College Physics, Volume 1
2nd Edition
ISBN: 9781133710271
Author: Giordano
Publisher: Cengage
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Chapter 5, Problem 38P
To determine
The ratio of your apparent weights at the equator to the poles.
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Chapter 5 Solutions
College Physics, Volume 1
Ch. 5.1 - Velocity and Acceleration in Circular Motion...Ch. 5.1 - Prob. 5.2CCCh. 5.2 - Prob. 5.3CCCh. 5.3 - Prob. 5.5CCCh. 5.4 - Prob. 5.6CCCh. 5.4 - Prob. 5.7CCCh. 5 - Prob. 1QCh. 5 - Prob. 2QCh. 5 - Prob. 3QCh. 5 - Consider the Cavendish experiment in Figure 5.22....
Ch. 5 - Prob. 5QCh. 5 - Prob. 6QCh. 5 - Prob. 7QCh. 5 - What force makes it possible for a car to move...Ch. 5 - Prob. 9QCh. 5 - Prob. 10QCh. 5 - Prob. 11QCh. 5 - Prob. 12QCh. 5 - Prob. 13QCh. 5 - Prob. 14QCh. 5 - Prob. 15QCh. 5 - Prob. 16QCh. 5 - Prob. 17QCh. 5 - Prob. 18QCh. 5 - Plutos mass. In 1978, it was discovered that Pluto...Ch. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Prob. 8PCh. 5 - Prob. 9PCh. 5 - Prob. 10PCh. 5 - A compact disc spins at 2.5 revolutions per...Ch. 5 - Prob. 12PCh. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - Consider the motion of a rock tied to a string of...Ch. 5 - Prob. 17PCh. 5 - Prob. 18PCh. 5 - Prob. 19PCh. 5 - Prob. 20PCh. 5 - Prob. 21PCh. 5 - Prob. 23PCh. 5 - Prob. 24PCh. 5 - Prob. 25PCh. 5 - Prob. 26PCh. 5 - Prob. 27PCh. 5 - Prob. 29PCh. 5 - Consider a Ferris wheel in which the chairs hang...Ch. 5 - Prob. 31PCh. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 35PCh. 5 - Prob. 36PCh. 5 - Prob. 37PCh. 5 - Prob. 38PCh. 5 - Prob. 39PCh. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Prob. 46PCh. 5 - Prob. 47PCh. 5 - Prob. 48PCh. 5 - Prob. 50PCh. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53PCh. 5 - Prob. 54PCh. 5 - Prob. 55PCh. 5 - Prob. 56PCh. 5 - Prob. 57PCh. 5 - Prob. 58PCh. 5 - Prob. 59PCh. 5 - Prob. 60PCh. 5 - Prob. 61PCh. 5 - Prob. 62PCh. 5 - Prob. 63PCh. 5 - Prob. 64PCh. 5 - Prob. 65PCh. 5 - Prob. 66PCh. 5 - Prob. 67PCh. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Prob. 71PCh. 5 - Prob. 72PCh. 5 - A rock of mass m is tied to a string of length L...Ch. 5 - Prob. 74PCh. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77P
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- The mass of the Earth is approximately 5.98 1024 kg, and the mass of the Moon is approximately 7.35 1022 kg. The Moon and the Earth are separated by about 3.84 108 m. a. What is the magnitude of the gravitational force that the Moon exerts on the Earth? b. If Serena is on the Moon and her mass is 25 kg, what is the magnitude of the gravitational force on Serena due to the Moon? The radius of the Moon is approximately 1.74 106 m.arrow_forward(a) Find the magnitude of the gravitational force between a planet with mass 7.50 1024 kg and its moon, with mass 2.70 1022 kg, if the average distance between their centers is 2.80 108 m. (b) What is the acceleration of the moon towards the planet? (c) What is the acceleration of the planet towards the moon?arrow_forwardSuppose the gravitational acceleration at the surface of a certain moon A of Jupiter is 2 m/s2. Moon B has twice the mass and twice the radius of moon A. What is the gravitational acceleration at its surface? Neglect the gravitational acceleration due to Jupiter, (a) 8 m/s2 (b) 4 m/s2 (c) 2 m/s2 (d) 1 m/s2 (e) 0.5 m/s2arrow_forward
- In Example 2.6, we considered a simple model for a rocket launched from the surface of the Earth. A better expression for the rockets position measured from the center of the Earth is given by y(t)=(R3/2+3g2Rt)2/3j where R is the radius of the Earth (6.38 106 m) and g is the constant acceleration of an object in free fall near the Earths surface (9.81 m/s2). a. Derive expressions for vy(t) and ay(t). b. Plot y(t), vy(t), and ay(t). (A spreadsheet program would be helpful.) c. When will the rocket be at y=4R? d. What are vy and ay when y=4R?arrow_forwardEvery few months, memes circulate claiming that certain alignments of the planets with the Earth will result in a change in the gravitational force you feel. Usually these memes state that the alignment will counteract Earth's gravity slightly so you will feel less of a gravitational pull towards the Earth. Can this ever happen? Let's look at the numbers. What is the gravitational force (in N) of the Earth on you (MĚ = 5.97 × 1024 kg, R₁ = 6380 km)? Say your mass is 64 kg. (Enter the magnitude.) What is the gravitational force (in N) of Jupiter on you when it is closest to Earth (M₁ = 1.90 × 1027 kg, R₁ = 5.88 × 108 km)? (Enter the magnitude.) By what factor would the mass of Jupiter need to increase to be equal to the gravitational force you feel from the Earth? Part 1 of 5 The gravitational force between two masses is given by -GMm r² where G = 6.67 x 10-11 m³/s²/kg. FgE Part 2 of 5 We can use this expression to determine the magnitude of the gravitational force you feel while on the…arrow_forwardNewton's Law of Gravitation states that two bodies with masses M and N attract each other with a force MN F = G- p2 where r is the distance between the bodies and G is the gravitational constant. Assume that Earth's mass is 5.98 × 104 kg and is concentrated at its center. Moreover, take the radius of the Earth to be 6.37 x 10° m and G = 6.67 x 10-1" N · m²/kg². With this information, find the work required to propel a 1000-kg satellite out of Earth's gravitational field. Work =arrow_forward
