Chemistry Atoms First2e
2nd Edition
ISBN: 9781947172647
Author: OpenStax
Publisher: OpenStax College
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Chapter 5, Problem 3E
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Chapter 5 Solutions
Chemistry Atoms First2e
Ch. 5 - Explain how σ and bonds are similar and how they...Ch. 5 - Use valence bond theory to explain the bonding in...Ch. 5 - Use valence bond theory to explain the bonding in...Ch. 5 - How many and bonds are present in the molecule...Ch. 5 - A friend tell you N2 has three bonds due to...Ch. 5 - Draw the Lewis Structures for CO2andCO , and...Ch. 5 - Why is the concept of hybridization required in...Ch. 5 - Give the shape that describes each hybrid orbital...Ch. 5 - Explain why a carbon atom cannot from five bonds...Ch. 5 - What is the hybridization of the central atom in...
Ch. 5 - A molecule with the formula AB3 could have one of...Ch. 5 - Methionine, CH3SCH2CH2CH(NH2)CO2H, is an amino...Ch. 5 - Sulfuric acid is manufactured by a series of...Ch. 5 - Two important industrial chemicals,...Ch. 5 - Analysis of a compound indicates that it contains...Ch. 5 - Consider nitrous acid, HNO2(HONO). (a) Write a...Ch. 5 - Strike-anywhere matches contain a layer of KC1O3...Ch. 5 - Identify the hybridization of each carbon atom in...Ch. 5 - Write Lewis structures for NF3andPF5 . On the...Ch. 5 - In addition to NF3, two other fluoro derivatives...Ch. 5 - The bond energy of a C-C single bond averages...Ch. 5 - For the carbonate ion, CO32 -, draw all of the...Ch. 5 - A useful solvent that will dissolve salts as well...Ch. 5 - For the molecule allene, H2C=C=CH2, give the...Ch. 5 - Identify the hybridization of the central atom in...Ch. 5 - Describe the molecular geometry and hybridization...Ch. 5 - For each of the following molecules, indicate the...Ch. 5 - For each of the following structures, determine...Ch. 5 - Draw the orbital diagram for carbon in CO2 showing...Ch. 5 - Sketch the distribution of electron density in the...Ch. 5 - How are the following similar, and how do they...Ch. 5 - If molecular orbitals are created by combining...Ch. 5 - Can a molecule with an odd number of electrons...Ch. 5 - Can a molecule with an even number of electrons...Ch. 5 - Why are bonding molecular orbital lower in energy...Ch. 5 - Calculate the bond order for an ion with this...Ch. 5 - Explain why an electron in the bonding molecular...Ch. 5 - Predict the valence electron molecular orbital...Ch. 5 - Determine the bond order of each member of the...Ch. 5 - For the first ionizations energy for an N2...Ch. 5 - Compare the atomic and molecular orbitaI diagrams...Ch. 5 - Which of the period 2 homonuclear diatomic...Ch. 5 - A friend tells you that the 2s orbital for...Ch. 5 - True or false: Boron contains 2s22p1 valence...Ch. 5 - What charge would be needed on F2 to generate an...Ch. 5 - Predict whether the MO diagram for S2 would show...Ch. 5 - Explain why N22+ is diamagnetic, while O24+, which...Ch. 5 - Using the MO diagrams, predict the bond order for...
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- a Nitrogen trifluoride, NF3, is a relatively unreactive, colorless gas. How would you describe the bonding in the NF3 molecule in terms of valence bond theory? Use hybrid orbitals. b Silicon tetrafluoride, SiF4, is a colorless gas formed when hydrofluoric acid attacks silica (SiO2) or glass. Describe the bonding in the SiF4 molecule, using valence bond theory.arrow_forwardThe sulfamate ion, H2NSO3, can be thought of as having been formed from the amide ion, NH2, and sulphur trioxide, SO3. (a) What are the electron-pair and molecular geometries or the amide ion and or SO3? What are the hybridizations of the N and S atoms, respectively? (b) Sketch a structure for the sulfamate ion, and estimate the bond angles. (c) What changes in hybridization do you expect for N and S in the course of the reaction NH2 + SO3 H2NSO3? (d) Is SO3 the donor of an electron pair or the acceptor of an electron pair in the reaction with amide ion? Does the electrostatic potential map shown below confirm your prediction?arrow_forwardIdentify the hybrid orbitals used by boron in BCl3 and in BCl4, the ion formed from the reaction of BCl3 and Cl. Explain your choices.arrow_forward
- It is possible to write a simple Lewis structure for the SO42- ion, involving only single bonds, which follows the octet rule. However, Linus Pauling and others have suggested an alternative structure, involving double bonds, in which the sulfur atom is surrounded by six electron pairs. (a) Draw the two Lewis structures. (b) What geometries are predicted for the two structures? (c) What is the hybridization of sulfur in each case? (d) What are the formal charges of the atoms in the two structures?arrow_forwardDescribe the hybridization around the central atom and the bonding in SCl2 and OCS.arrow_forwardUse valence bond theory to describe the bonding in methylamine. CH3NH2.arrow_forward
- Draw the molecular orbital diagram for C2 and O2. Indicate the bond order for each, and whether the molecules are paramagnetic or diamagnetic.arrow_forwardBased on molecular orbital theory, explain why removing one electron from O2 strengthens its bonding whereas removal of one electron from N2 weakens it.arrow_forwardWhat is the molecular geometry of SO2?arrow_forward
- Use the molecular orbital model to fully describe the bonding in O2+, O2, O2-, and O22-.Determine which of the following statements are true and which are false. True or false? : Bond length increases with increasing bond order while bond energy decreases.The number of unpaired electrons in O2- and O2 is, respectively, 1 and 2. The electron configuration of O2 is (σ2s)2(σ2s*)2(σ2p)2(π2p)4(π2p*)1. The electron configuration of O2- is (σ2s)2(σ2s*)2(σ2p)2(π2p)4(π2p*)3. The bond order in O2- and O22- is, respectively, 2.5 and 1. The bond lengths increase in the order: O22- < O2- < O2 < O2+.arrow_forwardDetermine the shape (geometry) of PCl3 and then decide on the appropriate hybridization of phosphorus in this molecule. (Phosphorus is the central atom.)arrow_forwardUse the molecular orbital model to fully describe the bonding in O₂+, O₂, O₂™, and 0₂²- Determine which of the following statements are true and which are false. The electron configuration of O₂ is (025)²(0₂s*)²(02p)²(¹2)4(¹²p*)². 2- The bond order in O₂¯ and O₂²- is, respectively, 2.5 and 1. The number of unpaired electrons in O₂ and O₂ is, respectively, 1 and 0. The electron configuration of O₂¯ is (02)²(02s*)²(0₂p)²(12p)4(¹²µ*)³. The bond energies increase in the order: 0₂²- < 0₂¯ < 0₂ < 0₂¹. Bond length increases with increasing bond order while bond energy decreases.arrow_forward
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