Universe
11th Edition
ISBN: 9781319039448
Author: Robert Geller, Roger Freedman, William J. Kaufmann
Publisher: W. H. Freeman
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 4, Problem 3Q
(a)
To determine
The direction of motion of the planet relative to the horizon over the course of one night.
(b)
To determine
The interpretation that can be drawn for speed at which planets moves on the celestial sphere when the planets move westwards whether the planets is in direct or retrograde motion.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
According to Lunar Laser Ranging experiment the average distance LM from the Earth to the Moon is approximately 3.92 x 105 km. The Moon orbits the
Earth and completes one revolution relative to the stars in approximately 27.5 days (a sidereal month).
Calculate the orbital velocity of the Moon in m/s.
Answer:
Choose...
(to two decimal places): (what is ‘h’?)
Eccentricity of earth orbit is 0.0167
µ(sun) = 1.32712E+11 km^3/s^
semimajor axis of Earth orbit = 1.49598E+08
need to figure out what ‘h’ is.
a) Calculate the speed of the earth around the sun at aphelion? (29.29 KM/S)
b) At perihelion? (30.29 KM/S)
On the evening of an autumnal equinox day Siddhant noticed that Mars was
exactly along the north-south meridian in his sky at the exact moment when the sun was
setting. In other words, the Sun and Mars subtended an angle of exactly 90° as measured
from the Earth. If the orbital radius of Mars is 1.52 au, What will be the approximate rise
time of the mars on the next autumnal equinox day?
Chapter 4 Solutions
Universe
Ch. 4 - Prob. 1CCCh. 4 - Prob. 2CCCh. 4 - Prob. 3CCCh. 4 - Prob. 4CCCh. 4 - Prob. 5CCCh. 4 - Prob. 6CCCh. 4 - Prob. 7CCCh. 4 - Prob. 8CCCh. 4 - Prob. 9CCCh. 4 - Prob. 10CC
Ch. 4 - Prob. 11CCCh. 4 - Prob. 12CCCh. 4 - Prob. 13CCCh. 4 - Prob. 14CCCh. 4 - Prob. 15CCCh. 4 - Prob. 16CCCh. 4 - Prob. 17CCCh. 4 - Prob. 18CCCh. 4 - Prob. 19CCCh. 4 - Prob. 20CCCh. 4 - Prob. 21CCCh. 4 - Prob. 22CCCh. 4 - Prob. 23CCCh. 4 - Prob. 24CCCh. 4 - Prob. 1CLCCh. 4 - Prob. 2CLCCh. 4 - Prob. 1QCh. 4 - Prob. 2QCh. 4 - Prob. 3QCh. 4 - Prob. 4QCh. 4 - Prob. 5QCh. 4 - Prob. 6QCh. 4 - Prob. 7QCh. 4 - Prob. 8QCh. 4 - Prob. 9QCh. 4 - Prob. 10QCh. 4 - Prob. 11QCh. 4 - Prob. 12QCh. 4 - Prob. 13QCh. 4 - Prob. 14QCh. 4 - Prob. 15QCh. 4 - Prob. 16QCh. 4 - Prob. 17QCh. 4 - Prob. 18QCh. 4 - Prob. 19QCh. 4 - Prob. 20QCh. 4 - Prob. 21QCh. 4 - Prob. 22QCh. 4 - Prob. 23QCh. 4 - Prob. 24QCh. 4 - Prob. 25QCh. 4 - Prob. 26QCh. 4 - Prob. 27QCh. 4 - Prob. 28QCh. 4 - Prob. 29QCh. 4 - Prob. 30QCh. 4 - Prob. 31QCh. 4 - Prob. 32QCh. 4 - Prob. 33QCh. 4 - Prob. 34QCh. 4 - Prob. 35QCh. 4 - Prob. 36QCh. 4 - Prob. 37QCh. 4 - Prob. 38QCh. 4 - Prob. 39QCh. 4 - Prob. 40QCh. 4 - Prob. 41QCh. 4 - Prob. 42QCh. 4 - Prob. 43QCh. 4 - Prob. 44QCh. 4 - Prob. 45QCh. 4 - Prob. 46QCh. 4 - Prob. 47QCh. 4 - Prob. 48QCh. 4 - Prob. 49QCh. 4 - Prob. 50QCh. 4 - Prob. 51QCh. 4 - Prob. 52QCh. 4 - Prob. 53QCh. 4 - Prob. 54QCh. 4 - Prob. 55QCh. 4 - Prob. 56QCh. 4 - Prob. 57QCh. 4 - Prob. 58Q
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- (a) Jupiter's third-largest natural satellite, Io, follows an orbit with a semimajor axis of 422,000 km (4.22 ✕ 105 km) and a period of 1.77 Earth days (PIo = 1.77 d). To use Kepler's Third Law, we first must convert Io's orbital semimajor axis to astronomical units. One AU equals 150 million km (1 AU = 1.50 ✕ 108 km). Convert Io's a value to AU and record the result. aIo = AU (b) One Earth year is about 365 days. Convert Io's orbital period to Earth years and record the result. PIo = yr (c) Use the Kepler's Third Law Calculator to calculate Jupiter's mass in solar units. Record the result. MJup(Io) = MSun (d) Based on this result, Jupiter's mass is about that of the Sun. Jupiter has a similar fraction of the Sun's volume. The two objects therefore have rather similar density! In fact, Jupiter has a fairly similar composition as well: most of its mass is in the form of hydrogen and helium.arrow_forwardA mini satellite weighing 50 kg is going to be launched into an orbit around earth by arocket. One sidereal day (period of earth’s self-orbit) is 23 hours, 56 minutes and 4.1seconds. (a) The rocket is to be launched from a platform in the Mongolian Plateau with a heightof 3.5 km above earth surface. Calculate the acceleration due to earth’s gravity atthis elevation.(b) The satellite shall complete 10 orbits in precisely 1 sidereal day. Calculate theorbital height and orbital velocity of the satellite.(c) Once the satellite is in this orbit, what is the acceleration due to earth’s gravityexperienced by the satellite?(d) Referring to your answer in part (c), explain why the satellite does not fall towardsearth as a result of earth’s gravitational pull?(e) Calculate the total energy of the satellite in orbit, using infinity as frame ofreference.(f) Calculate the escape velocity to leave earth’s gravitational well.arrow_forwardTwo exoplanets, UCF1.01 and UCF1.02 are found revolving around the same star. The period of planet UCF1.01 is 92.4 days, and that of planet UCF1.02 is 7.1 days. If the average distance of UCF1.01 to the sun is 5,828.0 km, what is the average distance of UCF1.02 to the sun in km? Please keep four digits after decimal points.arrow_forward
