Essentials of Genetics (9th Edition) - Standalone book
9th Edition
ISBN: 9780134047799
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
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Chapter 7, Problem 13PDQ
Two different female Drosophila were isolated, each heterozygous for the autosomally linked genes black body (b), dachs tarsus (d), and curved wings (c). These genes are in the order d-b-c, with b closer to d than to c. Shown in the following table is the genotypic arrangement for each female, along with the various gametes formed by both. Identify which categories are noncrossovers (NCO), single crossovers (SCO), and double crossovers (DCO) in each case. Then, indicate the relative frequency with which each will be produced.
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In a cross in Drosophila, a female heterozygous for the autosomallylinked genes a, b, c, d, and e (abcde/ + + + + +) was testcrossedwith a male homozygous for all recessive alleles (abcde/abcde).Even though the distance between each of the loci was at least3 map units, only four phenotypes were recovered, yielding thefollowing data:
Phenotype No. of Flies+ + + + + 440a b c d e 460+ + + + e 48a b c d + 52 Total = 1000
Why are many expected crossover phenotypes missing? Can anyof these loci be mapped from the data given here? If so, determinemap distances.
A PORTION OF THE LINKAGE MAP OF CHROMOSOME
2 IN THE TOMATO IS ILLUSTRATED HERE.
ci (compound influorescence)
o (oblate)
- 15 CM
20 CM
p (peach)
THE OBLATE PHENOTYPE IS A FLATTENED FRUIT,
THE PEACH PHENOTYPE IS HAIRY FRUIT (LIKE A
PEACH), AND COMPOUND INFLORESCENCE MEANS
CLUSTERED FLOWERS.
IGNORE THE PEACH LOCUS. AMONG 1000 GAMETES
PRODUCED BY A PLANT OF GENOTYPE O CI /+ +,
WHAT TYPES OF GAMETES WOULD BE EXPECTED,
AND WHAT NUMBER WOULD BE EXPECTED OF EACH?
The genotype of a Drosophila with a heterozygous translocation
between chromosome 2 and chromosome 3 is shown below, where bw =
brown eyes and e = ebony body:
bw+
bw
e
Assume there is no crossing over in the female and that alternate =
adjacent 1 = adjacent 2 disjunction. [Yes, these assumptions are incorrect, but
they make the problem much easier!] Two individuals of the above genotype,
i.e. both heterozygous for this 2;3 translocation and both heterozygous for bw
(on chromosome 2) and e (on chromosome 3) are crossed.
A (Only zygotes with balanced genomes will survive to adulthood.
What proportion of F1 zygotes have a balanced genome?
B. Draw the genotype(s) and state the phenotype(s) of the surviving
progeny you mentioned in part A above. For each different genotype/phenotype
indicate it's frequency among the surviving progeny.
Chapter 7 Solutions
Essentials of Genetics (9th Edition) - Standalone book
Ch. 7 -
CASE STUDY | Links to autism
As parents of an...Ch. 7 -
CASE STUDY | Links to autism
As parents of an...Ch. 7 - CASE STUDY | Links to autism As parents of an...Ch. 7 -
CASE STUDY | Links to autism
As parents of an...Ch. 7 -
HOW DO WE KNOW?
1. In this chapter, we focused on...Ch. 7 -
CONCEPT QUESTION
2. Review the Chapter Concepts...Ch. 7 - Describe the cytological observation that suggests...Ch. 7 - Why does more crossing over occur between two...Ch. 7 - Why is a 50 percent recovery of single-crossover...Ch. 7 - Why are double-crossover events expected less...
Ch. 7 - What is the proposed basis for positive...Ch. 7 - What three essential criteria must be met in order...Ch. 7 - The genes dumpy wings (dp), clot eyes (cl), and...Ch. 7 - Colored aleurone in the kernels of corn is due to...Ch. 7 - In the cross shown here, involving two linked...Ch. 7 - In a series of two-point map crosses involving...Ch. 7 -
13. Two different female Drosophila were...Ch. 7 -
14. In Drosophila, a cross was made between...Ch. 7 -
15. A cross in Drosophila involved the recessive,...Ch. 7 -
16. Drosophila melanogaster has one pair of sex...Ch. 7 -
17. Drosophila females homozygous for the third...Ch. 7 - In Drosophila, the two mutations Stubble bristles...Ch. 7 -
19. A female of genotype
produces 100 meiotic...Ch. 7 - In a plant, fruit color is either red or yellow,...Ch. 7 - In Drosophila, Dichaete (D) is a mutation on...Ch. 7 - An organism of the genotype AaBbCc was testcrossed...Ch. 7 - Based on our discussion of the potential...Ch. 7 - Prob. 24PDQCh. 7 - DNA markers have greatly enhanced the mapping of...Ch. 7 - Are sister chromatid exchanges effective in...
