Concept explainers
(a)
Interpretation:
The mass of the lithium in grams is to be calculated.
Concept Introduction:
The
The formula to calculate the mass of any species for a given number of moles is,
Where,
n represents the number of moles.
(a)
Answer to Problem 16A
The mass of lithium in
Explanation of Solution
The average molecular mass is also equal to molecular mass. The mass of lithium is calculated as follows:
The formula to calculate the number of moles is,
Where,
n represents the number of moles.
Therefore the mass of the species becomes,
Given data:
n =
The molecular mass of lithium =
Plugin the values in equation (2)
(b)
Interpretation:
The mass of the aluminum present in
Concept Introduction:
The average atomic mass is numerically equal to the atomic mass which is given in the periodic table.
The formula to calculate the mass of any species for a given number of moles is,
Where,
n represents the number of moles.
(b)
Answer to Problem 16A
The mass of aluminum in
Explanation of Solution
The average molecular mass is also equal to molecular mass. The mass of aluminum is calculated as follows:
The formula to calculate the number of moles is,
Where,
n represents the number of moles.
Therefore the mass of the species becomes,
Given data:
n =
The molecular mass of aluminum =
Plugin the values in equation (2)
(c)
Interpretation:
The mass of lead in grams is to be calculated.
Concept Introduction:
The average atomic mass is numerically equal to the atomic mass which is given in the periodic table.
The formula to calculate the mass of any species for a given number of moles is,
Where,
n represents the number of moles.
(c)
Answer to Problem 16A
The mass of lead in
Explanation of Solution
The average molecular mass is also equal to molecular mass. The mass of lead is calculated as follows:
The formula to calculate the number of moles is,
Where,
n represents the number of moles.
Therefore the mass of the species becomes,
Given data:
n =
The molecular mass of lead =
Plugin the values in equation (2)
(d)
Interpretation:
The mass of chromium present in
Concept Introduction:
The average atomic mass is numerically equal to the atomic mass which is given in the periodic table.
The formula to calculate the mass of any species for a given number of moles is,
Where,
n represents the number of moles.
(d)
Answer to Problem 16A
The mass of chromium in
Explanation of Solution
The average molecular mass is also equal to molecular mass. The mass of chromium is calculated as follows:
The formula to calculate the number of moles is,
Where,
n represents the number of moles.
Therefore the mass of the species becomes,
Given data:
n =
The molecular mass of chromium =
Plugin the values in equation (2)
(e)
Interpretation:
The mass of iron present in
Concept Introduction:
The average atomic mass is numerically equal to the atomic mass which is given in the periodic table.
The formula to calculate the mass of any species for a given number of moles is,
Where,
n represents the number of moles.
(e)
Answer to Problem 16A
The mass of iron in
Explanation of Solution
The average molecular mass is also equal to molecular mass. The mass of chromium is calculated as follows:
The formula to calculate the number of moles is,
Where, n represents the number of moles.
Therefore the mass of the species becomes,
Given data:
n =
The molecular mass of iron =
Plugin the values in equation (2)
(f)
Interpretation:
The mass of magnesium is to be calculated.
Concept Introduction:
The average atomic mass is numerically equal to the atomic mass which is given in the periodic table.
The formula to calculate the mass of any species for a given number of moles is,
Where,
n represents the number of moles.
(f)
Answer to Problem 16A
The mass of magnesium
Explanation of Solution
The average molecular mass is also equal to molecular mass. The mass of chromium is calculated as follows:
The formula to calculate the number of moles is,
Where,
n represents the number of moles.
Therefore the mass of the species becomes,
Given data:
n =
The molecular mass of magnesium =
Plugin the values in equation (2)
Chapter 6 Solutions
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