Universe
11th Edition
ISBN: 9781319039448
Author: Robert Geller, Roger Freedman, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 4, Problem 22Q
To determine
The area that is swept out during 2011 and then over a period of five years, when the line joining the Sun and an asteroid is found to sweep out an area of
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0.99
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0.97
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-0.02
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Title
If you observed the solar system from the nearest star (distance 1.3 parsecs), what would the...
Description
If you observed the solar system from the nearest star (distance 1.3 parsecs), what would the maximum
angular separation be between Earth and the sun? Note that 1 pc is 2.1 105 AU. (Hint: Use the small-angle
formula, Chapter 3.)
Chapter 4 Solutions
Universe
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- If you observed the Solar System from the vantage point of the nearest star, at a distance of 1.3 pc, what would the maximum angular separation be between Earth and the Sun? (Hint: Use the small-angle formula, Eq. 3-1.) (Note: 1 pc = 2.1 105 AU.)arrow_forwardConsidering that Earth experiences an average intensity of sunlight of 1330 W/m? and is at a distance from the Sun of 1.0 AU = 150 million km, and considering that that the apparent magnitude of the Sun as seen from Earth is m = -26.7, (a) then how far from the Sun would a distant Kuiper- belt world need to be in order for the apparent magnitude of the Sun to be m = -11.0 as seen on that world? Give your answer in AU. (b) What would be the orbital period of this world? Give your answer in Earth years.arrow_forwardAccording to the solar nebula theory, why is there a common direction of revolution and rotation for most objects in the Solar System?arrow_forward
- Explain the tidal hypothesis.arrow_forward1. These images were taken six months apart, first when Earth was as far to one side of Alpha Centauri as it can get and again when Earth was as far to the other side of Alpha Centauri as it can get. Consequently, the baseline between the two observing positions is how many AU across? Answer: 1.7 arcsec 2. First, convert this to kilometers using your measurement of how many kilometers are in an AU. 3. Now convert the baseline to kilometers using the true value for the number of kilometers in an AU. 4. Calculate the distance to Alpha Centauri using parallax and the true baseline in kilometers. 5. Google and record the true value. 6. Calculate your percent error 7. Discuss significant sources of errorarrow_forward4) Science fiction movies often portray asteroid belts as crowded, dense regions that require spaceships to maneuver quickly to get through them. In this problem, we will calculate the fraction of volume in an asteroid belt that is actually occupied by asteroids. a) If there are 300,000 large asteroids between 2 and 3 AU from the Sun, and each asteroid is assumed to be spherical with a radius of 100 km, determine the total volume occupied by asteroids in this region. Recall that the volume of a sphere is given by the equation V = 4TR³ /3. b) Let's assume the region in which these asteroids orbit is an annulus with an inner radius of 2 AU, an outer radius of 3 AU, and a thickness of 2Ro. Determine the volume of this region. Recall that the area of a circle is given by the equation A = TR². Here are two conversions that you'll need: 1 AU = 1.496 × 108 km and 1 Ro = 6.955 × 105 km. c) What is the ratio of the volume occupied by asteroids to the volume of the asteroid belt (i.e., the…arrow_forward
- 9) An interstellar cloud fragment 0.2 light-year in diameter is rotating at a rate of one revolution per million years. It now begins to collapse. Assuming that the mass remains constant, estimate the cloud's rotation period when it has shrunk to (a) the size of the solar nebula, 100 AU across, and (b) the size of Earth's orbit, 2 AU across. (answers: 0.016 revolutions per year, and an orbital period of 62.5 years, This is 40 revolutions per year, and an orbital period of 0.025 years, or just a little over 9 days)arrow_forwardA planet has a volume of 6.7*10^(13)km^(3). One of its moons has a volume of 9.3*10^(10)km^(3). Which of the following most closely approximates how many orders of magnitude more volume the planet has?arrow_forwardOur solar system is approximately 10 billion km across. This diameter can be also be expressed as: 10 x 10⁹ km 1010 km 1013 m All of the above. Both a and b are correctarrow_forward
- Thinking about the Scale of the Solar System As we discussed, the radius of the Earth is approximately 6370 km. The Sun, on the other hand, is approximately 700,000 km in radius and located, on average, one astronomical unit (1 au=1.5x108 km) from the Earth. Imagine that you stand near Mansueto Library, at the corner of 57th and Ellis. You hold a standard desk globe, which has a diameter of 12 inches, and you want to build a model of the Sun, Earth, and their separation that keeps all sizes and lengths in proportion to one another. a) How big would the Sun be in this scale model? Give your answer in feet and meters. b) The nearest star to the Solar System outside of the Sun is Proxima Centauri, which is approximately 4.2 light years away (a light year is the distance light travels in one year, or approximately 9.5x1012 km). Given the scale model outlined above, how far would a model Proxima Centauri be placed from you? Give your answer in miles and km.arrow_forwardWhat Is KMT And What Are Its Assumptions?arrow_forwardVenus can be as bright as apparent magnitude -4.7 when at a distance of about 1AU. How many times fainter would Venus look from a distance of 7pc? Assume Venus has the same illumination phase from your new vantage point. (Hint: Recall the inverse square law; also, review the definition of apparent visual magnitudes. Note: 1 pc = 2.1 x 10^5 AU _______ times fainter what would it's apparently magnitude be? _______arrow_forward
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