Heating Ventilating and Air Conditioning: Analysis and Design
6th Edition
ISBN: 9780471470151
Author: Faye C. McQuiston, Jeffrey D. Spitler, Jerald D. Parker
Publisher: Wiley, John & Sons, Incorporated
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Chapter 5, Problem 5.26P
A heated building is built on a concrete slab with dimensions of
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Q2/ A composite wall is formed of a 2.5 cm copper plate, a 3.2 mm layer of
asbestos, and a 5 cm layer of fiberglass. The wall is subjected to an overall
temperature difference of 560 C. Calculate the heat flow per unit area
through the composite structure.
2. Calculate the heat loss for the structure described below. Use the indoor
design setpoint of 70°F.
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.
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.
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Hint: Utilize the Q=U*A*(ti-to) & Q = U'*P*(ti-to). Make sure to reference
the following tables and examples to help assist you solve this problem;
Table 5-5a, Table 5-8, Table 5-4a, Example 5-3, Eq. 5-23, and Fig 5-8.
Given:
i. Location: Des Moines, IA @ 99% winter OAT
ii. Walls: Table 5.7, Construction 2
iii. Floor: Concrete slab with 2-ft, R-5.4, vertical edge insulation
iv. Windows: Double-Insulating Glass; 1/4-in. air space; e = 0.6 on
surface 2, 3x4-ft, double hung, reinforced vinyl frame; three on
each side
v.
vi.
Roof-Ceiling: Same as Example 5.3, height of 8-ft
vii. House Plan: Single story, 36-ft x 64-ft
Doors: Wood, 1-3/4-in. panel doors with metal storm doors, three
each, 3x6.75-ft
Qwindows =
Qdoors=
Qwalls =
Qroof/ceiling=
Qfloor =
QTOTAL =
Btu/(hroft²0F)
Btu/h Heat Loss
Btu/h Heat Loss
Btu/h Heat Loss
Btu/h Heat Loss
Btu/h Heat Loss
[2] A reservoir of hot water kept at 380K is well insulated except for a copper rod with a
cross sectional area of 0.25 m? and a length of 0.50 meters. The rod is also well insulated
except for its ends and the other end is in a second well insulated reservoir of water held
at 280K.
a) Determine the rate of heat flow through the copper rod.
b) Calculate the temperature at the center of the rod (0.25 meters from either end).
Then extend the process to find the temperature at each point 0.1m along the rod.
c) Calculate the rate of entropy change at each end of the rod.
d) Using your answer for (c), show that the statements "Heat flows spontaneously from
high temperature to low temperature." and "Any spontaneous process causes the entropy
of the universe to increase." are logically equivalent for situations with heat flow.
e) Each reservoir of water holds 1 m of water. With a steady flow established, the power
fails so that the heating and cooling of the water ceases. What are the…
Chapter 5 Solutions
Heating Ventilating and Air Conditioning: Analysis and Design
Ch. 5 - Determine the thermal conductivity of 4 in. (100...Ch. 5 - Compute the unit conductance C for 512 in. (140...Ch. 5 - Compute the unit thermal resistance and the...Ch. 5 - What is the unit thermal resistance for an inside...Ch. 5 - Compute the thermal resistance per unit length for...Ch. 5 - Assuming that the blocks are not filled, compute...Ch. 5 - The partition of Problem 5-4 has still air on one...Ch. 5 - The pipe of Problem has water flowing inside with...Ch. 5 - Compute the overall thermal resistance of a wall...Ch. 5 - Compute the overall heat-transfer coefficient for...
Ch. 5 - Estimate what fraction of the heat transfer for a...Ch. 5 - Make a table similar to Table 5-4a showing...Ch. 5 - Estimate the unit thermal resistance for a...Ch. 5 - Refer to Problem 5-13, and estimate the unit...Ch. 5 - A ceiling space is formed by a large flat roof and...Ch. 5 - A wall is 20 ft (6.1 m) wide and 8 ft (2.4 m) high...Ch. 5 - Estimate the heat-transfer rate per square foot...Ch. 5 - A wall exactly like the one described in Table...Ch. 5 - Prob. 5.19PCh. 5 - Compute the overall heat-transfer coefficient for...Ch. 5 - Compute the overall heat transfer for a single...Ch. 5 - Determine the overall heattransfer coefficient for...Ch. 5 - A basement is 2020ft(66m) and 7 ft (2.13 m) below...Ch. 5 - Estimate the overall heat-transfer coefficient for...Ch. 5 - Rework Problem 5-23 assuming that the walls are...Ch. 5 - A heated building is built on a concrete slab with...Ch. 5 - A basement wall extends 6 ft (1.8 m) below grade...Ch. 5 - A 2440ft(7.312.2m) building has a full basement...Ch. 5 - The floor of the basement described in Problem...Ch. 5 - Assume that the ground temperature tg is 40 F (10...Ch. 5 - Use the temperatures given in Problem 5-30 and...Ch. 5 - A small office building is constructed with a...Ch. 5 - A 100 ft length of buried, uninsulated steel pipe...Ch. 5 - Estimate the heat loss from 100 m of buried...Ch. 5 - A large beverage cooler resembles a small building...Ch. 5 - Consider the wall section shown in Fig. 5-10. (a)...Ch. 5 - A building has floor plan dimensions of 3060ft....Ch. 5 - Compute the temperature of the metal roof deck of...Ch. 5 - Consider the wall section shown in Fig. -4a,...Ch. 5 - Consider the knee space shown in Fig. 5-11. The...Ch. 5 - Estimate the temperature in an unheated basement...
