EBK EXPERIMENTAL ORGANIC CHEMISTRY: A M
6th Edition
ISBN: 9781305687875
Author: Gilbert
Publisher: CENGAGE LEARNING - CONSIGNMENT
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 6.3, Problem 6E
Interpretation Introduction
Interpretation: The compound’s affinity needs to be explained for the mobile phase relative to the stationary phase based on the principle of like dissolves like.
Concept introduction: Column chromatography is a large scale solid-liquid adsorption chromatographic technique that can separate multigram amounts of mixtures. This is a preparative version of thin layer chromatography that permits separation and isolation of products by collection of eluted fractions.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The density of an aqueous solution increases as solutes such as salts are added. What bearing might this have on predicting whether the aqueous solution will be on the top or on the bottom for an extraction?
(d) Why is complete solid solubility likely to occur in substitutional solid solutions but not in
interstitial solid solutions?
Experiments show that the solubility
of alum in 25 ml of 1.4 M KOH and 10
ml of 9 M H2SO4 is approximately 1.0
g at 1.0 oC and 1.7 g at 6.0 oC.
Estimate the amount of alum left in
the 65 ml of a solution chilled to 4 oC.
What might you do reduce the
amount of alum remaining in
solution?
Chapter 6 Solutions
EBK EXPERIMENTAL ORGANIC CHEMISTRY: A M
Ch. 6.2 - Prob. 1ECh. 6.2 - Prob. 2ECh. 6.2 - Prob. 3ECh. 6.2 - Prob. 4ECh. 6.2 - Prob. 5ECh. 6.2 - Prob. 6ECh. 6.2 - Prob. 7ECh. 6.2 - Prob. 8ECh. 6.2 - Prob. 9ECh. 6.3 - Prob. 1E
Ch. 6.3 - Prob. 2ECh. 6.3 - Prob. 3ECh. 6.3 - Prob. 4ECh. 6.3 - Prob. 5ECh. 6.3 - Prob. 6ECh. 6.3 - Prob. 7ECh. 6.3 - Prob. 8ECh. 6.3 - Prob. 9ECh. 6.3 - Prob. 10ECh. 6.3 - Prob. 11ECh. 6.3 - Prob. 12ECh. 6.3 - Prob. 13ECh. 6.3 - Prob. 14ECh. 6.3 - Prob. 15ECh. 6.3 - Prob. 16ECh. 6.3 - Prob. 17ECh. 6.3 - Prob. 18ECh. 6.3 - Prob. 19ECh. 6.3 - Prob. 20ECh. 6.4 - Prob. 1ECh. 6.4 - Prob. 2ECh. 6.4 - Prob. 3ECh. 6.4 - Prob. 4ECh. 6.4 - Prob. 5E
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- The distribution coefficient of hydrogen sulfide between benzene and water at 25 degrees Celsius is 5.9880. What is the minimum volume of benzene at 25 degrees Celsius necessary to extract in a single step 80% of the hydrogen sulfide from 1 liter of 0.15 molar aqueous solution of hydrogen sulfide?a.) 0.1336b.) 23.9520c.) 0.6680d.) 1.5030E.) none of the abovearrow_forwardWhat is the minimum distribution constant that permits removal of 99% of a solute from 50.0 mL of water with two 25.0-mL extractions with toluene? five 10.0-mL extractions with toluene?arrow_forwardWhat is the minimum distribution constant that permits removal of 99% of a solute from 50.0 mL of water with five 10.0-mL extractions with toluene?arrow_forward
- List and describe two methods that can used to improve the separation of a liquid mixture by fractional distillationarrow_forwardDescribe the distillation of partial miscible liquid in terms of phase diagram.arrow_forwardWhat Is The Activity Coefficient Of Benzoate Ion (C7H5O2-) With An Ionic Size Parameter Of a = 0.60 nm For 0.50 M Sodium Sulfate Solution?arrow_forward
- For solid solutions, check all that applies: V A. For the case of an interstitial solid solution of elements A and B, the atomic diameters do not differ by more than 15%. O B. For the case of an interstitial solid solution of elements A and B, the solute atom is much smaller than the solvent atom. V C. For the case of a substitutional solid solution of elements A and B, a difference in crystal structure of the two elements does not affect solubility. O D. For the case of a substitutional solid solution of elements A and B, high solubility requires that the atomic diameters do not differ by more than 15%.arrow_forward15 g of unknown organic sample was dissolve in 575 mL of Dicloromethane (DCM). The boiling point of benzene was increased by 3.40oC. Determine the molecular weight of the unknown sample? Kb of DCM = 2.42oC/m Bb of benzene = 39.6 oC density of benzene = 1.33 g/mL at 25 °Carrow_forwardo Solute S has a distribution constant of 4.7 between water (phase 1) and hexane (phase 2). A 82.0 mL solution of S in water is extracted six times with 17.0 mL of hexane. Calculate the fraction of S remaining in the aqueous phase. fraction remaining:arrow_forward
- Describe the differences between a Stober procedure and a water/oil emulsion procedure for the synthesis of colloidal silica particles.arrow_forward7 How is the variation in sample composition in a powder random mix influenced by the proportion of active ingredient particles and by the total number of particles in the sample?arrow_forwardWhat is the mean ionic activity coefficient for the ions M3+ and X1- of the ionic compound M1X3 if we could somehow magically know that y+ = 0.930 and y- = 0.473? %3D Type your answer...arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physical ChemistryChemistryISBN:9781133958437Author:Ball, David W. (david Warren), BAER, TomasPublisher:Wadsworth Cengage Learning,
Physical Chemistry
Chemistry
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Wadsworth Cengage Learning,
Thermogravimetric Analysis [ TGA ] # Thermal Analysis # Analytical Chemistry Part-11# CSIR NET/GATE; Author: Priyanka Jain;https://www.youtube.com/watch?v=p1K-Jpzylso;License: Standard YouTube License, CC-BY