Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 5, Problem 5.3P
(a)
To determine
The phase present in Cu-Ni alloy.
(b)
To determine
Chemical composition of Cu-Ni alloy.
(c)
To determine
Atom fraction of each phase.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Calculate the unit cell edge length for an 57 wt% Ag- 43 wt% Pd alloy. All of the palladium is in solid solution, and the crystal structure for this alloy is FCC. Room temperature densities for Ag and Pd are 10.49 g/cm3 and 12.02 g/cm3, respectively, and their respective atomic weights are 107.87 g/mol and 106.4 g/mol. Report your answer in nanometers.
Need help with this question. Thank you :)
A niobium alloy is produced by introducing tungsten substitutional atoms in the BCC structure. The lattice parameter and density of the alloy is 0.3285 nm and 12.25 g/cm3, respectively. Calculate the fraction of tungsten alloys. (AW = 183.85 g/mol, ANb =92.91 g/mol).
Chapter 5 Solutions
Materials Science And Engineering Properties
Ch. 5 - Prob. 1CQCh. 5 - Prob. 2CQCh. 5 - Prob. 3CQCh. 5 - Prob. 4CQCh. 5 - Prob. 5CQCh. 5 - Prob. 6CQCh. 5 - Prob. 7CQCh. 5 - Prob. 8CQCh. 5 - Prob. 9CQCh. 5 - Prob. 10CQ
Ch. 5 - Prob. 11CQCh. 5 - Prob. 12CQCh. 5 - Prob. 13CQCh. 5 - Prob. 14CQCh. 5 - Prob. 15CQCh. 5 - Prob. 16CQCh. 5 - Prob. 17CQCh. 5 - Prob. 18CQCh. 5 - Prob. 19CQCh. 5 - Prob. 20CQCh. 5 - Prob. 21CQCh. 5 - Prob. 22CQCh. 5 - Prob. 23CQCh. 5 - Prob. 24CQCh. 5 - Prob. 25CQCh. 5 - Prob. 26CQCh. 5 - Prob. 27CQCh. 5 - Prob. 28CQCh. 5 - Prob. 29CQCh. 5 - Prob. 30CQCh. 5 - Prob. 31CQCh. 5 - Prob. 32CQCh. 5 - Prob. 33CQCh. 5 - Prob. 34CQCh. 5 - Prob. 35CQCh. 5 - Prob. 36CQCh. 5 - Prob. 1ETSQCh. 5 - Prob. 2ETSQCh. 5 - Prob. 3ETSQCh. 5 - Prob. 4ETSQCh. 5 - Prob. 5ETSQCh. 5 - Prob. 6ETSQCh. 5 - Prob. 7ETSQCh. 5 - Prob. 8ETSQCh. 5 - Prob. 9ETSQCh. 5 - Prob. 10ETSQCh. 5 - Prob. 11ETSQCh. 5 - Prob. 12ETSQCh. 5 - Prob. 1DRQCh. 5 - Prob. 2DRQCh. 5 - Prob. 3DRQCh. 5 - Prob. 5.1PCh. 5 - Prob. 5.2PCh. 5 - Prob. 5.3PCh. 5 - Prob. 5.4PCh. 5 - Prob. 5.5PCh. 5 - Prob. 5.6PCh. 5 - Prob. 5.7PCh. 5 - Prob. 5.8PCh. 5 - Prob. 5.9PCh. 5 - Prob. 5.10PCh. 5 - Prob. 5.11PCh. 5 - Prob. 5.12PCh. 5 - Prob. 5.13PCh. 5 - Prob. 5.14PCh. 5 - Prob. 5.15PCh. 5 - Prob. 5.16PCh. 5 - Prob. 5.17PCh. 5 - Prob. 5.18PCh. 5 - Prob. 5.19P
Knowledge Booster
Similar questions
- Alumina (A12O3) is a(n) _________ material.arrow_forwardThe unit cell for MgFe2O4 (MgO-Fe2O3) has cubic symmetry with a unit cell edge length of 0.836 nm. If the density of this material is 4.52 g/cm3, compute its atomic packing factor. For this computation, you will need to use the ionic radii listed in Table Ionic Radii for Several Cations and Anions for a Coordination Number of 6.arrow_forwardFor alloys of two hypothetical metals A and B, there exist an a, A-rich phase and a ß, B-rich phase. From the mass fractions of both phases for two different alloys (given below), which are at the same temperature, determine the composition of the phase boundary (or solubility limit) for the following: Fraction Fraction Alloy Composition a Phase B Phase 60 wt% A - 40 wt% B 0.59 0.41 30 wt% A - 70 wt% B 0.13 0.87 (a) a phase wt% A (b) B phase wt% Aarrow_forward
