(a)
The speed of the two blocks after collision.
(a)
Answer to Problem 79GP
The speed of the small block after collision is
The speed of the bigger block after collision is
Explanation of Solution
Given:
The mass of small block is
The angle is
The mass of bigger block is
The height is
Formula used:
The expression for the velocity is,
Here, g is the acceleration due to gravity and h is the height.
The expression for relative velocity is,
Here,
The expression for law of conservation of momentum is,
Here,
Calculation:
Consider the initial velocity of the bigger block
Consider the acceleration due to gravity as
The speed of the small block is,
The relative velocity is,
Apply the conservation of momentum.
The speed of the small block after collision using Equation (1) is,
Conclusion:
Thus, the speed of the small block after collision is
(b)
The distance in the incline that smaller mass will go.
(b)
Answer to Problem 79GP
The distance in the incline that smaller mass will go is
Explanation of Solution
Given:
The mass of small block is
The angle is
The mass of bigger block is
The height is
Formula used:
The expression for the acceleration is,
Here, g is the acceleration due to gravity and
The expression for velocity is,
Here, v is the final velocity, a is the acceleration due to gravity, and s is the distance.
Calculation:
From part (a), the speed of the small block after collision is
The acceleration is,
The distance in the incline the smaller mass will go is,
Conclusion:
Thus, the distance in the incline that smaller mass will go is
Chapter 7 Solutions
Physics: Principles with Applications
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