Chapter 6, Problem 3A

Interpretation Introduction

Interpretation: The number of corks, number of rubber stops and mass of rubber stoppers needs to be determined using the given information.

Concept Introduction: The molecular mass of compound is the sum of atomic mass of all the atoms present in the given chemical compound. Mole concept is used to calculate the moles, mass, number of atoms and moles of a compound. The relation between these values can be shown as:

  $\begin{array}{l}\text{Moles = }\frac{\text{mass}}{\text{molar mass}}\\ {\text{1 mole = N}}_{\text{a}}\text{ atoms}\\ {\text{N}}_{\text{a}}\text{ = 6}\text{.022 }\times {\text{ 10}}^{\text{23}}\end{array}$

Answer to Problem 3A

  $\text{Number of corks = 307corks}$

  $\text{Number of rubber stopper = 116 rubber stopper}$

  $\text{Mass of rubber stoppers = }2642\text{ g}$

Explanation of Solution

Given information:

Mass of corks = 1.63 g

Mass of rubber stopper = 4.31 g

Given mass of corks = 500 g

Given mass of stoppers= 500 g

Calculate number of corks in 500 g:

  $\text{Number of corks = }\frac{\text{500 g}}{\text{1}\text{.63 g}}\text{=307corks}$

Calculate number of rubber stopper in 500 g:

  $\text{Number of rubber stopper = }\frac{\text{500 g}}{\text{4}\text{.31 g}}\text{= 116 rubber stopper}$

Number of corks in 1.00 kg or 1000 g:

  $\text{Number of corks = }\frac{\text{1000 g}}{\text{1}\text{.63 g}}\text{=613 corks}$

Number of rubber stoppers = 613

Mass of each rubber stopper = 4.31 g

So total mass of rubber stoppers:

  $\text{Mass = 613 }\times \text{ 4}\text{.31 g = 2642 g}$

Conclusion

Thus,

  $\text{Number of corks = 307corks}$

  $\text{Number of rubber stopper = 116 rubber stopper}$

  $\text{Mass of rubber stoppers = }2642\text{ g}$