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- Vermillion eye color in Drosophila sp. is a sex-linked recessive trait. What phenotype would be found in this progeny of a cross between a vermillion female and a wild type male?arrow_forwardIN DROSOPHILA, AN X-LINKED RECESSIVE MUTATION, Xm CAUSES MINIATURE WINGS. LIST THE F₂ PHENOTYPIC RATIOS IF: A MINIATURE-WINGED FEMALE IS CROSSED WITH A NORMAL MALE AND A MINIATURE-WINGED MALE IS ● ● CROSSED WITH A NORMAL FEMALE. WHAT WOULD THE PHENOTYPIC RATIO FROM (A) BE IF THE MINIATURE- WINGED GENE WERE AUTOSOMAL? ASSUME IN ALL CASES THAT THE P1 INDIVIDUALS ARE TRUE-BREEDING.arrow_forwardExplain why it is possible for the proband in the following pedigree to have children of blood types A, B, and AB. Considering epistatic genes, what are the possible genotypes of II-2?arrow_forward
- The genes for mahogany eyes and ebony body are approximately 18 map units apart on chromosome III in Drosophila. Assume that a mahogany-eyed female was mated to an ebony-bodied male, and the resulting F1 phenotypically wild-type females were mated to mahogany-ebony males. Of 942 offspring, what would be the expected phenotypes and in what numbers would they be expected?arrow_forwardThree recessive mutations in that affect eye colour, wing shape and body colourarew, m and b. The following numbers were obtained for testcross progeny in Drosophila. Number Phenotype + m + w + b + + b w m + m b 218 236 168 178 95 101 w + + + 3 w mb 1 (i) Determine the chromosomal composition of the heterozygous female parent. Construct a genetic map of the linkage group(s) these genes occupy. Show the order and give the map distances between the genes. (ii)arrow_forwardIn Drosophila, the genes ct(cut wing margin), y (yellow body), and v (vermilion eye color) are X-linked. Females heterozygous for all three markers were mated with wildtype males and the following male progeny were obtained. As is conventional in Drosophila genetics, the wild-type allele of each gene is designated by a “+” sign in the appropriate column. Use the data to (A) create a genetic map of the genes, (B) calculate interference, and (C) interpret the value of interference. Show your work.arrow_forward
- Black body (b) and purple eye (pr) are recessive autosomal mutations in Drosophila. Bridges are crossed b/b females with pr/pr males and in the F2 observed 684 wild type, 371 black-bodied, and 300 purple-eyed flies. Do these results indicate that the b and pr genes are closely linked? Explain. (Remember that there is no crossing-over in male Drosophila)..arrow_forwardBar (B) is a dominant sex-linked mutant of D. melanogaster. Held-out wings and ebony body are recessive, autosomal mutants on chromosome III, mapping 12 map units apart. A Bar-eyed, ebony-bodied male was crossed to a held-out female, and the resulting F1 progeny WERE INBRED to produce the F2. At what frequency do you expect wild-type flies from this cross? (Reminder: Crossing over does not occur in the male). Based on the information in Problem 3, how often would you get a bar ebony but not held-out progeny?arrow_forwardConsider the following three autosomal recessive mutations in Drosophila:vestigial wings (v); wild type is long (v+)black body color (b); wildtype is gray (b+)plum eyes (p); wildtype is red (p+)A vestigal, gray, red female (homozygous for all three genes) is crossed with a long wing, black, plum male (homozygous for all three genes). The F1 female progeny are mated with triple homozygous recessive males. Here is the phenotypic data for the F2 progeny:vestigal; gray; red 580long wings; black; plum 592vestigal; black; red 45long; gray; plum 40vestigal; black; plum 89long; gray; red 94vestigal; gray; plum 3long; black; red 5A total of 1448 progeny were counted.Which one of the following values is the approximate distance between the plum eye color and black body color loci?arrow_forward
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