Essentials of Genetics (9th Edition) - Standalone book
9th Edition
ISBN: 9780134047799
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
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Textbook Question
Chapter 7, Problem 11PDQ
In the cross shown here, involving two linked genes, ebony (e)and claret (ca), in Drosophila, where crossing over does not occur in males, offspring were produced in a (2+:1ca:1e)
These genes are 30 mu apart on chromosome III. What did crossing over in the female contribute to these phenotypes?
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In Drosophila,, the curled mutation (cu, chromosome 3, position 50.0) results in wings that curl up,
while ebony (e, chromosome 3, position 70.7) results in a dark body. True breeding, wild type females
are mated with true breeding males with curled wings and ebony bodies.
Considering Drosophila notation, which of the following correctly diagrams the P1 cross?
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The genes for mahogany eyes and ebony body are approximately 18 map units apart on chromosome III in Drosophila. Assume that a mahogany-eyed female was mated to an ebony-bodied male, and the resulting F1 phenotypically wild-type females were mated to mahogany-ebony males. Of 942 offspring, what would be the expected phenotypes and in what numbers would they be expected?
The genotype of a Drosophila with a heterozygous translocation
between chromosome 2 and chromosome 3 is shown below, where bw =
brown eyes and e = ebony body:
bw+
bw
e
Assume there is no crossing over in the female and that alternate =
adjacent 1 = adjacent 2 disjunction. [Yes, these assumptions are incorrect, but
they make the problem much easier!] Two individuals of the above genotype,
i.e. both heterozygous for this 2;3 translocation and both heterozygous for bw
(on chromosome 2) and e (on chromosome 3) are crossed.
A (Only zygotes with balanced genomes will survive to adulthood.
What proportion of F1 zygotes have a balanced genome?
B. Draw the genotype(s) and state the phenotype(s) of the surviving
progeny you mentioned in part A above. For each different genotype/phenotype
indicate it's frequency among the surviving progeny.
Chapter 7 Solutions
Essentials of Genetics (9th Edition) - Standalone book
Ch. 7 -
CASE STUDY | Links to autism
As parents of an...Ch. 7 -
CASE STUDY | Links to autism
As parents of an...Ch. 7 - CASE STUDY | Links to autism As parents of an...Ch. 7 -
CASE STUDY | Links to autism
As parents of an...Ch. 7 -
HOW DO WE KNOW?
1. In this chapter, we focused on...Ch. 7 -
CONCEPT QUESTION
2. Review the Chapter Concepts...Ch. 7 - Describe the cytological observation that suggests...Ch. 7 - Why does more crossing over occur between two...Ch. 7 - Why is a 50 percent recovery of single-crossover...Ch. 7 - Why are double-crossover events expected less...
Ch. 7 - What is the proposed basis for positive...Ch. 7 - What three essential criteria must be met in order...Ch. 7 - The genes dumpy wings (dp), clot eyes (cl), and...Ch. 7 - Colored aleurone in the kernels of corn is due to...Ch. 7 - In the cross shown here, involving two linked...Ch. 7 - In a series of two-point map crosses involving...Ch. 7 -
13. Two different female Drosophila were...Ch. 7 -
14. In Drosophila, a cross was made between...Ch. 7 -
15. A cross in Drosophila involved the recessive,...Ch. 7 -
16. Drosophila melanogaster has one pair of sex...Ch. 7 -
17. Drosophila females homozygous for the third...Ch. 7 - In Drosophila, the two mutations Stubble bristles...Ch. 7 -
19. A female of genotype
produces 100 meiotic...Ch. 7 - In a plant, fruit color is either red or yellow,...Ch. 7 - In Drosophila, Dichaete (D) is a mutation on...Ch. 7 - An organism of the genotype AaBbCc was testcrossed...Ch. 7 - Based on our discussion of the potential...Ch. 7 - Prob. 24PDQCh. 7 - DNA markers have greatly enhanced the mapping of...Ch. 7 - Are sister chromatid exchanges effective in...
