Understanding Our Universe
3rd Edition
ISBN: 9780393614428
Author: PALEN, Stacy, Kay, Laura, Blumenthal, George (george Ray)
Publisher: W.w. Norton & Company,
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Chapter 7, Problem 31QAP
To determine
The reason for slight temperature change during day and night.
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On the night side of Venus, we find that the brightest wavelength, that is the wavelength this region of the planet is emitting the most energy, is about 3.9 micrometres (3.9x10-6 meters). Approximately how warm is the planet in this region?
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Chapter 7 Solutions
Understanding Our Universe
Ch. 7.1 - Prob. 7.1CYUCh. 7.2 - Prob. 7.2CYUCh. 7.3 - Prob. 7.3CYUCh. 7.4 - Prob. 7.4CYUCh. 7.5 - Prob. 7.5CYUCh. 7 - Prob. 1QAPCh. 7 - Prob. 2QAPCh. 7 - Prob. 3QAPCh. 7 - Prob. 4QAPCh. 7 - Prob. 5QAP
Ch. 7 - Prob. 6QAPCh. 7 - Prob. 7QAPCh. 7 - Prob. 8QAPCh. 7 - Prob. 9QAPCh. 7 - Prob. 10QAPCh. 7 - Prob. 11QAPCh. 7 - Prob. 12QAPCh. 7 - Prob. 13QAPCh. 7 - Prob. 14QAPCh. 7 - Prob. 15QAPCh. 7 - Prob. 16QAPCh. 7 - Prob. 17QAPCh. 7 - Prob. 18QAPCh. 7 - Prob. 19QAPCh. 7 - Prob. 20QAPCh. 7 - Prob. 21QAPCh. 7 - Prob. 22QAPCh. 7 - Prob. 23QAPCh. 7 - Prob. 24QAPCh. 7 - Prob. 25QAPCh. 7 - Prob. 26QAPCh. 7 - Prob. 27QAPCh. 7 - Prob. 28QAPCh. 7 - Prob. 29QAPCh. 7 - Prob. 30QAPCh. 7 - Prob. 31QAPCh. 7 - Prob. 32QAPCh. 7 - Prob. 33QAPCh. 7 - Prob. 34QAPCh. 7 - Prob. 35QAPCh. 7 - Prob. 36QAPCh. 7 - Prob. 37QAPCh. 7 - Prob. 38QAPCh. 7 - Prob. 39QAPCh. 7 - Prob. 40QAPCh. 7 - Prob. 41QAPCh. 7 - Prob. 42QAPCh. 7 - Prob. 43QAPCh. 7 - Prob. 44QAPCh. 7 - Prob. 45QAP
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- Would you expect as many impact craters per unit area on the surface of Venus as on the surface of Mars? Why or why not?arrow_forwardWhat is a dust devil? Would you expect to feel more of a breeze from a dust devil on Mars or on Earth? Explain.arrow_forwardHow might Venus’ atmosphere have evolved to its present state through a runaway greenhouse effect?arrow_forward
- If you weigh 150 lbs. on the surface of Earth, how much would you weigh on Venus? On Mars?arrow_forwardThe runaway greenhouse effect and its inverse, the runaway refrigerator effect, have led to harsh, uninhabitable conditions on Venus and Mars. Does the greenhouse effect always cause climate changes leading to loss of water and life? Give a reason for your answer.arrow_forwardDescribe and explain changes in Venuss surface temperature during the planets history.arrow_forward
- Which of the following is NOT best explained by Venus's extreme greenhouse effect? a. its extremely high surface temperature b. its extremely uniform surface temperature c. its extremely low surface wind speeds d. its lack of magnetismarrow_forwardThe clouds that surround Venus are so thick that the planet actually absorbs less sunlight than the Earth. Nevertheless, Venus has a surface temperature of more than 400 C. Which of these best explains this high surface temperature?arrow_forwardDescribe the planet Venus. Attributes like atmosphere, rotation, etc. should be included in your description.arrow_forward
- Assume that Venus has an isothermal atmosphere with a surface temperature of 750 K. The surface pressure of Venus is 90 times the Earth's surface pressure which is about 1013mb. Also assume that the carbon dioxide dominant atmosphere of Venus is photodissociated and oxygen atoms are produced. These oxygen atoms stop the solar wind at the ionopause distance where the atmospheric pressure of Venus and the dynamic pressure of the solar wind are in balance. Accordingly, calculate the lonopause distance of the planet Venus if the solar wind density is 7 #/cm² and solar wind speed is 410 km/sec.arrow_forwardDespite being within the sun’s “habitable zone”, both Venus and Mars have average surface temperatures that do not permit the existence of liquid water. Besides albedo, name three other important properties of a planet that can influence its temperature.arrow_forwardA)At what altitude would a geostationary sattelite need to be above the surface of Mars? Assume the mass of Mars is 6.39 x 1023 kg, the length of a martian solar day is 24 hours 39minutes 35seconds, the length of the sidereal day is 24hours 37minutes 22seconds, and the equatorial radius is 3396 km. The answer can be calculated using Newton's verison of Kepler's third law.arrow_forward
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