Concept explainers
Each of these boxes is pulled by the same force F to the left. All boxes have the same mass and slide on a friction-free surface.
Rank the following from greatest to least.
a. the acceleration of the boxes
b. the tension in the rope connected to the boxes on the right in B and in C
(a)
The rank of the acceleration of the boxes from greatest to least.
Answer to Problem 23A
The rank of the acceleration of the boxes from greatest to least is
Explanation of Solution
Introduction:
The expression for Newton’s second law of acceleration as follows:
Here,
Sketch the Free Body diagram of the forces acting on the system as shown in Figure.
Refer to Figure.
The acceleration of box A as follows:
The acceleration of box B as follows:
The acceleration of box C as follows:
Conclusion:
Thus, the rank of the acceleration of the boxes from greatest to least is
(b)
The rank of the tension in the rope connected to the boxes on the right in B and in C from greatest to least.
Answer to Problem 23A
The rank of the tension in the rope connected to the boxes on the right in B and in C from greatest to least from greatest to least is
Explanation of Solution
Sketch the Free Body diagram of the tension in the rope connected to the boxes on the right in B and in C as shown in Figure.
Refer to Figure.
The tension in the rope connected to the boxes on the right in B as follows
The tension in the rope connected to the boxes on the right in C as follows
Conclusion:
Thus, the rank of the tension in the rope connected to the boxes on the right in B and in C from greatest to least from greatest to least is
Chapter 7 Solutions
Conceptual Physics: The High School Physics Program
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