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- In Drosophila the genes forked bristles (f and f+) and vermilion eyes (v and v+) are ~24 m.u. apart on the X chromosome. From a cross of f v / f+ v+ females with f v / y males, what % of the progeny do you expect to have the f+ v+ phenotypes? (Don’t let the X chromosome throw you off – this question is essentially asking what % of the female’s gametes will be f+ v+).arrow_forwardFemales of wild-type Strain A and males of mutant Strain B, as well as females of mutant Strain B and males of wild-type Strain A, make reciprocal crosses. Explain why reciprocal crosses are needed in genetics experiments involving Drosophila fruit flies.arrow_forwardDrosophila females heterozygous for three recessive mutations, a, b, and c , were crossed to males homozygous for all three mutations.The cross yielded the following results: in the image Q. Construct a linkage map showing the correct order of these genes and estimate the distances between them.arrow_forward
- In Drosophila, a cross was made between females—all expressing the three X-linked recessive traits scute bristles (sc), sable body (s), and vermilion eyes (v)—and wild-type males. In the F1, all females were wild type, while all males expressed all three mutant traits. The cross was carried to the F2 generation, and 1000 offspring were counted, with the results shown in the following table. Phenotype Offspring sc s v 314 + + + 280 + s v 150 sc + + 156 sc + v 46 + s + 30 sc s + 10 + + v 14 No determination of sex was made in the data. (a) Using proper nomenclature, determine the genotypes of the P1 and F1 parents. (b) Determine the sequence of the three genes and the map distances between them. (c) Are there more or fewer double crossovers than expected? (d) Calculate the coefficient of coincidence. Does it represent positive or negative interference?arrow_forwardIn Drosophila, a heterozygous female for the X-linkedrecessive traits a, b, and c was crossed to a male that phenotypically expressed a, b, and c. The offspring occurred inthe following phenotypic ratios.+ b c 460a + + 450a b c 32+ + + 38a + c 11+ b + 9 No other phenotypes were observed.(a) What is the genotypic arrangement of the alleles ofthese genes on the X chromosome of the female?arrow_forwardVermillion eye color in Drosophila sp. is a sex-linked recessive trait. What phenotype would be found in this progeny of a cross between a vermillion female and a wild type male?arrow_forward
- A PORTION OF THE LINKAGE MAP OF CHROMOSOME 2 IN THE TOMATO IS ILLUSTRATED HERE. ci (compound influorescence) o (oblate) - 15 CM 20 CM p (peach) THE OBLATE PHENOTYPE IS A FLATTENED FRUIT, THE PEACH PHENOTYPE IS HAIRY FRUIT (LIKE A PEACH), AND COMPOUND INFLORESCENCE MEANS CLUSTERED FLOWERS. IGNORE THE PEACH LOCUS. AMONG 1000 GAMETES PRODUCED BY A PLANT OF GENOTYPE O CI /+ +, WHAT TYPES OF GAMETES WOULD BE EXPECTED, AND WHAT NUMBER WOULD BE EXPECTED OF EACH?arrow_forwardTwo different female Drosophila were isolated, each heterozygous for the autosomally linked genes black body (b), dachs tarsus (d), and curved wings (c). These genes are in the order d–b–c, with b closer to d than to c. Shown in the following table is the genotypic arrangement for each female, along with the various gametes formed by both. Identify which categories are noncrossovers (NCO), single crossovers (SCO), and double crossovers (DCO) in each case. Then, indicate the relative frequency with which each will be produced.arrow_forwardIn Drosophila,, the curled mutation (cu, chromosome 3, position 50.0) results in wings that curl up, while ebony (e, chromosome 3, position 70.7) results in a dark body. True breeding, wild type females are mated with true breeding males with curled wings and ebony bodies. Considering Drosophila notation, which of the following correctly diagrams the F1 cross? X X 3+ cu e + X X e + + + + + cu e + O + ■ 3+ X X X X Y Y + + ■ cu cu cu ' + ■ cu ■ ' + e + e e e e e + cu +arrow_forward
- In Drosophila, a heterozygous female for the X-linkedrecessive traits a, b, and c was crossed to a male that phenotypically expressed a, b, and c. The offspring occurred inthe following phenotypic ratios.+ b c 460a + + 450a b c 32+ + + 38a + c 11+ b + 9 No other phenotypes were observed.(a) What progeny phenotypes are missing? Why?arrow_forwardIn Drosophila, a cross was made between a yellowbodied male with vestigial (not fully developed)wings and a wild-type female (brown body). The F1generation consisted of wild-type males and wild-typefemales. F1 males and females were crossed, and theF2 progeny consisted of 16 yellow-bodied males withvestigial wings, 48 yellow-bodied males with normalwings, 15 males with brown bodies and vestigialwings, 49 wild-type males, 31 brown-bodied femaleswith vestigial wings, and 97 wild-type females.Explain the inheritance of the two genes in questionbased on these results.arrow_forwardA female Drosophila with the mutant phenotype 'notched wings' was mated to a wild type male. Two-thirds of the progeny were female. Half of the females had notched wings and the other half had wild type wings and all the male progeny had wild type wings. When the notched progeny were mated to their wild type brothers, the same results were obtained. Explain.arrow_forward
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