Explanation The level of service is LOS C . Given: The free flow speed is 56 mi / h . The two way flow rate is 275 veh / h . The analysis directional flow rate is 324 veh / h . The opposing directional flow rate is 216 veh / h . The peak hour factor is 0.87 . Formula Used: Write the expression for the analysis flow rate. v p = V P H F × f G × f HV …… (I) Here, v p is the flow rate, V is the hourly volume, P H F is the peak hour factor, N is the number of lanes and f HV is the heavy vehicle adjustment factor. Write the expression for the heavy vehicle adjustment factor. f HV = 1 1 + P T ( E T − 1 ) + P R ( E R − 1 ) …… (II) Here, P T is the proportion of the heavy vehicles and E T is the passenger car equivalent for heavy vehicles. Write the expression for free flow speed. A T S d = F F S − 0.00776 ( v d ) − f np …… (III) Here, A T S d is the average travel speed. Write the expression for base percent spent time. B P T S F d = 100 [ 1 − e a v d b ] …… (IV) Here, B P T S F d is the base percent spent time and a , b are constants. Write the expression for percent spent time. P T S F d = B P T S F d + f np …… (V) Here, P T S F d is the percent spent time. Write the expression for total volume. V = directional flow + opposite direction flow …… (VI) Here, V is the total volume. Calculation: Refer Table 6.16 “Passenger car equivalent for heavy vehicles for average travel speed” of the book “Principles of Highway Engineering and traffic, 6 th Edition.” For the truck with rolling terrain having directional flow less than 100 E T is 1.9 and E R is 1.1 . Substitute 1.9 for E T , 0.10 for P R , 1.1 for E R and 0.15 for P T in equation (II). f HV = 1 1 + 0.15 ( 1.9 − 1 ) + 0.10 ( 1.1 − 1 ) = 0.873 For opposing direction, Refer Table 6.16 “Passenger car equivalent for heavy vehicles for average travel speed” of the book “Principles of Highway Engineering and traffic, 6 th Edition.” For the truck with rolling terrain having directional flow 200 E T is 1.5 and E R is 1.0 . Substitute 1.5 for E T , 0.10 for P R , 1.0 for E R and 0.05 for P T in equation (II). f HV = 1 1 + 0.05 ( 1.5 − 1 ) + 0.10 ( 1 − 1 ) = 1 1 + 0.025 + 0 = 1 1.025 = 0.976 Refer Table 6.15 “Grade adjustment factor for average travel speed” of the book “Principles of Highway Engineering and traffic, 6 th Edition.” The f G for directional flow rate 400 veh / h on rolling terrain is 0.90 . The f G for directional flow rate 300 veh / h on rolling terrain is 0.83 . Calculate the f G for directional flow rate 324 veh / h on rolling terrain using interpolation, x = 0

The level of service of highway.

Principles of Highway Engineering and Traffic Analysi (NEW!!)

6th Edition

ISBN: 9781119305026

Author: Fred L. Mannering, Scott S. Washburn

Publisher: WILEY

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Chapter 6, Problem 31P

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Tubibi Highway is a Class II Two-lane highway that is considered a level terrain. Based on the data, 1,631 passenger cars travel on average per hour for both directions with a directional split of 50/50. A maximum of 388 passenger cars is recorded within a 15-min time segment of the peak hour. The traffic stream contains 2% large trucks, 3% buses, and 3% recreational vehicles. Determine the opposing direction flow rate in pc/hr. Answer in two decimal places. 2,953.65 776 margin of error +/- 0.5

A class I two-lane highway is on Rolling terrain with a measured free-flow speed of 90 km/h. and 80% no passing zones. The analysis direction flow rate is 324 veh/h, the opposing direction flow rate is 216 veh/h, and the PHF = 0.87. There are 5% large trucks and 10% recreational vehicles. Determine the level of services.

Class I two-lane highway is on rolling terrain and the free-flow speed was measured at 56 mi/h, but this was during a two-way flow rate of 275 veh/h. There are 80% no-passing zones. During the peak hour, the analysis direction flow rate is 324 veh/h, the opposing direction flow rate is 216 veh/h, and the PHF = 0.87. There are 5% large trucks and buses and 10% recreational vehicles. Determine the level of service.

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The level of service of highway.

Solution Summary: The author explains the level of service of highway. The free flow speed, the two-way flow rate, and the peak hour factor are given.

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