Concept explainers
a.
Weight of a given mass on the surface of Mercury.
a.
Answer to Problem 53A
Weight on the surface of Mercury is 22.34 N.
Explanation of Solution
Given :
Mass is
Acceleration due to gravity on mercury is 0.38 times of gravity on earth.
Formula used:
The weight of the body is,
Where,
m is mass
g is acceleration due to gravity.
Calculation:
Acceleration due to gravity on earth is
It is given acceleration due to gravity on mercury is 0.38 times of gravity on earth.
Therefore, acceleration due to gravity on mercury is,
Weight on the surface of Mercury is,
Conclusion:
Therefore, weight on mercury is 22.34 N
b.
Weight of a given mass on the surface of Pluto.
b.
Answer to Problem 53A
Weight on the surface of Pluto is 2.09 N
Explanation of Solution
Given :
Mass is given
Acceleration due to gravity on Pluto is 0.08 times of gravity on Mercury.
Formula used :
The weight of the body is.
Where, m is mass and g is acceleration due to gravity.
Calculation:
From previous subpart, acceleration due to gravity on Mercury is
Now,
It is given acceleration due to gravity on Pluto is 0.08 times of gravity on Mercury.
Therefore, acceleration due to gravity on Pluto is;
Weight is given by,
Here, m is mass and
Conclusion:
Therefore, weight on Pluto is 2.09 N
Chapter 4 Solutions
Glencoe Physics: Principles and Problems, Student Edition
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