- Using the m, = 1.99 x 1030 kg and the mę = 5.98 x 1024 kg and the distance between them as 1.00 AU (astronomical unit), what would be the orbital period of an object orbiting the sun at a distance of 2.12 AU? (please give answer in years) Number Unitsarrow_forwardA new planet is discovered orbiting a distant star. Observations have confirmed that the planet has a circular orbit with a radius of 12 AU and takes 117 days to orbit the star. Determine the mass of the star. State your answer with appropriate mks units. [NOTE: AU ..stands.for...astronomical unit". It is the average distance between Earth & the Sun. 1 AU≈ 1.496 x 1011 m.] Enter a number with units. I be quite large and your calculator will display the answer as a power of 10. If, as an example, your answer was 8.54 x 1056, you would type "8.54e56" into the answer box (remember to state your units with your answer).]arrow_forwardAssume that the planet's orbit is circular of radius R = 130 × 106 km and planet's period is T = 30 × 10° s. What is the magnitude of the vector J = r x r' (in units of square kilometers per second)? (Use decimal notation. Give your answer to three decimal places.) ||J|| = x10° km²/s Find the rate at which the planet's radial vector sweeps out area in units of square kilometers per second. (Use decimal notation. Give your answer to three decimal places.) dA x10° km²/s dtarrow_forward
- The Halley’s Comet regularly passes by the earth on its tour around the sun (at the time of Jesus’ birth itwas something different, most probably). The semi-major axis of the elliptical path is 17.8 AU(astronomical unit = 150·109 m). Halley’s last visit at our earth was in 1985. Are you going to experience the next visit?arrow_forwardSam is an astronomer on planet Hua, which orbits the distant star Barnard. It has recently been accepted that Hua is spherical in shape, although its exact size is unknown. While studying in the library, in the city of Joy, Sam learns that during equinox, Barnard is directly overhead in the city of Bar, located 1500.0 km north of his location. On the equinox, Sam goes outside and measures the altitude of Barnard at 83 degrees. What is the radius of Hua in km?arrow_forwardA)At what altitude would a geostationary sattelite need to be above the surface of Mars? Assume the mass of Mars is 6.39 x 1023 kg, the length of a martian solar day is 24 hours 39minutes 35seconds, the length of the sidereal day is 24hours 37minutes 22seconds, and the equatorial radius is 3396 km. The answer can be calculated using Newton's verison of Kepler's third law.arrow_forward
- As an aspiring science fiction author, you are writing about a space-faring race and their home planet, Krypton, which has one moon. This moon takes 1,702,948 seconds to complete an orbit around Krypton. If the distance from the center of the moon to the surface of Krypton is 462.5 x 106 m and the planet has a radius of 37.2 x 106 m, calculate the moon's centripetal acceleration. Your Answer: Answerarrow_forwardThe earth revolves around the sun in exactly 365 1/4 days which is equivalent to 1 year. To make up for the loss of 1/4 day, the calendar was adjusted so that we have a leap year for every 4 years. If the earth were to speed in its motion slightly so that a year would be completed in exactly 365 days and 6 hours, how often would we need to have a leap year?arrow_forwardIn a distant star system there are many inhabitable planets. One of these planets is named Qomar. Qomar is 3.2 AU's from its star and takes 6.5 Earth years to go around its star once. There is another planet in the same star system called Ferenginar. Ferenginar is 0.9 AUs from the star. What is the length of a Ferengi year (on Ferenginar) in terms of Earth years?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Stars and GalaxiesPhysicsISBN:9781305120785Author:Michael A. Seeds, Dana BackmanPublisher:Cengage Learning
An Introduction to Physical SciencePhysicsISBN:9781305079137Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar TorresPublisher:Cengage Learning
Stars and Galaxies
Physics
ISBN:9781305120785
Author:Michael A. Seeds, Dana Backman
Publisher:Cengage Learning
An Introduction to Physical Science
Physics
ISBN:9781305079137
Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher:Cengage Learning
Time Dilation - Einstein's Theory Of Relativity Explained!; Author: Science ABC;https://www.youtube.com/watch?v=yuD34tEpRFw;License: Standard YouTube License, CC-BY