Every few months, memes circulate claiming that certain alignments of the planets with the Earth will result in a change in the gravitational force you feel. Usually these memes state that the alignment willcounteract Earth's gravity slightly so you will feel less of a gravitational pull towards the Earth.Can this ever happen? Let's look at the numbers.What is the gravitational force (in N) of the Earth on you (MĚ = 5.97 × 1024 kg, R₁ = 6380 km)? Say your mass is 64 kg. (Enter the magnitude.)What is the gravitational force (in N) of Jupiter on you when it is closest to Earth (M₁ = 1.90 × 1027 kg, R₁ = 5.88 × 108 km)? (Enter the magnitude.)By what factor would the mass of Jupiter need to increase to be equal to the gravitational force you feel from the Earth?Part 1 of 5The gravitational force between two masses is given by-GMmr²where G = 6.67 x 10-11 m³/s²/kg.FgEPart 2 of 5We can use this expression to determine the magnitude of the gravitational force you feel while on the surface of the Earth.(6.67 x 10-11 m³/s²/kg)(ME)(64 kg)FgE=g==(RE)²8500000000 XHow does the gravitational force depend on the mass and distance? Check your calculations. N

Every few months, memes circulate claiming that certain alignments of the planets with the Earth will result in a change in the gravitational force you feel. Usually these memes state that the alignment will counteract Earth's gravity slightly so you will feel less of a gravitational pull towards the Earth. Can this ever happen? Let's look at the numbers. What is the gravitational force (in N) of the Earth on you (ME = 5.97 x 1024 kg, RE = 6380 km)? Say your mass is 64 kg. (Enter the magnitude.) What is the gravitational force (in N) of Jupiter on you when it is closest to Earth (M₁ = 1.90 x 1027 kg, R₁E = 5.88 x 108 km)? (Enter the magnitude.) By what factor would the mass of Jupiter need to increase to be equal to the gravitational force you feel from the Earth? Part 1 of 5 The gravitational force between two masses is given by -GMm where G = 6.67 x 10-11 m³/s²/kg. Part 2 of 5 We can use this expression to determine the magnitude of the gravitational force you feel while on the surface of the Earth. (6.67 x 10-11 m³/s²/kg)(ME)(64 kg) FgE = FgE (RE)² = 8500000000 x How does the gravitational force depend on the mass and distance? Check your calculations. N

Every few months, memes circulate claiming that certain alignments of the planets with the Earth will result in a change in the gravitational force you feel. Usually these memes state that the alignment will counteract Earth's gravity slightly so you will feel less of a gravitational pull towards the Earth. Can this ever happen? Let's look at the numbers. What is the gravitational force (in N) of the Earth on you (ME = 5.97 x 1024 kg, RE = 6380 km)? Say your mass is 64 kg. (Enter the magnitude.) What is the gravitational force (in N) of Jupiter on you when it is closest to Earth (M₁ = 1.90 x 1027 kg, R₁E = 5.88 x 108 km)? (Enter the magnitude.) By what factor would the mass of Jupiter need to increase to be equal to the gravitational force you feel from the Earth? Part 1 of 5 The gravitational force between two masses is given by -GMm where G = 6.67 x 10-11 m³/s²/kg. Part 2 of 5 We can use this expression to determine the magnitude of the gravitational force you feel while on the surface of the Earth. (6.67 x 10-11 m³/s²/kg)(ME)(64 kg) FgE = FgE (RE)² = 8500000000 x How does the gravitational force depend on the mass and distance? Check your calculations. N

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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The Lunar reconnaissance orbiter (LRO) is currently in orbit around the moon on an exploration mission to map its surface. If it has a mass of 1820 kg and is orbiting at an elevation of 65.0 km from the surface, what is the gravitational force acting on the LRO due to the moon? The moon has a mass of 7.348 x 1022 kg and a radius of 1738 km. {G = 6.674 x 10-11 N m2/kg?} r = 1,803 km 1738 km I m, Norbiter = 1,820 kg mmoon 7.348 × 102² kg 65.0 km
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Scientists want to place a 4 × 103 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 2.4 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem: mmars = 6.4191 x 1023 kgrmars = 3.397 x 106 mG = 6.67428 x 10-11 N-m2/kg2 1.)What is the force of attraction between Mars and the satellite? 2.)What speed should the satellite have to be in a perfectly circular orbit? 3.)How much time does it take the satellite to complete one revolution?
If you weigh 685 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 18.0 km ? Take the mass of the sun to be ms = 1.99×1030 kg , the gravitational constant to be G = 6.67×10−11 N⋅m2/kg2 , and the acceleration due to gravity at the earth's surface to be g = 9.810 m/s2 . Express your weight wstar in newtons.
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During a solar eclipse, the Moon is positioned directly between Earth and the Sun. The masses of the Sun, Earth, and the Moon are 1.99 × 10³0 kg, 5.98 × 1024 kg, and 7.36 × 1022 kg, respectively. The Moon's mean distance from Earth is 3.84 × 108 m, and Earth's mean distance from the Sun is 1.50 × 10¹¹ m. The gravitational constant is G = 6.67 × 10-¹1 N-m²/kg². Find the magnitude F of the net gravitational force acting on the Moon during the solar eclipse due to both Earth and the Sun. F = What is the direction of this force? toward Earth toward Venus toward the Sun elsewhere N
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