An object is subject to two forces that do not point in opposite directions. Is it possible to choose their magnitudes so that the object is in equilibrium? Explain.
An object is subject to two forces that do not point in opposite directions. Is it possible to choose their magnitudes so that the object is in equilibrium? Explain.
An object is subject to two forces that do not point in opposite directions. Is it possible to choose their magnitudes so that the object is in equilibrium? Explain.
Expert Solution & Answer
To determine
To find: Whether the object is in equilibrium or not.
Answer to Problem 1CQ
The object is not in equilibrium.
Explanation of Solution
Given data:
An object is subjected to two forces that do not point in opposite directions. It is required to find whether the object is in equilibrium condition or not.
Formula used:
Write the expression for an equilibrium condition of the forces on the object as follows:
∑F=0 (1)
Here,
∑F is the sum of the forces acting on any object.
Explanation:
From Equation (1), if the sum of the forces acting on the object is zero, then the object will be in equilibrium condition.
If the two forces are equal in magnitude and opposite to each other, then the two forces cancel out and the net force becomes zero.
From the given data, the two forces are not in the opposite directions. Therefore, the two forces do not cancel each other out and the net force will be available on the object. Thus, the object is not in the equilibrium condition.
Conclusion:
Thus, the object is not in equilibrium.
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A painter with 80 weight is on a 4 meters long platform. Platform has negligible weight. The painter is balanced by two cables. One is at the left end and the other one is 3.2 meters away from the first cable.
a)What is the tension on the left cable and the right cable when the painter is in the middle of the platform
b)Would the painter be able to move the right end of the platform without loosing balance. Calculate the tensions on the cables for that case and show that it leads to a negative tension.
A person stands on the ball of one foot. The normal force due to the ground pushing
up on the ball of the foot has magnitude 750 N. Ignore the weight of the foot itself.
The other significant forces acting on the foot are the tension in the Achilles tendon
pulling up and the force of the tibia pushing down on the ankle joint.
Gastrocnemius-
soleus muscles
FAchilles
Achilles tendon-
Calcaneus
(heel bone)
Tibia
N
Tibia
AN
If the tension in the Achilles tendon is 2234 N, what is the force exerted on the foot
by the tibia? If the force is upward, enter a positive value. If the force is downward,
enter a negative value.
Box m₁ = 2.4 kg remains stacked on box m₂ = 15.9 kg as they are pulled from rest
across a smooth, horizontal floor by a constant horizontal force of magnitude P =
24.4 N, as in the figure. What is the magnitude Fnet of the net force on the upper
box?
net
m1
m2
=
P
N
Chapter 5 Solutions
College Physics: A Strategic Approach (3rd Edition)
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