- 3.11 Each of the following statements describes a silicate mineral or mineral group. In each case, provide the appropriate name. a- The most common member of the amphibole group. b- The most common non ferromagnesian member of the mica family. c- The only silicate mineral made entirely of silicon and oxygen. d- A high-temperature silicate with a name that is based on its color. e-Characterized by striations. f- Originates as a product of chemical weathering.arrow_forwardThe following information is given for cadmium at 1atm: boiling point = 765 °C Hvap(765 °C) = 100 kJ/mol melting point = 321 °C Hfus(321 °C) = 6.11 kJ/mol specific heat solid= 0.230 J/g°C specific heat liquid = 0.264 J/g°C __________kJ are required to melt a 31.0 g sample of solid cadmium, Cd, at its normal melting point.arrow_forwardA magnesium-lead alloy of mass 6.4 kg consists of a solid a phase that has a composition just slightly below the solubility limit at 300°C (570°F). The magnesium-lead phase diagram is shown in Animated Figure 9.20. (a) What mass of lead is in the alloy? i kg (b) If the alloy is heated to 400°C (750°F), how much more lead may be dissolved in the a phase without exceeding the solubility limit of this phase? kgarrow_forward
- 1. A 65 wt% Ni -35 wt% Cu alloy is heated to a temperature within the a + liquid phase region. If the composition of the a phase is 70 wt % Ni, determine i. The temperature of the alloy ii. The composition of the liquid phase iii. The mass fraction of both phases Composition (at% Ni) 20 40 60 80 100 1600 H 2800 1500 Liquid 1453°C 2600 1400 Solidus line Liquidus line 2400 1300 a +L 1200 2200 1100 A 2000 1085°C 1000 20 40 60 80 100 (Cu) Composition (wt% Ni) (Ni) Temperature (°C) Temperature (F)arrow_forwardWhich of the following alloys would form a complete substitutional solid solution? Metal 1 is BCC, metal 2 is FCC, and atomic radíus difference is 12%. Metal 1 is FCC, metal 2 is FCC, and atomic radius difference is 12%. Metal 1 is FCC, metal 2 is FCC, and atomic radíus difference is 15%. Metal 1 is HCP, metal 2 is FCC, and atomic radius differene is less than 15%. Metal 1 is BCC, metal 2 is BCC, and atomic radius difference is at least 15%.arrow_forward18 Material Science and Engineeringarrow_forward
- Which one of the following is NOT a way minerals form? O Compression of organic material on the surface Precipitation from solution Crystallization from magma Biological precipitation by organismsarrow_forwardCeramics are referred to as refractory materials. These are known to withstand high amounts of temperature. Explain the reason why ceramics has this particular property.arrow_forwardView Policies Current Attempt in Progress Using the Animated Figure 10.40, the isothermal transformation diagram for a 0.45 wt% C steel alloy, specify the nature of the final microstructure (in terms of the microconstituents present) of a small specimen that has been subjected to the following temperature treatments. In each case assume that the specimen begins at 845 °C and that it has been held at this temperature long enough to have achieved a complete and homogeneous austenitic structure. a) Rapidly cool to 700 degrees C, hold for 100,000 s, then quench to room temperature. b) Rapidly cool to 450 degrees C, hold for 10 s, then quench to room temperature. proeutectoid ferrite + pearlite proeutectoid ferrite + martensite proeutectoid ferrite + pearlite + martensite eT proeutectoid ferrite + pearlite + bainite + martensite all spheroidite Save all bainite Attempts: 0 of 5 used Submit Answer all martensite bainite + martensitearrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Materials Science And Engineering PropertiesCivil EngineeringISBN:9781111988609Author:Charles GilmorePublisher:Cengage LearningConstruction Materials, Methods and Techniques (M...Civil EngineeringISBN:9781305086272Author:William P. Spence, Eva KultermannPublisher:Cengage Learning
Materials Science And Engineering Properties
Civil Engineering
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Cengage Learning
Construction Materials, Methods and Techniques (M...
Civil Engineering
ISBN:9781305086272
Author:William P. Spence, Eva Kultermann
Publisher:Cengage Learning