Concept explainers
(1)
The transformation product after quenching and then after cool at room temperature.
(1)
Explanation of Solution
Introduction:
The process of rapid cooling of a metal in water, or air or oil in order to alter the
(a)
The steel has eutectoid composition that is initially equilibrated at
(b)
When the product formed in part (a) is cooled to room temperature, then the transformation product that is formed will be the
Conclusion:
Thus, the product formed after quenching is
(2)
The transformation product after quenching and then after cool at room temperature.
(2)
Explanation of Solution
Introduction:
The process of rapid cooling of a metal in water, or air or oil in order to alter the mechanical properties of the metal is called quenching. The process of quenching helps in the prevention of undesired low-temperature processes like phase transformation. Under normal conditions quenching is performed for few seconds.
(a)
The steel has eutectoid composition that is initially equilibrated at
(b)
When the product formed in part (a) is cooled to room temperature, then the transformation product that is formed will be the
Conclusion:
Thus, the product formed after quenching is
(3)
The transformation product after quenching and then after cool at room temperature.
(3)
Explanation of Solution
Introduction:
The process of rapid cooling of a metal in water, or air or oil in order to alter the mechanical properties of the metal is called quenching. The process of quenching helps in the prevention of undesired low-temperature processes like phase transformation. Under normal conditions quenching is performed for few seconds.
(a)
The steel has eutectoid composition that is initially equilibrated at
(b)
When the product formed in part (a) is cooled to room temperature, then the transformation product that is formed will be the
Conclusion:
Thus, the product formed after quenching is
(4)
The transformation product after quenching and then after cool at room temperature.
(4)
Explanation of Solution
Introduction:
The process of rapid cooling of a metal in water, or air or oil in order to alter the mechanical properties of the metal is called quenching. The process of quenching helps in the prevention of undesired low-temperature processes like phase transformation. Under normal conditions quenching is performed for few seconds.
(a)
The steel has eutectoid composition that is initially equilibrated at
(b)
When the product formed in part (a) is cooled to room temperature, then the transformation product that is formed will be the
Conclusion:
Thus, the product formed after quenching is
(5)
The transformation product after quenching and then after cool at room temperature.
(5)
Explanation of Solution
Introduction:
The process of rapid cooling of a metal in water, or air or oil in order to alter the mechanical properties of the metal is called quenching. The process of quenching helps in the prevention of undesired low-temperature processes like phase transformation. Under normal conditions quenching is performed for few seconds.
(a)
The steel has eutectoid composition that is initially equilibrated at
(b)
When the product formed in part (a) is cooled to room temperature, then the transformation product that is formed will be the
Conclusion:
Thus, the product formed after quenching is
(6)
The transformation product after quenching and then after cool at room temperature.
(6)
Explanation of Solution
Introduction:
The process of rapid cooling of a metal in water, or air or oil in order to alter the mechanical properties of the metal is called quenching. The process of quenching helps in the prevention of undesired low-temperature processes like phase transformation. Under normal conditions quenching is performed for few seconds.
(a)
The steel has eutectoid composition that is initially equilibrated at
(b)
When the product formed in part (a) is cooled to room temperature, then the transformation product that is formed will be the
Conclusion:
Thus, the product formed after quenching is
(7)
The transformation product after quenching and then after heating.
(7)
Explanation of Solution
Introduction:
The process of rapid cooling of a metal in water, or air or oil in order to alter the mechanical properties of the metal is called quenching. The process of quenching helps in the prevention of undesired low-temperature processes like phase transformation. Under normal conditions quenching is performed for few seconds.
(a)
The steel has eutectoid composition that is initially equilibrated at
(b)
When the product formed in part (a) is heated at the temperature of
Conclusion:
Thus, the product formed after quenching is
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Chapter 5 Solutions
Materials Science And Engineering Properties
- The following information is given for n-pentane at 1 atm:boiling point = 36.20°C ΔHvap (36.20°C) = 357.6 J/g melting point = − 129.7°C ΔHfus (−129.7°C) = 116.7 J/g specific heat gas = 1.650 J/g ⋅ °C specific heat liquid = 2.280 J/g ⋅ °C A 26.10-g sample of liquid n-pentane is initially at −51.40°C. If the sample is heated at constant pressure (P = 1 atm), how many kJ of energy are needed to raise the temperature of the sample to 65.30°C?arrow_forwardA sufficient amount of pure copper is(4 to be heated for casting a large plate in an open mold. The plate has dimensions: length = 20 in, width=D10 in, and thickness =3 in. Compute the amount of heat that must be added to the metal to heat it to a temperature of 21500F for pouring. Assume that the amount of metal heated will be 10% more than what is needed to fill the mold cavity. Properties of the metal are: density=0.324 Ibm/in3, melting point = 19810F, specific heat of the %3D metal=0.093Btu/lbm-F in the solid state and 0.090 Btu/lbm-F in the liquid * .state, and heat of fusion = 80 Btu/lbmarrow_forwardView Policies Current Attempt in Progress Using the Animated Figure 10.40, the isothermal transformation diagram for a 0.45 wt% C steel alloy, specify the nature of the final microstructure (in terms of the microconstituents present) of a small specimen that has been subjected to the following temperature treatments. In each case assume that the specimen begins at 845 °C and that it has been held at this temperature long enough to have achieved a complete and homogeneous austenitic structure. a) Rapidly cool to 700 degrees C, hold for 100,000 s, then quench to room temperature. b) Rapidly cool to 450 degrees C, hold for 10 s, then quench to room temperature. proeutectoid ferrite + pearlite proeutectoid ferrite + martensite proeutectoid ferrite + pearlite + martensite eT proeutectoid ferrite + pearlite + bainite + martensite all spheroidite Save all bainite Attempts: 0 of 5 used Submit Answer all martensite bainite + martensitearrow_forward
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Materials Science And Engineering PropertiesCivil EngineeringISBN:9781111988609Author:Charles GilmorePublisher:Cengage Learning