College Physics, Volume 1
2nd Edition
ISBN: 9781133710271
Author: Giordano
Publisher: Cengage
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Chapter 5, Problem 50P
To determine
The period of the orbit of the asteroid.
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orbit, measured from the center of the planet is R = 2.2 × 107 m. The mass of the planet is M = 6.4 x
1024 kg.
Problem 3: A satellite is orbiting around a planet in a circular orbit. The radius of the
The orbit of the moon around the earth is approximately circular, with a mean radius of 3.85 x 108 m. It takes 27.3 days for the moon to complete one revolution around the earth. Find the average orbital speed of the moon.
A satellite is orbiting around a planet in a circular orbit. The radius of the orbit, measured from the center of the planet is R = 1.4 × 107 m. The mass of the planet is M = 4.4 × 1024 kg.
Express the magnitude of the gravitational force F in terms of M, R, the gravitational constant G, and the mass m of the satellite.
F =
Express the magnitude of the centripetal acceleration ac of the satellite in terms of the speed of the satellite v, and R.
ac =
Express the speed v in terms of G, M and R.
v =
Calculate the numerical value of v, in m/s.
v =
Chapter 5 Solutions
College Physics, Volume 1
Ch. 5.1 - Velocity and Acceleration in Circular Motion...Ch. 5.1 - Prob. 5.2CCCh. 5.2 - Prob. 5.3CCCh. 5.3 - Prob. 5.5CCCh. 5.4 - Prob. 5.6CCCh. 5.4 - Prob. 5.7CCCh. 5 - Prob. 1QCh. 5 - Prob. 2QCh. 5 - Prob. 3QCh. 5 - Consider the Cavendish experiment in Figure 5.22....
Ch. 5 - Prob. 5QCh. 5 - Prob. 6QCh. 5 - Prob. 7QCh. 5 - What force makes it possible for a car to move...Ch. 5 - Prob. 9QCh. 5 - Prob. 10QCh. 5 - Prob. 11QCh. 5 - Prob. 12QCh. 5 - Prob. 13QCh. 5 - Prob. 14QCh. 5 - Prob. 15QCh. 5 - Prob. 16QCh. 5 - Prob. 17QCh. 5 - Prob. 18QCh. 5 - Plutos mass. In 1978, it was discovered that Pluto...Ch. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Prob. 8PCh. 5 - Prob. 9PCh. 5 - Prob. 10PCh. 5 - A compact disc spins at 2.5 revolutions per...Ch. 5 - Prob. 12PCh. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - Consider the motion of a rock tied to a string of...Ch. 5 - Prob. 17PCh. 5 - Prob. 18PCh. 5 - Prob. 19PCh. 5 - Prob. 20PCh. 5 - Prob. 21PCh. 5 - Prob. 23PCh. 5 - Prob. 24PCh. 5 - Prob. 25PCh. 5 - Prob. 26PCh. 5 - Prob. 27PCh. 5 - Prob. 29PCh. 5 - Consider a Ferris wheel in which the chairs hang...Ch. 5 - Prob. 31PCh. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 35PCh. 5 - Prob. 36PCh. 5 - Prob. 37PCh. 5 - Prob. 38PCh. 5 - Prob. 39PCh. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Prob. 46PCh. 5 - Prob. 47PCh. 5 - Prob. 48PCh. 5 - Prob. 50PCh. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53PCh. 5 - Prob. 54PCh. 5 - Prob. 55PCh. 5 - Prob. 56PCh. 5 - Prob. 57PCh. 5 - Prob. 58PCh. 5 - Prob. 59PCh. 5 - Prob. 60PCh. 5 - Prob. 61PCh. 5 - Prob. 62PCh. 5 - Prob. 63PCh. 5 - Prob. 64PCh. 5 - Prob. 65PCh. 5 - Prob. 66PCh. 5 - Prob. 67PCh. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Prob. 71PCh. 5 - Prob. 72PCh. 5 - A rock of mass m is tied to a string of length L...Ch. 5 - Prob. 74PCh. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77P
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- Let gM represent the difference in the gravitational fields produced by the Moon at the points on the Earths surface nearest to and farthest from the Moon. Find the fraction gM/g, where g is the Earths gravitational field. (This difference is responsible for the occurrence of the lunar tides on the Earth.)arrow_forwardModel the Moons orbit around the Earth as an ellipse with the Earth at one focus. The Moons farthest distance (apogee) from the center of the Earth is rA = 4.05 108 m, and its closest distance (perigee) is rP = 3.63 108 m. a. Calculate the semimajor axis of the Moons orbit. b. How far