6. The following engineering stress-strain data were obtained for 0.2% C plain carbon steel. (a) Plot the engineering stress-strain curve (b) Determine the ultimate tensile strength for the alloy (c) Determine the percent elongation at fracture (d) Plot the true stress-strain curve Engineering strain, in./in. Engineering stress, ksi 30 0.001 55 0.002 60 0.005 68 0.01 72 0.02 74 0.04 75 0.06 76 0.08 75 0.1 73 0.12 69 0.14 65 0.16 56 0.18 51 0.19(fracture) LO o o LO o o o

6. The following engineering stress-strain data were obtained for 0.2% C plain carbon steel. (a) Plot the engineering stress-strain curve (b) Determine the ultimate tensile strength for the alloy (c) Determine the percent elongation at fracture (d) Plot the true stress-strain curve Engineering strain, in./in. Engineering stress, ksi 30 0.001 55 0.002 60 0.005 68 0.01 72 0.02 74 0.04 75 0.06 76 0.08 75 0.1 73 0.12 69 0.14 65 0.16 56 0.18 51 0.19(fracture) LO o o LO o o o

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

O The following engineering stress-strain data were obtained for a 0.2% C plain-carbon steel. (i) Plot the engineering stress-strain curve. (ii) Determine the ultimate tensile strength of the alloy. (iii) Determine the percent elongation at fracture. Engineering Engineering Engineering Engineering Stress Strain Stress Strain (ksi) (in./in.) (ksi) (in./in.) 76 0.08 30 0.001 75 0.10 55 0.002 73 0.12 60 0.005 69 0.14 68 0.010 65 0.16 72 0.020 56 0.18 74 0.040 51 0.19 75 0.060 (Fracture)
2) Use the engineering stress strain diagram provided below to answer parts (A) to (H) below (the stress-strain diagram has already been drawn for you): stress strain diagram 400 350 0 300 0 250 0 200 0 150.0 100.0 50.0 00 0 05 01 0. 15 strain A. Determine the tensile strength of this alloy. B. show the clastic, plastic and total strain on the diagram stress (Mpa)
Following is the Tensile stress-strain data for several hypothetical metals to be used. Answer the following questions referring to table 1.1. Table 1.1: Material Property Data Material Tensile Strength Fracture Strength Strain at Strength (MPa) (MPa) 340 265 550 505 112 150 Fracture before yielding A B C D 0.23 0.15 0.40 a. Which will experience the greatest percent reduction in area? Why? b. Which is the strongest? Why? c. Which is the stiffest? Why? Elastic Modulus (GPa) 210 310 180 400
The engineering stress-strain curve below was obtained for a precipitation hardened Aluminum alloy. What is the approximate Yield Strength for this alloy in psi? Engineering Stress Based on Original Area (psi) 50,000 45,000 40,000 35,000 30,000 25,000 20,000 15,000 10,000 5,000 0 O 0.02 0.04 0.06 Aluminum 6061-T6 0.08 0.1 0.12 Engineering Strain (in/in) 0.14 X 0.16 0.18
1. What is the approximate ductility (%EL) of a cold worked brass that has a yield strength of 345 MPa (50,000 psi) 140 120 1040 Steel 1040 Steel 120 700 600 100 500 Brass Brass eo S400 Brass 300 Copper 40 200 Copper 040 e 00 40 Copper 100 O 10 20 30 40 50 60 70 Percent cold work 200 0 10 20 30 40 50 60 70 Percent cold work O 10 20 30 40 D0 60 70 Percent cold work (a) (b)
For a piece of copper alloy, a standard stress test was applied to it, the following data was collected, from which a stress-strain diagram must be generated, where as data it is known that the initial diameter of the element is 0.505in. The analysis must include the following: 1.Modulus of Elasticity and modulus of resilience. 2.Percentage of elongation. 3.Percentage of area reduction. 4.Real and engineering stress at fracture. It is known that after the specimen fractures, its dimensions in terms of length and diameter are 3.014 and 0.374in, respectively.
Determine the tensile yield strength (0.2% offset) and the maximum strength of a metal alloy having the following tensile stress-strain diagram. Select one: The tensile yield strength Sy = 100 Mpa and the maximum strength Smax = 250 Mpa. The tensile yield strength Sy = 170 Mpa and the maximum strength Smax = 250 Mpa. The tensile yield strength Sy = 150 Mpa and the maximum strength Smax = 200 Mpa. The tensile yield strength Sy = 240 Mpa and the maximum strength Smax = 250 Mpa. The tensile yield strength Sy = 80 Mpa and the maximum strength Smax = 250 Mpa.
The yield stresses (oy) have been measured using steel and aluminum specimens of various grain sizes, as follows: Q.1 Material D (um) σν (MPa) Steel 60.5 160 136 128 Aluminum 11.1 235 100 223 (a) Determine the coefficients oo and ky in the Hall- Petch for these two materials. (b) Determine the yield stress in each material for a grain size of d326 um.
The figure below shows the tensile engineering stress-strain behavior for a steel alloy. (a) What is the modulus of elasticity? (b) What is the yield strength at a strain offset of 0.002? (c) What is the tensile strength? Stress (MPa) 600 500 400 300 200 100 T I 0.00 Stress (MPa) 0.04 500 400 300 200 100 0.000 0.08 0.002 Strain 0.004 Strain 0.12 I 0.006 0.16 0.20 In the previous problem, A load of 85,000 N (19,100 lbf) is applied to a cylindrical specimen of the steel alloy that has a cross-sectional diameter of 15 mm (0.59 in.). (a) Will the specimen experience elastic and/or plastic deformation? Why? (b) If the original specimen length is 250 mm (10 in.), how much will it increase in length when this load is applied?
al 72% Í 22:39 365 3bed sleimen 10 minutes ago Question 1 Determine the percentage of ductility of a metal alloy having the following tensile stress-strain diagram. Not yer answered Stress-Strain Diagram Marked out of 15.00 P lag question 025 Strain jem/em Select one: O 25% O 0.26
(b) Figure 1 shows, the tensile engineering stress-strain curve for an aluminum alloy. Based on Figure 1, determine: (1) Yield strength (a) (ii) Ultimate Tensile Strength (ors) (ii) Young Modulus (E) | Stress vs Strain 350 300 250 200 150 100 50 0.002 0.004 0.006 0.008 0.01 0.012 0.014 0.016 Strain (mm/mm) Figure 1: Engineering stress-strain curve for aluminum alloy Stress (N/mm2)
1. For the stress-strain curve shown below, please estimate the properties indicated. (a) Fracture Strain Please do your work on a separate sheet of paper, and put your answers in the boxes on the right. Be sure to include the proper symbol and units. Stress Strain 70 60 50 Stress (ksi) 240 30 20 10 70 0 0.000 60 50 Stress (ksi) 40 20 10 KULL 0 0.000 0.010 0.050 0.100 Strain (in/in) Stress Strain 0.020 0.030 Strain (in/in) 0.040 0.150 0.050 (b) Ultimate Tensile Stress (c) Fracture Stress (d) Proportional Limit (e) Elastic Modulus (1) Yield Stress (g) Tensile Toughness (Modulus of Toughness) (h) Modulus of Resilience