Chapter 6, Problem 49A

Interpretation Introduction

Interpretation :

Molecular formula of the compound with empirical formula CH₄O and molar mass approximately 192 g must be found out.

Concept Introduction :

Empirical formula of a molecule is the smallest unit which is repeated in the molecule.

Molecular formula of a compound is the representation of the molecule with the number of different atoms present in the molecule.

Molecular formula $\text{=empirical formula×n}$ where n is any positive integer like 1, 2, 3 and so on.

Answer to Problem 49A

The molecular formula is C₆H₂₄O₆.

Explanation of Solution

The molecular formula can be found from the empirical formula using the following relationship.

Molecular formula $\text{=empirical formula×n}$ where n is any positive integer like 1, 2, 3 and so on.

Molar mass of ${\text{CH}}_4\text{O=(12+4}\times \text{1+16)g=32 g}\text{.}$

Molar mass of the compound is approximately 192 g.

Now Molecular formula= ${{\text{(CH}}_4\text{O)}}_{\text{n}}$ .

Thus 192= ${{\text{(CH}}_4\text{O)}}_{\text{n}}$ or $\text{n=}\frac{192}{32}\text{=6}$ .

Thus molecular formula is ${{\text{(CH}}_4\text{O)}}_6{\text{=C}}_6{\text{H}}_{24}{\text{O}}_6\text{.}$

Conclusion

Molecular formula of the compound is C₆H₂₄O₆.