Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Question
Chapter 4, Problem 24QLP
To determine
How does the shape of graphite in cast iron affect its properties?
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Check out a sample textbook solutionStudents have asked these similar questions
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Is this a austenite microstructure if so how can you tell
Continuous Cooling Transformation (CCT) Diagram for Steel
1. If a sample of austenite is cooled from 760°C to room temperature at a rate of 85°C/s (midway
between the red and blue dotted lines), estimate the following values:
a) How much time would it take for pearlite to begin forming and at what temperature would this
occur?
b) How much time would it take for martensite to begin forming and at what temperature would
this occur?
Temperature (°C)
800
Eutectoid temperature
1400
700
Pearlite
600
500
400
300
Critical
cooling
rate
200
140°C/s
Austenite
35°C/s
1200
1000
800
600
M (start)
400
100
Martensite
Martensite I
+ ++
Pearlite
200
Pearlite
0
10-1
1
10
102
103
104
105
Time (s)
Temperature (°F)
Chapter 4 Solutions
Manufacturing Engineering & Technology
Ch. 4 - Describe the difference between a solute and a...Ch. 4 - What is a solid solution?Ch. 4 - Prob. 3RQCh. 4 - Describe the difference between a single-phase and...Ch. 4 - What is an induction heater? What kind of part...Ch. 4 - Describe the major features of a phase diagram.Ch. 4 - What do the terms equilibrium and constitutional,...Ch. 4 - Prob. 8RQCh. 4 - What is tempering? Why is it performed?Ch. 4 - Explain what is meant by severity of quenching.
Ch. 4 - What are precipitates? Why are they significant in...Ch. 4 - Prob. 12RQCh. 4 - Prob. 13RQCh. 4 - Prob. 14RQCh. 4 - Prob. 15RQCh. 4 - You may have seen some technical literature on...Ch. 4 - Prob. 17QLPCh. 4 - What is the difference between hardness and...Ch. 4 - Prob. 19QLPCh. 4 - Prob. 20QLPCh. 4 - Prob. 21QLPCh. 4 - Describe the characteristics of (a) an alloy, (b)...Ch. 4 - Explain why carbon, among all elements, is so...Ch. 4 - Prob. 24QLPCh. 4 - In Section 4.8.2, several fluids are listed in...Ch. 4 - Why is it important to know the characteristics of...Ch. 4 - Explain why, in the abscissa of Fig. 4.16c, the...Ch. 4 - Prob. 28QLPCh. 4 - Prob. 29QLPCh. 4 - Prob. 30QLPCh. 4 - Design a heat-treating cycle for carbon steel,...Ch. 4 - Using Fig. 4.4, estimate the following quantities...Ch. 4 - Prob. 33QTPCh. 4 - Prob. 34QTPCh. 4 - Prob. 35SDPCh. 4 - Figure 4.18b shows hardness distributions in...Ch. 4 - Throughout this chapter, you have seen specific...Ch. 4 - Refer to Fig. 4.24, and think of a variety of...Ch. 4 - Inspect various parts in your car or home, and...
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Similar questions
- (all of the above is not correct) also could you please provide an explanation to this problem? Thanksarrow_forwardBelow is a continuous cooling transformation curve for steel (upper) and for a silicate melt (lower). Describe the similarities and differences as follows. a. What is the critical cooling rate in each case? b. What phase(s) form in each case when the critical cooling rate is exceeded? c. What phase(s) form in each case if the cooling rate is very slow? 800 1400 Ae lemperature Austenite *peorlite begins 10FI 700 1200 Austenitepearlite complete 1600 1000 5009 800 Tronsformation stops 400 600 300 400 Austenite -mortenstic structure 200 -Isathermal dogram Continuous transformaton diogrom Constant rate coding curves - 100 200 Findl structure Mortensite Morlensite i peorlile Peorite (softer, coorser- 0.1 10? 10 Tronsformation time, seconds Continuous Cooling-Transformation (C-T)Diagram (Derived from the isothermal-transformation diagram for a plain-carbon eutectoid steel) 1200 Glass Crystallization begins 1100 1000 Critical cooling rate Glass-ceramic 900 Crystallization ends 800 700 102 10…arrow_forwardMaterials Science Engineering; CCT Diagramarrow_forward
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