Glencoe Chemistry: Matter and Change, Student Edition
Glencoe Chemistry: Matter and Change, Student Edition
1st Edition
ISBN: 9780076774609
Author: McGraw-Hill Education
Publisher: MCGRAW-HILL HIGHER EDUCATION
bartleby

Concept explainers

Crystal Structures
Solids are present all around us. They have different properties and applications. Diamond and graphite are two well-known solids. Diamond is the hardest material in the world and is used in making jewelry. Graphite on the other hand is soft. The lead of…
Question
Book Icon
Chapter 7, Problem 96A
Interpretation Introduction

Interpretation:

The large difference in the melting point of Beryllium which is 1287(C and Lithium which is 180(C needs to be explained.

Concept introduction:

Metallic bonds are those where the metal forms metal ions which are embedded in a sea of electrons. Its ionisation energy is low. Due to the presence of empty orbitals, the metal atoms overlap their valence orbitals and lose their valence electrons.

Expert Solution & Answer
Check Mark

Answer to Problem 96A

The element Beryllium has higher melting point than Lithium as it has two delocalized electrons thus increasing the lattice energy and henceforth it smelting point.

Explanation of Solution

Metallic bonds are formed when metal ions are surrounded by sea of electrons. It occurs between two metals. Its ionisation energy is low. Due to the presence of empty orbitals, the metal atoms overlap their valence orbitals and lose their valence electrons.

Lithium belongs to group 1 and Beryllium belongs to group 2. Lithium has one valence electrons while Beryllium has two valence electrons.

In case of Lithium it indicates that this one electron is delocalized in the metallic lattice. Hence, the energy between this one electron and metal is lower.

In case of Beryllium, there are two outermost electrons and hence delocalizes two electrons in metallic lattice. Due to these two electrons the forces of attraction between delocalized electrons and metal ions are more.

Hence, with increased delocalized electrons, the lattice energy increases thereby increasing the melting point.

Conclusion

The element Beryllium has higher melting point than Lithium as it has two delocalized electrons thus increasing the lattice energy and henceforth its melting point.

