Chapter 4.2, Problem 26SSC

To determine

The resulting acceleration of T.

Answer to Problem 26SSC

  $0.14{\text{m/s}}^{\text{2}}$

Explanation of Solution

Given:

Mass of the T, $m=65.\text{0 kg}$ .

Applied force, $F=9.0\text{N}$

Formula used:

From Newton’s Second law of motion:

  $F_{net}=ma$

Where, a is the acceleration, m is the mass and $F_{net}$ is the net force.

Calculation:

Using the given values of mass and force in above formula of Newton’s second law, the resulting acceleration can be calculated as,

  $\begin{array}{c}a=\frac{F_{net}}{m}\\ =\frac{9.0}{65}\\ =0.14{\text{m/s}}^{\text{2}}\end{array}$

Conclusion:

Thus, T’s resulting acceleration is $0.14{\text{m/s}}^{\text{2}}$ .