Organic Chemistry: Principles and Mechanisms (Second Edition)
2nd Edition
ISBN: 9780393663556
Author: Joel Karty
Publisher: W. W. Norton & Company
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Chapter 4, Problem 4.67P
Interpretation Introduction
Interpretation:
The more stable chair conformation of
Concept introduction:
For substituted cyclohexane, the isomer having substituents at equatorial position is most stable. Preferably, the bulkier groups are more stable at equatorial position than axial due to reduced
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The two structures shown are examples of monosaccharide units with multiple chiral centers. The two structures are
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Chapter 4 Solutions
Organic Chemistry: Principles and Mechanisms (Second Edition)
Ch. 4 - Prob. 4.1PCh. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Prob. 4.4PCh. 4 - Prob. 4.5PCh. 4 - Prob. 4.6PCh. 4 - Prob. 4.7PCh. 4 - Prob. 4.8PCh. 4 - Prob. 4.9PCh. 4 - Prob. 4.10P
Ch. 4 - Prob. 4.11PCh. 4 - Prob. 4.12PCh. 4 - Prob. 4.13PCh. 4 - Prob. 4.14PCh. 4 - Prob. 4.15PCh. 4 - Prob. 4.16PCh. 4 - Prob. 4.17PCh. 4 - Prob. 4.18PCh. 4 - Prob. 4.19PCh. 4 - Prob. 4.20PCh. 4 - Prob. 4.21PCh. 4 - Prob. 4.22PCh. 4 - Prob. 4.23PCh. 4 - Prob. 4.24PCh. 4 - Prob. 4.25PCh. 4 - Prob. 4.26PCh. 4 - Prob. 4.27PCh. 4 - Prob. 4.28PCh. 4 - Prob. 4.29PCh. 4 - Prob. 4.30PCh. 4 - Prob. 4.31PCh. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - Prob. 4.34PCh. 4 - Prob. 4.35PCh. 4 - Prob. 4.36PCh. 4 - Prob. 4.37PCh. 4 - Prob. 4.38PCh. 4 - Prob. 4.39PCh. 4 - Prob. 4.40PCh. 4 - Prob. 4.41PCh. 4 - Prob. 4.42PCh. 4 - Prob. 4.43PCh. 4 - Prob. 4.44PCh. 4 - Prob. 4.45PCh. 4 - Prob. 4.46PCh. 4 - Prob. 4.47PCh. 4 - Prob. 4.48PCh. 4 - Prob. 4.49PCh. 4 - Prob. 4.50PCh. 4 - Prob. 4.51PCh. 4 - Prob. 4.52PCh. 4 - Prob. 4.53PCh. 4 - Prob. 4.54PCh. 4 - Prob. 4.55PCh. 4 - Prob. 4.56PCh. 4 - Prob. 4.57PCh. 4 - Prob. 4.58PCh. 4 - Prob. 4.59PCh. 4 - Prob. 4.60PCh. 4 - Prob. 4.61PCh. 4 - Prob. 4.62PCh. 4 - Prob. 4.63PCh. 4 - Prob. 4.64PCh. 4 - Prob. 4.65PCh. 4 - Prob. 4.66PCh. 4 - Prob. 4.67PCh. 4 - Prob. 4.68PCh. 4 - Prob. 4.69PCh. 4 - Prob. 4.70PCh. 4 - Prob. 4.71PCh. 4 - Prob. 4.72PCh. 4 - Prob. 4.73PCh. 4 - Prob. 4.1YTCh. 4 - Prob. 4.2YTCh. 4 - Prob. 4.3YTCh. 4 - Prob. 4.4YTCh. 4 - Prob. 4.5YTCh. 4 - Prob. 4.6YTCh. 4 - Prob. 4.7YTCh. 4 - Prob. 4.8YTCh. 4 - Prob. 4.9YTCh. 4 - Prob. 4.10YTCh. 4 - Prob. 4.11YTCh. 4 - Prob. 4.12YTCh. 4 - Prob. 4.13YTCh. 4 - Prob. 4.14YTCh. 4 - Prob. 4.15YTCh. 4 - Prob. 4.16YTCh. 4 - Prob. 4.17YTCh. 4 - Prob. 4.18YTCh. 4 - Prob. 4.19YTCh. 4 - Prob. 4.20YTCh. 4 - Prob. 4.21YTCh. 4 - Prob. 4.22YTCh. 4 - Prob. 4.23YTCh. 4 - Prob. 4.24YTCh. 4 - Prob. 4.25YT
