPCh. 7.10 - Determine the critical crack length for a through...Ch. 7.10 - Determine the critical crack length for a through...Ch. 7.10 - The critical stress intensity (KIC) for a material...Ch. 7.10 - What is the largest size (in mm) of internal...Ch. 7.10 - A Ti-6Al-4V alloy plate contains an internal...Ch. 7.10 - Using the equation KIC=fa, plot the fracture...Ch. 7.10 - (a) Determine the critical crack length (mm) for a...Ch. 7.10 - A fatigue test is made with a maximum stress of 25...Ch. 7.10 - A fatigue test is made with a mean stress of...Ch. 7.10 - A large, flat plate is subjected to...Ch. 7.10 - Prob. 32AAPCh. 7.10 - Refer to Problem 7.31: Compute the final critical...Ch. 7.10 - Prob. 34AAPCh. 7.10 - Prob. 35AAPCh. 7.10 - Equiaxed MAR-M 247 alloy (Fig. 7.31) is used to...Ch. 7.10 - Prob. 37AAPCh. 7.10 - If DS CM 247 LC alloy (middle graph of Fig. 7.31)...Ch. 7.10 - Prob. 39AAPCh. 7.10 - Prob. 40AAPCh. 7.10 - Prob. 41SEPCh. 7.10 - Prob. 42SEPCh. 7.10 - A Charpy V-notch specimen is tested by the...Ch. 7.10 - Prob. 44SEPCh. 7.10 - Prob. 45SEPCh. 7.10 - Prob. 46SEPCh. 7.10 - Prob. 47SEPCh. 7.10 - Prob. 48SEPCh. 7.10 - Prob. 49SEPCh. 7.10 - Prob. 50SEPCh. 7.10 - While driving your car, a small pebble hits your...Ch. 7.10 - Prob. 52SEPCh. 7.10 - Prob. 53SEPCh. 7.10 - Prob. 54SEPCh. 7.10 - Prob. 56SEPCh. 7.10 - Prob. 57SEPCh. 7.10 - Prob. 58SEPCh. 7.10 - Prob. 59SEPCh. 7.10 - The components in Figure P7.60 are high-strength...
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- A support rod for the landing gear of a private airplane is subjected to a tensile load during landing. The loads are predicted to be as high as 40,000 pounds. Because the rod is crucial and failure could lead to a loss of life, the rod is to be designed with a factor of safety of 4 (that is, designed so that the rod is capable of supporting loads four times as great as expected). The operation of the system also produces loads that may induce cracks in the rod. Our non-destructive testing equipment can detect any crack greater than 0.02 in. deep. Based on the materials given in the following Table 7-1, design the support rod and the material, and justify your answer.arrow_forwardAn alumina component fractures at a stress level of 75 MPa. This material has a fracture toughness of 3 MPa(m)1/2. Estimate the external flaw size responsible for this behavior with a geometric factor of f = 1.12. Report your size in mm. 0.4mm 0.4060 mm 9 mm 0.8 mmarrow_forwardHelp me pleasearrow_forward
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