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- 1.3 A furnace wall is to be constructed of brick having standard dimensions of Two kinds of material are available. One has a maximum usable temperature of 1040°C and a thermal conductivity of 1.7 W/(m K), and the other has a maximum temperature limit of 870°C and a thermal conductivity of 0.85 W/(m K). The bricks have the same cost and are laid in any manner, but we wish to design the most economical wall for a furnace with a temperature of 1040°C on the hot side and 200°C on the cold side. If the maximum amount of heat transfer permissible is 950 , determine the most economical arrangement using the available bricks.arrow_forwardQ2/ Compute the peak heat gains and time for the East wall of a building at 32° latitude on 16 august. The wall consists (101.6mm Tile + Air Space). The wall is 3m by 6 m with 1 x 2 m window. If the indoor and outdoor design condition are 23°C & 29.4°C and overall heat transfer of the window is 0.00591 KW/m2.C with SC=0.50arrow_forwardQ1. Double glazed window is made of 2 glass panes of 6 mm thick each with an air gap of 6 mm between them. Assuming that the air layer is stagnant and only conduction is involved, determine the thermal resistance and overall heat transfer coefficient. The inside is exposed to convection with h - 15 W/m?. K and the outside to 9 W/m'. K. Compare the values with that of a single glass of 12 mm thickness. The conductivity of the glass - 1.4 W/m. K and that for air is 0.025 W/m. K. h, = 15 Wim'k Glass Air gap Giass 14 Wmk =0.025 WimK h Wim'k 6 mm Q2. A 2m long, 0.3cm diameter electrical wire extends across a room at 15°C. Heat is generated in the wire as a result of resistance heating, and the surface temperature of the wire is measured to be 152°C in steady operation. Also, the voltage drop and electric current through the wire are measured to be 60 V and 1.5 A, respectively. Disregarding any heat transfer by radiation, determine the convection heat transfer coefficient for heat transfer…arrow_forward
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- 2. Calculate Passive House's energy demand. a, Calculate window U-value based on given data in figure. 0.117m 0.117m 0.134m C₂ Utotal Wglass-0.996m = 1.229m glass Uglass = 0.6- glass W window - 123m W m².c 0.117m 1.48m nwindow W m² °C Uframe = 1.6- Area₁ U₁ + Area2 U₂... + Area, * U₁ Area total b. With the calculated U value for the windows find out how much power needed to maintain 20°C in a home with outside of 0°C based on the following: the house having a square footprint 17 m by 17 m, walls 2.5 m high (Uwalls = 0.152 each of the four walls hosting two windows, and each window having an area of 2 m². The entry door area is 2.5 m² (Udoor = 0.65- ). What are the heat loss rates for the installed windows, the door, the walls, the ceiling, and the floor? What is the overall heat loss rate of the home? m². C 1. What do these calculated heat loss rate values mean? 2. What is the definition of the passive house? 3. What does the U-value represent? Use its unit as a hint and describe it…arrow_forwardThe thermal conductivities of wood is kwood = 0.1W/(m°C)and air is kair = 0.0234W/(m°C). Part A If the temperature of the room is 20°C and outside is 10°C, find the rate of heat flow for a wall of wood with area = 10 m² and thickness of 5cm. O 60 W O 304 W O 34 W O 200 W O 100 W Submit Request Answer Part B The wall of wood with thickness of 5cm is now replaced with two layers of wood and a gap of air between the wood. Each layer of wood has a 2.5cm thickness and the gap is 1cm. The rate of heat flow will, decreases. increases. stay the same. Submit Request Answer Part C The temperature in the air gap will be, O 20°C, between 10°C and 20°C, O 10°C,arrow_forward1) "Two-by-four" wood studs have actual dimensions of 4. 13 x 9.21 cm and a thermal conductivity of 0.1 W/m. °C. A typical wall for a house is constructed as shown below. Calculate: a) heat transfer rate through the wall, b) temperature of inside wall, outside wall, and insulation material; and (c) temperature drop across common brick. Disregard any contact resistances at interfaces. Outside air convection, h = 15 W/m?. °C Common brick, k= 0.69 8 cm 1.9 cm, k = 0.96 Gypsum sheath 1.9 cm. k= 048 40.6 cm Insulation, k = 0.04 2 x 4 studs Inside air convection, h= 7.5 W/m²• Carrow_forward
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