(a) Show that the voltage-division rule for two capacitors in series as in Fig. 6.59(a) is v 1 = C 2 C 1 + C 2 v s , v 2 = C 1 C 1 + C 2 v s assuming that the initial conditions are zero. Figure 6.59 For Prob. 6.25. (b) For two capacitors in parallel as in Fig. 6.59(b), show that the current-division rule is i 1 = C 1 C 1 + C 2 i s , i 2 = C 2 C 1 + C 2 i s assuming that the initial conditions are zero.
(a) Show that the voltage-division rule for two capacitors in series as in Fig. 6.59(a) is v 1 = C 2 C 1 + C 2 v s , v 2 = C 1 C 1 + C 2 v s assuming that the initial conditions are zero. Figure 6.59 For Prob. 6.25. (b) For two capacitors in parallel as in Fig. 6.59(b), show that the current-division rule is i 1 = C 1 C 1 + C 2 i s , i 2 = C 2 C 1 + C 2 i s assuming that the initial conditions are zero.
Solution Summary: The author illustrates the voltage division rule for two series capacitors. The charge enclosed in each capacitor is equal.
Please draw the problem and answer, thanks for the help.
A capacitor is made of 2 rectangular metal plates with side length of 3 cm x 6 cm separated by a distance of 2.36 cm with water in between the plates. The capacitor has a voltage of 110 v and is not connected to a battery. Calculate the capacitance. What is the new capacitance if we replace water with a new dielectric material with a constant of 3.75 in between the plates? What is the new voltage? What is the charge on each plate?
6. The total capacitance of two 40-mF series-connected capacitors in parallel with a
70-mF capacitor is?
We connect a 6 uF capacitor to the terminals of a 12 V battery, leaving it for a long time. Once the capacitor is fully charged, we
remove the 12 V battery. Next, we connect the positive plate of the capacitor to the positive terminal of a 6 V battery, and the negative
plate of the capacitor to the battery's negative terminal. At the moment the capacitor is connected to the 6 V battery, draw the new
circuit. Indicate which plate of the capacitor is positive/negative and the direction of current flow,
Calculate the current in the circuit or explain why you can't if it's not possible. Either way, give some qualitative description of what
happens.
Hint: where is the resistance in a DC circuit without a resistor?
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Capacitors Explained - The basics how capacitors work working principle; Author: The Engineering Mindset;https://www.youtube.com/watch?v=X4EUwTwZ110;License: Standard YouTube License, CC-BY