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- Why are carbon atoms 1 and 3 of glyceraldehyde not considered chiral?arrow_forwardAnswer all the subparts pertaining to question 4arrow_forwardGlucose is the most abundant monosaccharide. In energy metabolism it is the most important source of energy for most organisms. Most carbohydrates have several chiral centers. How many chiral centers are present in the straight chain form of glucose? H- ОН НО H- ОН ОН CH,OHarrow_forward
- Kk.327.arrow_forwardPlease refer to the monosaccharides below when answering questions (a) – (). CHO CHO СНО СНО CHO НО H- HO Но- HO H- ОН но- H- ОН Но- H HO Но- H ОН Но H- H- ОН НО H- Но- H- ОН Но но- H- HO H- H- HO- CH2OH CH2OH ČH2OH CH2OH CH2OH I II III IV V (a) Draw the monosaccharide that results when III is treated with Br2/H2O. (b) Draw the monosaccharide that results when III is treated with 1. NaBH4/ 2. H2O. (c) Draw the monosaccharide that results when II is treated with the following reagents: 1. Br,/H20 2. Ca(ОН)2 3. H2O2/Fe3+arrow_forwardCharrow_forward
- 2. please what is the name of the monosaccharide Aarrow_forwardThe structure of DNA is based on a sugar, deoxyribose, shown below: OH НО Но 2-deoxyribose The cyclic form of deoxyribose contains • stereocentres. The open-chain form of deoxyribose has : stereocentres.arrow_forwardLactose is a disaccharide in which a glycosidic linkage connects the monosaccharides galactose and glucose. OH НО OH (a) Identify the glycosidic linkage and the acetal carbon in lactose. (b) What type of glycosidic linkage does lactose have (i.e., is it 1,1'-, 1,2'-, etc., and is it a or B)? (c) People who are lactose intolerant are deficient in the enzyme lactase, and therefore cannot efficiently break down the disaccharide into its monosaccharides. When lactose is treated with aqueous acid, however, this hydrolysis can take place, though relatively slowly. Draw the complete, detailed mechanism and the products of the acid-catalyzed hydrolysis of lactose. Но ОН НО ОН ОН Lactosearrow_forward
- Chair conformation of glucose, galactose , and fructosearrow_forwardPlease don't provide handwriting solutionarrow_forward1- Starch is a saccharide. a) reducing b) branched chain c) B-glucose straight chain d) oligo 2- The branching in the linkage between a) amylose; C1-C4 b) amylose; C1-C6 c) amylopectin; Ci-C4 d) amylopectin; C1-C6 3- The general formula of polysaccharides is: (A) (C6H10O5)n (B) (C6H12O5)n (C) (C6H10O6)n (D) (C6H10O6)n 4-The Ribose structure of fructose is obtained by the interaction of groups at component of starch occurs by the glycosidic carbons. which carbon atoms? a) C1 and C5 b) C1 and C6 c) C1 and C4 d) C2 and C5 5-. Lactose does not form homo disaccharides? a) True b) False 6- Which of the following glycosidic linkage found in maltose? a) Glucose (a-1 – 2B) Fructose b) Glucose (a1– 4) Glucose c) Galactose (B1– 4) Glucose d) Glucose (B1 – 4) Glucosearrow_forward
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