Chapter 6, Problem 55A

Interpretation Introduction

Interpretation: One of the given oxides of N must be chosen for which N is 46.7 %.

Concept Introduction :

Empirical formula of a molecule is the smallest unit which is repeated in the molecule.

Molecular formula of a compound is the representation of the molecule with the number of different atoms present in the molecule.

Molecular formula $\text{=empirical formula×n}$ where n is any positive integer like 1, 2, 3 and so on.

Answer to Problem 55A

The molecular formula is NO in which N is 46.7 %.

Explanation of Solution

% of N is 46.7 % and % of O $=(100-46.7)\%=53.3\%.$

Moles of N $=\frac{46.7}{14}=\mathrm{3.34.}$ .

Moles of O $=\frac{53.3}{16}=\mathrm{3.33.}$

Smallest mole ratio N: O $\begin{array}{l}=\frac{3.34}{3.33}:\frac{3.33}{3.33}\\ =1.003:1\approx :1:1.\end{array}$

Thus the compound is NO.

Conclusion

The species is NO which has 46.7 % N.