Previous
Chapter 7, Problem 95A
Next
Chapter 7, Problem 97A

Chapter 7 Solutions

Glencoe Chemistry: Matter and Change, Student Edition

Ch. 7.1 - Prob. 1SSCCh. 7.1 - Prob. 2SSCCh. 7.1 - Prob. 3SSCCh. 7.1 - Prob. 4SSCCh. 7.1 - Prob. 5SSCCh. 7.1 - Prob. 6SSCCh. 7.2 - Prob. 7PPCh. 7.2 - Prob. 8PPCh. 7.2 - Prob. 9PPCh. 7.2 - Prob. 10PP
Ch. 7.2 - Prob. 11PPCh. 7.2 - Prob. 12SSCCh. 7.2 - Prob. 13SSCCh. 7.2 - Prob. 14SSCCh. 7.2 - Prob. 15SSCCh. 7.2 - Prob. 16SSCCh. 7.2 - Prob. 17SSCCh. 7.2 - Prob. 18SSCCh. 7.3 - Prob. 19PPCh. 7.3 - Prob. 20PPCh. 7.3 - Prob. 21PPCh. 7.3 - Prob. 22PPCh. 7.3 - Prob. 23PPCh. 7.3 - Prob. 24PPCh. 7.3 - Prob. 25PPCh. 7.3 - Prob. 26PPCh. 7.3 - Prob. 27PPCh. 7.3 - Prob. 28PPCh. 7.3 - Prob. 29PPCh. 7.3 - Prob. 30PPCh. 7.3 - Prob. 31PPCh. 7.3 - Prob. 32PPCh. 7.3 - Prob. 33PPCh. 7.3 - Prob. 34SSCCh. 7.3 - Prob. 35SSCCh. 7.3 - Prob. 36SSCCh. 7.3 - Prob. 37SSCCh. 7.3 - Prob. 38SSCCh. 7.3 - Prob. 39SSCCh. 7.4 - Prob. 40SSCCh. 7.4 - Prob. 41SSCCh. 7.4 - Prob. 42SSCCh. 7.4 - Prob. 43SSCCh. 7.4 - Prob. 44SSCCh. 7.4 - Prob. 45SSCCh. 7 - How do positive ions and negative ions form?Ch. 7 - Prob. 47ACh. 7 - Prob. 48ACh. 7 - Prob. 49ACh. 7 - Prob. 50ACh. 7 - Prob. 51ACh. 7 - Prob. 52ACh. 7 - Prob. 53ACh. 7 - Prob. 54ACh. 7 - Prob. 55ACh. 7 - Prob. 56ACh. 7 - Prob. 57ACh. 7 - Prob. 58ACh. 7 - Prob. 59ACh. 7 - Prob. 60ACh. 7 - Prob. 61ACh. 7 - Prob. 62ACh. 7 - Prob. 63ACh. 7 - Prob. 64ACh. 7 - Prob. 65ACh. 7 - Prob. 66ACh. 7 - Prob. 67ACh. 7 - Prob. 68ACh. 7 - Prob. 69ACh. 7 - Prob. 70ACh. 7 - Prob. 71ACh. 7 - Prob. 72ACh. 7 - Prob. 73ACh. 7 - Prob. 74ACh. 7 - Prob. 75ACh. 7 - Prob. 76ACh. 7 - Prob. 77ACh. 7 - Prob. 78ACh. 7 - Prob. 79ACh. 7 - Prob. 80ACh. 7 - Prob. 81ACh. 7 - Prob. 82ACh. 7 - Prob. 83ACh. 7 - Prob. 84ACh. 7 - Prob. 85ACh. 7 - Prob. 86ACh. 7 - Prob. 87ACh. 7 - Prob. 88ACh. 7 - Prob. 89ACh. 7 - Prob. 90ACh. 7 - Prob. 91ACh. 7 - Prob. 92ACh. 7 - Prob. 93ACh. 7 - Prob. 94ACh. 7 - Prob. 95ACh. 7 - Prob. 96ACh. 7 - Prob. 97ACh. 7 - Prob. 98ACh. 7 - Prob. 99ACh. 7 - Prob. 100ACh. 7 - Prob. 101ACh. 7 - Prob. 102ACh. 7 - Prob. 103ACh. 7 - Prob. 104ACh. 7 - Prob. 105ACh. 7 - Prob. 106ACh. 7 - Prob. 107ACh. 7 - Prob. 108ACh. 7 - Prob. 109ACh. 7 - Prob. 110ACh. 7 - Prob. 111ACh. 7 - Prob. 112ACh. 7 - Prob. 113ACh. 7 - Prob. 114ACh. 7 - Prob. 115ACh. 7 - Prob. 116ACh. 7 - Prob. 117ACh. 7 - Prob. 118ACh. 7 - Prob. 119ACh. 7 - Prob. 120ACh. 7 - Prob. 121ACh. 7 - Prob. 122ACh. 7 - Prob. 123ACh. 7 - Prob. 124ACh. 7 - Prob. 125ACh. 7 - Prob. 126ACh. 7 - Prob. 127ACh. 7 - Prob. 128ACh. 7 - Prob. 129ACh. 7 - Prob. 130ACh. 7 - Prob. 131ACh. 7 - Prob. 132ACh. 7 - Prob. 133ACh. 7 - Prob. 134ACh. 7 - Prob. 1STPCh. 7 - Prob. 2STPCh. 7 - Prob. 3STPCh. 7 - Prob. 4STPCh. 7 - Prob. 5STPCh. 7 - Prob. 6STPCh. 7 - Prob. 7STPCh. 7 - Prob. 8STPCh. 7 - Prob. 9STPCh. 7 - Prob. 10STPCh. 7 - Prob. 11STPCh. 7 - Prob. 12STPCh. 7 - Prob. 13STPCh. 7 - Prob. 14STPCh. 7 - Prob. 15STPCh. 7 - Prob. 16STPCh. 7 - Prob. 17STPCh. 7 - Prob. 18STPCh. 7 - Prob. 19STPCh. 7 - Prob. 20STP

Additional Science Textbook Solutions

Find more solutions based on key concepts
1. Why is the quantum-mechanical model of the atom important for understanding chemistry?

Chemistry: Structure and Properties

3. What are prefix multipliers? List some examples.

Chemistry: Structure and Properties (2nd Edition)

For each of the following molecules, (1) draw the correct Lewis structure; (2) label each polar covalent bond w...

General, Organic, and Biological Chemistry (3rd Edition)

Compute the empirical and molecular formulas for each of the following elemental analyses In each case, propose...

Organic Chemistry (9th Edition)

[14.110] The following mechanism has been proposed for the gas-phase reaction of chloroform (CHCI3) and chlorin...

Chemistry: The Central Science (13th Edition)

35. For the reaction shown, calculate how many grams of each product form when the given amount of each reactan...

Introductory Chemistry (5th Edition) (Standalone Book)

Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
SEE MORE TEXTBOOKS