is the Earth from the center of the Moons elliptical orbit? c. Use a scale such as 1 cm 108 m to sketch the EarthMoon system at apogee and at perigee and the Moons orbit. (The semiminor axis of the Moons orbit is roughly b = 3.84 108 m.)arrow_forwardIn Example 2.6, we considered a simple model for a rocket launched from the surface of the Earth. A better expression for the rockets position measured from the center of the Earth is given by y(t)=(R3/2+3g2Rt)2/3j where R is the radius of the Earth (6.38 106 m) and g is the constant acceleration of an object in free fall near the Earths surface (9.81 m/s2). a. Derive expressions for vy(t) and ay(t). b. Plot y(t), vy(t), and ay(t). (A spreadsheet program would be helpful.) c. When will the rocket be at y=4R? d. What are vy and ay when y=4R?arrow_forward
- What is the average speed in mi/h of a person at the equator as a result of the Earths rotation? (Take the radius of the Earth to be RE = 4000 mi.)arrow_forwardWhich of the following is impossible for a car moving in a circular path? Assume that the car is never at rest. (a) The car has tangential acceleration but no centripetal acceleration. (b) The car has centripetal acceleration but no tangential acceleration. (c) The car has both centripetal acceleration and tangential acceleration.arrow_forwardTwo planets in circular orbits around a star have speed of v and 2v . (a) What is the ratio of the orbital radii of the planets? (b) What is the ratio of their periods?arrow_forward
- A satellite is orbiting around a planet in a circular orbit. The radius of the orbit, measured from the center of the planet is R = 1.8 × 107 m. The mass of the planet is M = 4.8 × 1024 kg. a)Express the magnitude of the gravitational force F in terms of M, R, the gravitational constant G, and the mass m of the satellite. b)Express the magnitude of the centripetal acceleration ac of the satellite in terms of the speed of the satellite v, and R. c) Express the speed v in terms of G, M and R.arrow_forwardAstronomers discover an exoplanet, a planet orbiting a star other than the Sun, that has an orbital period of 3.17 Earth years in a circular orbit around its star, which has a measured mass of 3.63×1030 kg. Find the radius r of the exoplanet's orbit.arrow_forwardA planet has a mass of 5.98 x 10²4 kg. It has an average orbital speed of 2.978 x 104 m/s as it completes a circular orbit. It takes 3.154 x 107 s to make one revolution. What is the average radius of the planet's orbit around the star?arrow_forward
- You are on the surface of a planet with no atmosphere. This planet has mass 9.8 x 1023 kg and radius 1.3 x 105 m. You throw a ball (mass irrelevant) straight upward with a velocity of 12.8 x 103 m/s. At the moment when the speed is now 4.1 x 103 m/s, what is the elevation of the ball above the surface, in units of 105 m. Use G = 6.7 x 10-11 N m2/kg2 (Please answer to the fourth decimal place - i.e 14.3225)arrow_forwardCommunications satellites are placed in a circular orbit where they stay directly over a fixed point on the equator as the earth rotates. These are called geosynchronous orbits. The altitude of a geosynchronous orbit is 3.58×107m(≈22,000miles)3.58×107m(≈22,000miles). What is the period of a satellite in a geosynchronous orbit? Express your answer to three significant figures and include the appropriate units. Find the value of gg at this altitude. Express your answer to three significant figures and include the appropriate units. What is the weight of a 2000 kg satellite in a geosynchronous orbit? Express your answer as an integer and include the appropriate units.arrow_forwardA satellite is in a circular orbit about the earth (ME = 5.98 x 1024 kg). The period of the satellite is 1.03 x 104 s. What is the speed at which the satellite travels?arrow_forward
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