- The International Space Station (ISS) orbits the Earth in a nearly circular orbit that is 345 km above the Earths surface. (a) How many hours does it take for the ISS to make each orbit? (b) Some of the experiments performed by astronauts in the ISS involve the effects of “weightlessness” on objects. What gravitational force does the Earth exert on a 10 kg object in the ISS? Express your answer in newtons and as a fraction of the force that Earth would exert on the object at Earth’s surface. (c) Considering your answer in part 2(b) above, how can an object be considered weightless in the ISS? 3. Two planets, both of mass m, are separated by a distance d. Their relative velocity is negligible, and there is an inertial frame in which both planets are essentially at rest. The gravitational potential u(r) at the position r in the presence of the two planets, located at R1 and R2, is given as u(r) = − Gm R1 −r − Gm R2 −r . This problem takes place far out in space and there are no other…arrow_forwardFor this problem, assume that the earth is a perfect sphere. Also, assume that if your mass is m, then the earth exerts a gravitational force on you of magnitude mg, where g = 9.8 m/s2 at all points of the earth's surface. a) Your mass is m = will the scale read? (Thanks to the Third Law, this is the same as asking for the normal force exerted on you by the scale.) b) Next you go to the Equator and stand on a scale. What does it read? The radius of the earth is 6.4 × 106 m. c) Suppose the earth were rotating so quickly that objects became “weightless" at the equator. How long would the day be? 50 kg. If you are standing on a scale at the North Pole, whatarrow_forwardEvery few months, memes circulate claiming that certain alignments of the planets with the Earth will result in a change in the gravitational force you feel. Usually, these memes state that the alignment will counteract Earth's gravity slightly so you will feel less of a gravitational pull towards the Earth. Can this ever happen? Let's look at the numbers. What is the gravitational force (in N) of the Earth on you (ME = 5.97 ✕ 1024 kg, RE = 6380 km)? Say your mass is 68 kg. (Enter the magnitude.) What is the gravitational force (in N) of Jupiter on you when it is closest to Earth (MJ = 1.90 ✕ 1027 kg, RJE = 5.88 ✕ 108 km)? (Enter the magnitude.) By what factor would the mass of Jupiter need to increase to be equal to the gravitational force you feel from the Earth? Part 1 of 5 The gravitational force between two masses is given by Fg = −GMm r2 where G = 6.67 ✕ 10−11 m3/s2/kg. We can use this expression to determine the magnitude of the gravitational force you feel…arrow_forward
- 12. Which of the following statements is not correct? a. The weight of a body on Earth is a measure of the gravitational attraction of Earth on that Gravitational force is a scalar quantity because it has magnitude only. The gravitational mass of a body depends on its surroundings and altitude. d Weight and force have both magnitude and direction. Apod 13. Which of the following statements about gravitational force, F, is not correct? The gravitational force between two objects depends on their separation. b. Gravitational force is an attractive force only, it is never repulsive. C. Gravitational forces always exist in pairs of equal magnitude. P. Gravitational force is the strongest of the fundamental forces,arrow_forwardObjects with masses of 180 kg and 343 kg are separated by 0.465 m. A 67.6 kg mass is placed midway between them. 343 kg 180 kg 67.6 kg 0.465 m - Find the magnitude of the net gravitational force exerted by the two larger masses on the 67.6 kg mass. The value of the universal gravi- tational constant is 6.672 x 10-¹1 N. m²/kg². Answer in units of N.arrow_forwardthe ratio between gravity on the moon's surface and the acceleration of gravity on the earth's surface is about 1:6. if an object weighs 100N on the earth's surface, then how far is the object from the center of the earth so that its attraction to the earth is the same as its weight on the surface right? the average radius of the earth re= 6.371kmarrow_forward
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